1 / 15

Scientific Notation

Scientific Notation. 65,000 kg  6.5 × 10 4 kg. Converting into Sci. Notation: Move decimal until there’s 1 digit to its left. Places moved = exponent. Large # (>1)  positive exponent Small # (<1)  negative exponent. 7. 2,400,000 g 8. 0.00256 kg 9. 7  10 -5 km

gravely
Télécharger la présentation

Scientific Notation

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Scientific Notation 65,000 kg  6.5 × 104 kg • Converting into Sci. Notation: • Move decimal until there’s 1 digit to its left. Places moved = exponent. • Large # (>1)  positive exponentSmall # (<1)  negative exponent

  2. 7. 2,400,000 g 8. 0.00256 kg 9. 7  10-5 km 10. 6.2  104 mm Scientific Notation Practice Problems 2.4  106 g 2.56  10-3 kg 0.00007 km 62,000 mm

  3. EXE EXP EXP ENTER EE EE Scientific Notation • Calculating with Sci. Notation (5.44 × 107 g) ÷ (8.1 × 104 mol) = Type on your calculator: 5.44 7 8.1 4 ÷ = 671.6049383 = 670 g/mol = 6.7 × 102 g/mol

  4. Practice • 1) 5.21 x 104+ 6.7 x 103 = • 5.9 x 104 • 2) 9.55 x 1014 / 3.354 x 106 = • 2.85 x 108 • 3) 8.467 x 105 x 2.01 x 108 = • 1.70 x 1014 • 4) 7.668 x 107– 3.4 x 108 = • -2.63 x 108

  5. M V D = Density • Density = mass per unit volume • Units for density: g/cm3 or g/mL or g/L (solids) (liquids) (gas)

  6. Density • An object has a volume of 825 cm3 and a density of 13.6 g/cm3. Find its mass. GIVEN: V = 825 cm3 D = 13.6 g/cm3 M = ? WORK: M = DV M = (13.6 g/cm3)(825cm3) M = 11,200 g

  7. WORK: V = M D V = 25 g 0.87 g/mL Density • A liquid has a density of 0.87 g/mL. What volume is occupied by 25 g of the liquid? GIVEN: D = 0.87 g/mL V = ? M = 25 g V = 29 mL

  8. Dimensional Analysis • The “Factor-Label” Method • Units, or “labels” are canceled, or “factored” out

  9. Dimensional Analysis • Steps: 1. Identify starting & ending units. 2. Line up conversion factors so units cancel. 3. Multiply all top numbers & divide by each bottom number. 4. Check units & answer.

  10. cm in Dimensional Analysis 5) Your European hairdresser wants to cut your hair 8.0 cm shorter. How many inches will he be cutting off? 8.0 cm 1 in 2.54 cm = 3.1 in

  11. qt mL  Dimensional Analysis • How many milliliters are in 1.00 quart of milk? 1 L 1.06 qt 1000 mL 1 L 1.00 qt = 943 mL

  12. cm yd Dimensional Analysis 6) Taft football needs 550 cm for a 1st down. How many yards is this? 1 ft 12 in 1 yd 3 ft 1 in 2.54 cm 550 cm = 6.0 yd

  13. lb cm3 Dimensional Analysis • You have 1.5 pounds of gold. Find its volume in cm3 if the density of gold is 19.3 g/cm3. 1 cm3 19.3 g 1 kg 2.2 lb 1000 g 1 kg 1.5 lb = 35 cm3

  14. Dimensional Analysis • Convert 75.0 in3 to cm3 (2.54 cm)3 (1 in)3 75.0 in3 = 1230 cm3

  15. Dimensional Analysis 1 hr 1609 m 939 m/min 60 min 1 hr 1 mi • Convert 35.0 mi/hr to m/min • (1609 m = 1 mile) • 35.0mi =

More Related