1 / 26

Chapter 10: Equilibrium Electrochemistry

Chapter 10: Equilibrium Electrochemistry. Homework: Exercises(a only):5, 6,7,12, 18, 20, 25, 26 Self Test: 8 and 9. Thermodynamic Properties of Ions in Solution Enthalpy and Gibbs Energy.

Ava
Télécharger la présentation

Chapter 10: Equilibrium Electrochemistry

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Chapter 10: Equilibrium Electrochemistry Homework: Exercises(a only):5, 6,7,12, 18, 20, 25, 26 Self Test: 8 and 9

  2. Thermodynamic Properties of Ions in SolutionEnthalpy and Gibbs Energy • Enthalpy and Gibbs energy of formationValues of DfHø and DfGø refer to formation of ions from reference state of parent ions • Individual enthalpies and Gibbs energies for ions not directly measurable Ag(s) ® Ag+(aq) + 1e- DfHø = ?, DfGø = ? • Only measure overall reactions Ag(s) + 1/2Cl2(g)® Ag+(aq) + 2Cl- (aq) DfHø = -61.58 kJ mol-1 • Since H and G state functions, the overall reaction is the sum of component reactions • DrHø =DfHø(Ag+, aq) + DfHø (Cl-,aq) • Could measure a number of reactions with similar components and by difference get DfHø • Need to know one DfHø however • Define reference ion and assign value of zero for DfHø and DfGø for it • Ion is H+: DfHø(H+(aq)) = 0 and DfGø(H+(aq)) = 0 definition • Measure other ions relative to H+ • Chlorine: DfHø(Cl-, aq) = -167.2 kJ mol-1 + DfGø(Ag+, aq) = -131.2 kJ mol-1 • Determine ions by difference from reaction enthalpy /Gibbs energy • Silver: DrHø =DfHø(Ag+, aq) + DfHø (Cl-,aq) or =DfHø(Ag+, aq) = DrHø - DfHø (Cl-,aq) DfHø(Ag+, aq) =-61.58 kJ mol-1 - (-167.2 kJ mol-1 ) = 105.6 kJ mol-1

  3. 3) Dissociate Cl2(g) 4) Add e- from Cl(g) 2) Remove e- from H(g) 5) Solvate Cl- 1) Dissociate H2(g) 6) Solvate H+ 6) Form H2(g) and Cl2(g) from solvated ions (-DrG) Contribution to DfGø • Contributions can be seen by constructing a thermodynamic cycle • Sum around cycle is zero (G is state function) • DfGø of an ion includes contribution from dissociation, ionization and solvation of hydrogen • All Gibbs energies except DG of solvation estimated from standard tables • DfGø of two ions is related to DsolvGø DfGø(Cl-, aq)= 1272 kJ mol-1 + DsolvGø(Cl-) + DsolvGø(H+) • Can be estimated from Born equation

  4. Born Equation - Solvation Gibbs Energies • Solvation Gibbs energy estimated from the electrical work required to transfer an ion to a solvent - Born Equation • Solvent treated as a dielectric with permittivity, eG • Good example of how work need not be PV work to calculate Gibbs energies {look at Justification 10.1, p.255} • For water, Born equation becomes DsolGø = 6.86 x 104(zi2/ri) kJ mol-1 ri is radius in pm • Values turn out to be in reasonable agreement with experimental

  5. + Standard Entropies of Ions in Solution • Like G and H can’t measure entropies of isolated ions in solution • Assume DfSø for H+ in solution is 0 • Derive values for other ions relative to it • Some ions have positive DfSø and some negative relative to H+ • DfSø (Cl-,aq) = 57 J K-1 mol-1 DfSø (Mg2+,aq) = -128 J K-1 mol-1 • Means that relative to water Mg2+ induces more order and Cl- less • Can be rationalized in terms of charge on ion affecting local order around ion • Small highly charged ions (Mg2+) induce more order than bigger less highly charged ions • Depends a bit on your model for the liquid state how you think about it • Various models include distorted ice-like structure, flickering clusters (Frank-Wen clusters), glassy water (J. Gibbs) • For structure breaking ions Zone B can encroach on Zone A • Estimate of DfSø (H+) on absolute (3rd Law scale) is -21 J K-1 mol-1 • H+ induces order Zone B: Structure somewhat broken Zone C: Structure unaffected Zone A: Structure Highly Affected

