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Discover PHYSICS for GCE ‘O’ Level Science

Discover PHYSICS for GCE ‘O’ Level Science. Unit 2: Kinematics. 2.1 Distance, Time and Speed. In this section, you’ll be able to: state what speed is calculate average speed plot and interpret a distance-time graph. distance. moved. Speed. =. taken. time. d. t. What is Speed?.

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Discover PHYSICS for GCE ‘O’ Level Science

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  1. Discover PHYSICS for GCE ‘O’ Level Science Unit 2: Kinematics

  2. 2.1 Distance, Time and Speed In this section, you’ll be able to: • state what speed is • calculate average speed • plot and interpret a distance-time graph

  3. distance moved Speed = taken time d t What is Speed? 2.1 Distance, Time and Speed Speed is the distance moved per unit time i.e. In symbols, v = where d = distance moved (m) t = time taken (s) v = speed (m s-1)

  4. d t d v The ‘Triangle’ Method 2.1 Distance, Time and Speed To find the value of a quantity, cover up the symbol to give the related formula: • d = v t • v = • t =

  5. 2.1 Distance, Time and Speed What is Average Speed? Can you calculate the speed of each athlete in the table below? Speed/m s–1 Location, year Athlete Event Time Atlanta, 1996 Bailey, Canada 100 m 9.84 s 10.2 Atlanta, 1996 Johnson, USA 200 m 19.32 s 10.4 Atlanta, 1996 Johnson, USA 400 m 43.49 s 9.2 Atlanta, 1996 Rodal, Norway 800 m 1:42.59 min 7.8

  6. What is Average Speed? 2.1 Distance, Time and Speed • The speed that you have calculated for each athlete is actually the average speed. • Each athlete did not run at the same speed throughout the race. • In short, average speed assumes that the object travels at the same speed throughout the entire distance.

  7. 1 m 1 km 60 s 60 min 3.6 km - 1 3.6 km h = =    1 s 1000 m 1 min 1 h 1 h What is 1 m s-1 in km h-1? 2.1 Distance, Time and Speed 1 m s-1 means that the object moves 1 m in 1 s. In 1 h, there are 60 × 60 = 3600 s. Hence, the distance travelled in 3600 s is 3600 m = 3.6 km. Therefore, 1 m s-1 = 3.6 km h-1. Or you can use conversion of units as follows:

  8. 80 10 Distance-time graphs 2.1 Distance, Time and Speed For an object moving with constant or uniform speed, the distance-time graph is a straight line. What is the speed of this object? Distance/m 100 The total distance moved after 10 s is 80 m. Therefore, the speed is: v = = 8 m s-1 80 60 40 20 0 2 4 6 8 10 12 Time/s

  9. 80 20 10 20 Distance-time graphs for increasing speed 2.1 Distance, Time and Speed After 10 s, distance moved is 20 m. Average speed after 10 s is : v = = 2 m s–1 Distance/m 100 80 60 After 20 s, distance moved is 80 m. The average speed after 20 s is: v = = 4 m s–1 40 20 0 2 4 6 8 10 12 14 16 18 20 Time/s

  10. Distance/m 100 80 60 40 20 0 2 4 6 8 10 12 14 16 18 20 Time/s Distance-time graphs for decreasing speed 2.1 Distance, Time and Speed During the first 18 s, the speed of the object decreases. After 18 s, distance moved remains 100 m. There is no change in the distance from 10 s to 15 s. Therefore, the speed is zero. The object is stationary or at rest.

  11. s Distance/m 90 t 14 100 80 60 40 20 0 2 4 6 8 10 12 14 16 18 20 Time/s 2.1 Distance, Time and Speed Instantaneous Speed The instantaneous speed of an object is the speed at a particular instant. It can be found from the gradient of the tangent at a point on the distance-time graph. At t = 5 s, the instantaneous speed is v = = = 6.4 m s-1 s t

  12. s t Key Ideas 2.1 Distance, Time and Speed • Speed is the change in distance per unit time, v = Its SI unit is m s-1. • Average speed is the total distance travelled, divided by the total time taken. • A distance-time graph shows how distance changes with time. (a) If speed is uniform, the graph is a straight line. (b) If speed is non-uniform, the graph is a curve. • The gradient of the tangent at a point on the s-t graph gives the instantaneous speed.

  13. Test Yourself 2.1 2.1 Distance, Time and Speed At the start of a journey, the odometer (a meter which clocks the total distance of a car has travelled) has an initial reading of 50780 km. At the end of the journey, the odometer reading was 50924 km. The journey took two hours. What was the average speed of the journey in (a) km h-1 ? (b) m s-1 ? Speedometer Odometer

  14. change in velocity Time taken 2.2 Speed, Velocity and Acceleration In this section, you’ll be able to: • state what velocity and uniform acceleration are • calculate acceleration using • interpret given examples of non-uniform acceleration

  15. Speed and Velocity 2.2 Speed, Velocity and Acceleration Velocity is the change in distance in a specified direction (i.e. displacement) per unit time. It can be positive or negative. For example, when you perform a 200 m sprint, your distance is 200 m, whereas your displacement is generally less, as shown in the figure below. What would your speed and velocity be when you run the 200 metres in 25 seconds? Distance travelled 200 m Displacement 50 m

  16. Acceleration 2.2 Speed, Velocity and Acceleration Acceleration is the change in velocity with time. In symbols: a = (in m s-2) 3 seconds after take off, a shuttle has a speed of 45 m s-1. What is its acceleration?  v  t

  17. Key Ideas 2.2 Speed, Velocity and Acceleration • Velocity is the change in displacement per unit time. It is speed in a specified direction. Its SI unit is m s-1, which is the same for speed. • Acceleration is the change in velocity per unit time. Its SI unit is m s-2.

