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S.K.1. Memecahkan masalah yang berkaitan dengan Konsep Operasi Bilangan Real. K.D.2. Menerapkan Operasi pada Bilangan Berpangkat ( Exponent ) Tujuan Pembelajaran : Siswa dapat mengoperasikan bilangan berpangkat 2. Siswa dapat menyederhanakan
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S.K.1. Memecahkan masalah yang berkaitan dengan Konsep Operasi Bilangan Real • K.D.2. MenerapkanOperasipada • BilanganBerpangkat • ( Exponent ) • TujuanPembelajaran : • Siswadapatmengoperasikan • bilanganberpangkat • 2. Siswadapatmenyederhanakan • bilanganberpangkat
EXPONENT Rene Descartes(1550-1617) A France mathematician, introduced the method of writing exponent for the first time
MAIN TOPIC Definition of The Positive Integer Exponent In junior high school, you had learned about exponential number with base 10. the positive integer exponent implies how many copies of the base are multiplied together (Bilangan Berpangkat adalah suatu cara perkalian dengan bilangan yang sama) Example: an = a x a x a x … x a , sebanyak n faktor 34 = 3 x 3 x 3 x 3 57 = 5 x 5 x 5 x 5 x 5 x 5 x 5
Definition ofExponent ba = c if b b = cardinal number ( bilangan pokok ) a =exponent number ( bilangan pangkat ) c =exponent of the number ( bilangan hasil perpangkatan ) Example : 3 2 = 9 if 3 , then = a 2 2
The Properties of Exponent ( Formula ) 1 2 3 4 5
The Properties of Exponent 6 7 8 9
Example aplication formula • aⁿ = a . a . a ….. a , sebanyak n faktor Contoh : a³ = a . a . a 2³ = 2 . 2 . 2 • aᵐ . aⁿ = aᵐ ⁺ ⁿ Contoh : a³ . a⁴ = a³ ⁺ ⁴ = a⁷ a⁶ . aˡ . a⁵ = a ⁶ ⁺ ˡ ⁺ ⁵ = aᴵ² , (a sebagaibilangan pokokharussama)
3. aᵐ : aⁿ = aᵐ ̄ ⁿ Contoh : a⁸ : a² = a ⁸ ̄ ² = a⁶ a³ . b⁴ = a³ . a ̄ ⁵ . b ⁴ . b ̄ ⁷ = a³ ̄ ⁵ . b ⁴ ̄ ⁷ a⁵ . b⁷ = a ̄ ² . b ̄ ³ 4. ( aᵐ )ⁿ = aᵐ·n Contoh : ( a³ )² = a³·² = a⁶ {(a³)²}⁴ = a³·²·⁴ = a²⁴ ( a³ . b )⁴ = a³·⁴ . b ⁴ = aˡ² . b⁴ a ² ⁵ = aˡ⁰ b ³ bˡ⁵
ᵐ√aⁿ = a n/m Contoh : ⁵√a³ = a3/5 √a = ²√aˡ = a1/2 √x = x1/2 x² . √x = x² . X 1/2 = x²⁺1/2 = x5/2 = x² 1/2 • a ̄ ⁿ = 1/aⁿ , aⁿ = 1/a ̄ ⁿ 3 ̄ ² = 1/3² = 1/9 , 3² = 1/3 ̄ ² 2 ̄ ³ = 1/2³ = 1/8 , 2³ = 1/2 ̄ ³ • a⁰ = 1 10000 ⁰ = 1
Example 1: Simplify the following expressions! a. ((6a2b3)2)4 b. (23a2b3)4 x (2ab2)3 Answer : a. ((6a2b3)2)4 = (62.a2x2.b3x2)4 = (62.a4.b6)4 = 68.a16.b24
b. (23a2b3)4 x (2ab2)3 Answer : = (23a2b3)4 x (2ab2)3 = (23x4 . a2x4 . b3x4) x (23 . a3 . b2x3) = (212 . a8. b12) x (23 . a3 . b6) = (212+3 . a8+3 . b12+6) = 215. a11 . b18
Example 2: Simplify and state each of the following expressions in their positive integer exponents! a. 2p3q-4 b. a-7b5c-9 : 10-10c7d-6 c. (5-2m2n-5)-4
Answer : • 1. 2p3q-4= • 2. a-7b5c-9 : 10-10c7d-6 = = • 3. (5-2m2n-5)-4 = 5-2.-4 . m2.-4 . n-5.-4 • = 58 m-8 n20 • =
Competence Check: • Simplify the following expressions! a. ((-6a2b3)2)4 b. (23a2b3)4 x (2ab2)3 c. • Simplify and state each of the following expressions in their positive integer exponents! a. b. c. (5a2b-3)-3 . 3(a2b3)2
ROOT There are so many phenomena in our life which Can be modeled to the function or equation containing roots. Let start our discussion about concept of roots by studying the rational and irrational number first
Rational numbers are numbers that can be expressed as fraction a/b, where a and b are integers and b 0 Definition of Rational and Irrational Numbers
Definition of Root Root are numbers in the root symbol which cannot produce rational numbers Example : , 07:37:10
Algebra Operation Of The Roots • Addition and Subtraction of the roots b. Multiplication of Roots There are several properties of multiplication of roots, such as: 1. 2. 3.
Example: • Study the following addition and subtraction a. b. • Simplify there following expression a. b.
Answer : • a. b. • a. b. = = =
Example : Simplify each of the following roots! Answer : a. b.