  6. Ion Activities Definition • The activity of a solution, a, is related to the chemical potential, µ µ = µø + RTln(a) • Tend to associate activity with concentration (molality) • Its related but not equivalent • Replacement valid in very dilute solution (<10-3 mol/kg total ion concentration) • Given a solution whose ions behave ideally with a molality, bø of 1 mol/kg a = g(b/bø) • g is the activity coefficient • Depends on composition, concentration (molality) and temperature • g ® 1 and a ® b/bø as b ® 0 • From [1] µ = µø + RTln(b) + RTln(g) where b = b/bø µ = µideal + RTln(g) • µideal (= µø + RTln(b) ) is the chemical potential of an ideal dilute solution of molality bhere b = b/bø

  7. Mean Activity coefficients • Consider a solution of two monovalenent cations (M+) and anions (X-) • Deviation from ideality contained in term RTln(g+ g-) • Define (g+ -) = (g+ g-)0.5 (geometric mean) • Reflects fact you can’t really separate deviation from non-ideality • (g+ -) is the mean activity coefficient for monovalent ions • Then, µ+ = µ+ideal + RTln(g+-)and µ- = µ-ideal + RTln(g+-) • Generally for compound MpXq that dissolves into p cations and q anions, by same process define mean activity coefficient as (g+ -) = (g+ g-)1/swhere s = p + q • The chemical potential, µi, becomes µi = µi ideal + RTln(g+-) • And G becomes G = p µ+ + q µ- • Again non-ideality is shared

  8. Estimating (g+ -) - Debye-Hückel Theory • Coulomb interactions imply oppositely charged ions attract each other • In solutions, near an ion counter ions are found (ionic atmosphere) • Coulomb potential(f) drops as 1/r: fi = Zi/r Zia ionic charge • G (& µ) of ion lowered by electrostatic interactions • Since µi = µi ideal + RTln(g+-), lowering is associated with RTln(g+-) • ln(g+-) can be calculated by modeling these interactions • Debye-Hückel Limiting Law (proof Justification 10.2): • zi is charged number on ions • Must sum all ions in solution • Sign of charge included, e.g, zNa+ = +1; zSO42- = -2 • You’ll be using this in lab (Expt. 7, 9) • Works well at dilute solutions (b < 1 mmol/kg) • Extended Debye-Hückel Limiting Law (1 mmol/kg <b < 0.1 mol/kg): • B dimensionless const., adjustable empirical parameter • b>0.1 mol/kg (e.g. sea water): Model dependence of g of solvent on solute and use Gibbs-Duhem equation (SnJdµJ) = 0 to estimate g of solute

  9. Estimating (g+ -) - Debye-Hückel Theory Limiting Law vs. Ionic Strength

  10. Electrochemical Cells • Electrochemical cell - two electrodes in contact with an electrolyte • Electrolyte is an ionic conductor (solution, liquid, or solid) • Electrode compartment = electrode + electrolyte • If electrolytes are different compartments may be connect with salt bridge • Electrolyte solution in agar • Galvanic cell - an electrochemical cell that produces electricity • Electrolytic cell - an electrochemical cell in which a non-spontaneous reaction is driven by an external source of current

  11. Types of Electrodes • Metal/metal ion (a) • Designation:M(s)|M+(aq) • Redox couple: M+ /M • Half reaction: M+(aq) + 1e-® M(s) • Gas (b) • Designation*: Pt(s)|X2(g)|X+(aq) or Pt(s)|X2(g)|X-(aq) • Redox couple: X+ /X2 or X2 / X- • Half reaction: X+(aq) + 1e-® 1/2X2(g) or 1/2X2(g) + 1e-® X-(aq) • Metal/insoluble salt(c) • Designation:M(s)|MX(s)|X-(aq) • Redox couple: MX /M,X- • Half reaction: MX(s) + 1e-® M(s) + X-(aq) • Redox (d) • Designation*: Pt(s)| M+(aq), M2+(aq) • Redox couple: M+/M2+ • Half reaction: M2+(aq) + 1e-® M+(aq) *Inert metal (Pt) source or sink of e-