  18. Test Yourself: Inside Scoop 2.2 Speed, Velocity and Acceleration Ever heard of the Vertical Marathon? Since 1987, this race takes place annually at the tallest hotel in Southeast Asia: the 226 metres high Stamford hotel in Singapore. Balvinder Singh set the record in 1989 by climbing the 1336 steps in 6 minutes and 55 seconds. Calculate his velocity in steps and in kilometres per hour. Is his velocity positive or negative?

  19. 2.3 Speed-Time Graphs In this section, you’ll be able to: • plot and interpret speed-time graphs • determine the distance travelled by calculating the area under the speed-time graph

  20. Uniform acceleration 2.3 Speed-Time Graphs In a speed-time graph, a straight line denotes uniform acceleration. How can you achieve uniform acceleration when playing a racing game in an arcade? Answer: by stepping on the pedal all the way! On the next slide we can see the corresponding speed-time graph.

  21. Speed/m s-1 35 30 25 20 15 10 5 Time/s 0 0 2 4 6 8 10 12 13 14 Uniform acceleration 2.3 Speed-Time Graphs The gradient of the line is 2 m s-2 Or: a = (v–u)/t = (20 – 10)/(10 – 0) = 2 m s-2

  22. Non-uniform acceleration 2.3 Speed-Time Graphs In a speed-time graph, a curved line denotes non-uniform acceleration. How can you achieve non-uniform acceleration when playing a racing game in an arcade? Answer: by stepping on the pedal slowly to its maximum (increasing acceleration) or by slowly releasing the pedal from its maximum position (decreasing acceleration).

  23. Non-uniform acceleration 2.3 Speed-Time Graphs Speed/m s-1 30 20 10 0 1 2 3 4 5 6 7 8 9 10 11 12 Time/s The gradient of the speed-time graph is not constantduring the first 10 seconds i.e. acceleration is non-uniform.

  24. Types of acceleration 2.3 Speed-Time Graphs Can you tell the difference between the following types of acceleration? Can you sketch the v-t graphs and give an example of each type of acceleration? Positive accelerationNegative acceleration Retardation Deceleration Increasing acceleration Decreasing acceleration Increasing deceleration Decreasing deceleration

  25. Area under speed-time graph 2.3 Speed-Time Graphs Distance is normally given by speedtime. The area under a speed-time graph is also equal to speedtime. Hence, the area under a speed-time graph gives the distance travelled. The next slide shows you how to find the distance travelled by using the area under the speed-time graph.

  26. 2.3 Speed-Time Graphs Speed/m s-1 50 40 30 20 10 Time/s 0 1 2 3 4 5 6 7 8 9 10 11 12 From t = 7.5 to t = 12, Speed decreases uniformly, acceleration = (0 - 45)/(12 - 7.5) = -1 m s-2 Distance moved = area of green triangle = 0.5  45  (12 - 7.5) = 101.25 m Can you find the total distance moved (from t = 0 to t = 12)?

  27. 2.3 Speed-Time Graphs Key Ideas • A speed-time graph shows how speed changes with time. • The gradient of the tangent at a point on the speed-time graph gives the instantaneous acceleration. • The area under the speed-time graph is the total distance travelled.

  28. 2.3 Speed-Time Graphs Test Yourself 2.3 1. The figure below shows the speed-time graph of a car. Describe the motions of the car at regions A, B, C and D. 2. The figure below shows the distance-time graph of a car. Describe the motions of the car at regions A, B, C and D.

  29. 2.4 Acceleration of Free Fall In this section, you’ll be able to: • state that the acceleration of free fall near to Earth is approximately 10 m s-2 • describe motion of bodies in free fall with and without air resistance • understand what terminal velocity is

  30. Galileo Galilei, an Italian, was one of the first modern scientists to verify experimentally the acceleration due to free fall. Supposedly experimenting from the Leaning Tower of Pisa, he found out that this ‘falling’ acceleration was about 10 m s-2 and the same for all objects! Galileo’s Discovery 2.4 Acceleration of Free Fall

  31. Falling without air resistance 2.4 Acceleration of Free Fall Take a coin from your wallet and hold it in one hand. Hold your wallet in the other hand and stand on your chair. Drop both items from the same height at the same time. What happens? a) The light coin hits the ground first b) The heavy wallet hits the ground first c) Both hit the ground at the same time

  32. Key Ideas 2.4 Acceleration of Free Fall • All objects fall under gravity with constant acceleration, g, the acceleration of free fall (about 10 m s-2)

  33. Test Yourself 2.4 2.4 Acceleration of Free Fall A parachutist jumps from an aircraft and falls through the air. After some time the parachute opens. Describe the motion of the parachutist at points A, B, C and D. D 50 40 C 30 Speed/m s –1 20 B 10 A T 0 ime/s 2 4 6 8 10 12 14 16 18

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