  12. Half-Reactions • Recall definition of redox: • Redox reaction is one involving transfer of electrons • OILRIG • Oxidation is loss of electrons • Reduction is gain of electrons • Reducing agent (reductant) is electron donor • Oxidizing agent (oxidant) is electron acceptor • Any redox reaction can be expressed as the difference of two reduction half reactions (sum of oxidation and reduction half reaction) Cu2+(aq) + 2e-® Cu(s) Zn2+(aq) + 2e-® Zn(s) (copper - zinc): Cu2+(aq) + Zn(s) ® Cu(s) + Zn2+(aq) • Redox couples are the reduced and oxidizing species in a redox reaction • Written Ox/Red for half reaction Ox + ne- ® Red • Example above: Cu2+/Cu; Zn2+/Zn

  13. Half Reactions • Reaction quotient for half-reaction (Q) • Like reaction quotient for overall reaction (activity of product over activity reactant raised to appropriate power for stoichiometry) except electrons omitted • Cu2+(aq) + 2e-® Cu(s) Q = 1/aCu {Metal in standard state aM = 1} • O2(g) + 4H+(aq) + 4e- ® 2H2O (l) O2 assumed to be ideal gas • Redox couples in an electrochemical cell separated in space • Oxidation in one compartment, reduction in another • Oxidation compartment • Red1® Ox1 + ne- • Electrode at which this occurs is the cathode • Reduction compartment • Ox2 + ne- ® Red2 • Electrode at which this occurs is the anode

  14. Electrolytic Cell Galvanic Cell Half Reactions • Galvanic cell (produces electricity) • Cathode at higher potential than anode • Species being reduced withdraws electrons from cathode giving it a relative (+) charge • Species being oxidized deposits electrons in anode giving it a relative (-) charge • Electrolytic cell(electricity supplied) • Oxidation still occurs at anode • Oxidation doesn’t occur spontaneously • Electrons come from the species in that compartment • Anode relatively positive to cathode • Cathode • Supply of electrons drives reduction

  15. Daniel Cell Types of Cells • Commonest cell has single electrolyte in contact with both electrodes • Daniel cell - electrode compartments separated • Different electrolyte in each compartment • Electrolyte concentration cell - same electrolyte, different concentration • Electrode concentration cell - electrodes have different concentration • Gas cells at different pressures • Amalgams at different cocentrations • Additional potential difference across interface of two electrolytes - liquid junction potential • Present in electrolyte concentration cells • Due to differing mobility of ions of different sizes across interface • Can be reduced with salt bridge • Potential is then independent of concentration of electrolyte solution

  16. Cell Reactions • Notation - overall cell reaction denoted by cell diagram • Phase boundary denoted by single vertical line (|) • Liquid junction denoted by single vertical dotted line (:) Daniel cell • Interface with no junction potential double verticla line (||) Salt bridge • Cell Reactions: reaction occurring in the cell with the right-hand as the cathode (spontaneous reduction) • To write cell reaction: 1. Write r.h.s. as reduction 2. Write l.h.s. as reduction 3. Subtract 2 from 1 • Cell Potential - electrical work that can be done through the transfer of electrons in a cell • Depends on the potential difference between electrodes • If overall reaction at equilibrium cell potential is zero • If reaction spontaneous, w is negative. At constant p and T we,max = DG • Work is maximum only if cell is operating reversibly • G is related to composition, work is reversible @ constant composition, i.e., no current • Under these conditions the potential difference is the electromotive force (emf) of the cell, E

  17. Cell Reactions: Relation between E and DrG • For a reversible cell, the Gibbs energy of reaction, DrG, is proportional to the cell potential, DrG = -nFE where n is the number of electrons transferred and F is Faraday’s constant  Proof • When potential is high,DrG is negative and cell reaction is spontaneous • The emf (driving power of cell) is related to the extent of reaction

  18. Nernst Equation: Relationship of emf to Activity • Recall that the Gibbs energy of reaction is related to composition: DrG = DrGø + RTlnQ where Q is reaction quotient(anJproducts/anJreactants) • Since DrG = -nFE E = -(DrGø/nF) - (RT/nF)lnQ • Define -(DrGø/nF) as Eø, the standard emf of the cell • So, E = Eø - (RT/nF)lnQ(Nernst Equation) • Eø is the emf when all reactants and products are in their standard states • aproducts = 1 and areactants = 1, so Q=1 and ln(Q) = 0 • Nernst Equation indicates a plot of E vs. ln Q will have • Slope = -(RT/nF) • Intercept = Eø You’ll see this in Lab #6 • At 25°C, RT/F = 0.0257 mV, Nernst equation becomes E = Eø - (0.0257 V/nF)lnQ

  19. Nernst Equation: Concentration Cells M|M+(aq, L)|| M+(aq, R)|M • In above cell the only difference is the concentration of electrolyte in each cell • Left cell - molality is L; right cell - molality is R • Cell reaction: M+(aq, R) ® M+(aq,L) • nis 1 • Eø is 0 because when R=L the two compartments are identical and no driving force • Nernst Equation: E = Eø - (RT/nF)lnQ • In this case: E = - (RT/F)ln(aL/aR) = - (RT/F)ln(bL/bR) • If R>L, ln(bL/bR)<0, E>0, concentration will be lowered by reduction in right compartment • If L>R, ln(bL/bR)>0, E<0, concentration will be lowered by reduction in left compartment • This has biological application - nerve firing involves change in permeability of cell membrane to Na+ This changes nerve cell potential. (see text)

  20. Nernst Equation: Equilibrium Cells • At equilibrium, by definition no work can be done • E = 0 • Concentrations are fixed by the equilibrium constant(K) • K=Q • Nernst Equation: E = Eø - (RT/nF)lnQ • In this case: E = 0 so Eø = (RT/nF)lnQ = (RT/nF)lnK • Rearranging, lnK = Eø/ (RT/nF) = nFEø/ RT or K = exp(nFEø/ RT) • This means cell potentials can be used to determine equilibrium constants

  21. Standard Potentials • Since you can’t measure the potential of a single electrode, one pair has been assigned, by convention a potential of 0 • Standard hydrogen electrode (SHE): • Other potentials determined by constructing cells in which SHE is left hand electrode: • Silver Chloride|Silver Pt(s)|H2(g)|H+(aq)||Cl-(aq)|AgCl(s)|Ag Eø(AgCl, Ag, Cl-)=+0.22V Reaction: AgCl(s) + 1/2H2(g) ® Ag(s) + H+(aq) + Cl-(aq) • Because all potentials are relative to the hydrogen electrode, the reaction is listed without the contribution of the SHE, AgCl(s) ® Ag(s) + Cl-(aq) • Numerical factors • If std emf reaction is multiplied by numerical factor, DrG increases by that factor • Standard potential does not increase! • Recall Eø = -(DrGø/nF) If DrGø(new) = n x DrGø, n(new) = n x n Eø (new) = -(DrGø(new) / n(new) F) =-(n x DrGø /nn(new) F)= -(DrGø/nF) = Eø

  22. Cell emf & Standard Potentials • Cell emf of any cell can be calculated from table of standard potentials • emf of cell is just difference in standard potential • Procedure: 1) Write new cell diagram 2) Eø = Eø(right) - Eø(left) • Sc(s)|Sc3+(aq)||Al3+(aq)|Al(s) • Al3+(aq) + 3e- ® Al(s) Eø = 1.69 V • Sc3+(aq) + 3e- ® Sc(s) Eø = -2.09 V • Al3+(aq) + Sc(s) ® Sc3+(aq) +Al • Eø = 1.69 V - (-2.09 V) = 3.78V • Recall: Eø = -(DrGø/nF) • If Eø > 0, DrGø < 0 and K>1 • Example above, at 25°C, K = exp(nFEø/ RT) = exp (3 x 3.78V/0.0257V) = exp(441) = 4.27 x 10191 K = [Sc3+]/[Al3+]

  23. Measuring Standard Potentials Harned Cell • From Nernst Equation E = E°(AgCl/Ag,Cl-) - (RT/F)ln Q E = E°- (RT/F)ln ((aH+ aCl-)/(fH2/pØ)0.5 = E°- (RT/F){ln (aH+ aCl-) -ln(fH2/pØ)0.5 } Let fH2= pØ. E = E°- (RT/F)ln (aH+ aCl-) But a =bg± and bH+= bCl-) so E = E°- (RT/F)ln (b2g± ) = E°- (RT/F)ln (b2) - (RT/F)ln (g±2) = E°- (2RT/F)ln(b) - (2RT/F)ln(g±) • Debye-Hückel Limiting Law log(g±) a -I0.5solog(g±) a -b0.5orln(g±) a -b0.5 • E = E°- (2RT/F)ln(b) + Cb0.5 or E + (2RT/F)ln(b) = E° + Cb0.5 • This meansa plot of {E + (2RT/F)ln(b)} vs. b0.5 has Eø as intercept • Measuring activity coefficients • Since E = E°- (2RT/F)ln(b) - (2RT/F)ln(g±) , ln(g±) = {(Eø - E)/(2RT/F)}- ln(b) • Knowing Eø and measuring E at known molality allows you to calculate activity coefficient

  24. More Reducing Applications of Standard Potential • Electrochemical series • Because Eø = -(DrGø/nF), if Eø > 0, DrGø < 0 • Since Eø = Eø2 - Eø1 , the reaction is spontaneous as written • Red1 has tendency to reduce Ox2 , if Eø1 <Eø2 • More directly in the electromotive series elements arranged such that low on the chart reduces high • Calcium reduces platinum (Eø = 4.05 V) • Platinum reduces gold (Eø = 0.51) • Tin reduced lead (Eø = 0.011 V) • Sodium reduces magnesium (Eø = 0.34 V) More Oxidzing

  25. pH and pKa Glass Electrode • For hydrogen electrode (1/2 reaction above), Eø = 0 • If fH2= pø, Q = 1/aH+ and E = (RT/F) ln(aH+) • E = Eø - (RT/nF) lnQ • Converting ln to log (ln =2.303log), E = (RT/F) 2.303log(aH+) • Define pH=-logaH so E = -2.303(RT/F)pH • At 25°C, E= -59.16mVpH • Measurement • Direct method: hydrogen electrode + saturated calomel reference electrode (Hg2Cl2) • At 25°C, pH = (E + E(calomel))/ (-59.16mV ) • Indirect method: • Replace hydrogen electrode with glass electrode sensitive to hydrogen activity (but not permeable to H+ • E(glass) a pH, E(glass) = 0 when pH = 7 • pKA • Since we learned pH = pKa when concentration of acid and conjugate base are equal pKa can be measured directly from pH measurement • Ion-Selective electrodes - related to glass electrode except potentials sensitive to other species (see Box 10.2, p 278)

  26. Electrochemical Cells and Thermodynamic Functions • Since the standard emf of a cell is related to the Gibbs energy, electrochemical measurements can be used to obtain other thermodynamic functions • Complementary to calorimetric measurements • Esp. useful for ions in solutions (aqueous, molten salts, etc.) • Starting point: DrGø = -nFEø and thermodynamic relationships we saw earlier • DrGø can be used to calculate Eø directly (or reverse) • Look at Example 10.4 - important caution about the relationship between numerical factors and Eø • Entropy (S) • Thermodynamic relationship: (∂G/∂T)p =-S DrGø = -nFEø At constant p, (dGø/dT)=-nF(dEø/dT) -DS=-nF(dEø/dT) or (dEø/dT) =DS/nF • Enthalpy (S) • Thermodynamic relationship: DrHø = DrGø + T DrSø DrHø = -nFEø + T(nF(dEø/dT)) DrHø =-nF(Eø -TdEø/dT)

More Related