html5-img
1 / 32

Whole Genome Sequencing

Whole Genome Sequencing. (Lecture for CS498-CXZ Algorithms in Bioinformatics) Sept. 13, 2005 ChengXiang Zhai Department of Computer Science University of Illinois, Urbana-Champaign. Most slides are taken/adapted from Serafim Batzoglou’s lectures. Outline.

Leo
Télécharger la présentation

Whole Genome Sequencing

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Whole Genome Sequencing (Lecture for CS498-CXZ Algorithms in Bioinformatics) Sept. 13, 2005 ChengXiang Zhai Department of Computer Science University of Illinois, Urbana-Champaign Most slides are taken/adapted from Serafim Batzoglou’s lectures

  2. Outline • Practical challenges in genome sequencing • Whole genome sequencing strategies • Sequencing coverage (Lander-Waterman model) • Overlap-Layout-Consensus approach

  3. Challenges with Fragment Assembly • Sequencing errors ~1-2% of bases are wrong • Repeats • Computation: ~ O( N2 ) where N = # reads false overlap due to repeat Bacterial genomes: 5% Mammals: 50%

  4. Repeat Types • Low-Complexity DNA (e.g. ATATATATACATA…) • Microsatellite repeats (a1…ak)N where k ~ 3-6 (e.g. CAGCAGTAGCAGCACCAG) • Transposons/retrotransposons • SINEShort Interspersed Nuclear Elements (e.g., Alu: ~300 bp long, 106 copies) • LINELong Interspersed Nuclear Elements ~500 - 5,000 bp long, 200,000 copies • LTRretroposonsLong Terminal Repeats (~700 bp) at each end • Gene Families genes duplicate & then diverge • Segmental duplications ~very long, very similar copies

  5. The sequencing errors, repeats, and the complexity of genomes make it necessary to use many heuristics in practice… The Shortest Superstring formulation is an over-simplification of the problem

  6. Strategies for whole-genome sequencing • Hierarchical – Clone-by-cloneyeast, worm, human • Break genome into many long fragments • Map each long fragment onto the genome • Sequence each fragment with shotgun • Online version of (1) – Walkingrice genome • Break genome into many long fragments • Start sequencing each fragment with shotgun • Construct map as you go • Whole Genome Shotgunfly, human, mouse, rat, fugu One large shotgun pass on the whole genome

  7. Hierarchical Sequencing vs. Whole Genome Shotgun • Hierarchical Sequencing • Advantages: Easy assembly • Disadvantages: • Build library & physical map; • Redundant sequencing • Whole Genome Shotgun (WGS) • Advantages: No mapping, no redundant sequencing • Disadvantages: Difficult to assemble and resolve repeats Whole Genome Shotgun appears to get more popular…

  8. cut many times at random Whole Genome Shotgun Sequencing genome forward-reverse paired reads known dist ~500 bp ~500 bp

  9. Fragment Assembly reads Cover region with ~7-fold redundancy Overlap reads and extend to reconstruct the original genomic region

  10. Read Coverage Length of genomic segment: G Number of reads: N Length of each read: L Definition:Coverage C = NL/ G C

  11. Enough Coverage How much coverage is enough? According to the Lander-Waterman model: Assuming uniform distribution of reads, C=7 results in 1 gap per 1,000 nucleotides

  12. Lander-Waterman Model • Major Assumptions • Reads are randomly distributed in the genome • The number of times a base is sequenced follows a Poisson distribution • Implications • G= genome length, L=read length, N = # reads • Mean of Poisson: =LN/G (coverage) • % bases not sequenced: p(X=0) =0.0009 = 0.09% • Total gap length: p(X=0)*G • Total number of gaps: p(X=0)*N Average times This model was used to plan the Human Genome Project…

  13. Repeats, Errors, and Read lengths • Repeats shorter than read length are OK • Repeats with more base pair diffs than sequencing error rate are OK • To make a smaller portion of the genome appear repetitive, try to: • Increase read length • Decrease sequencing error rate Role of error correction: Discards ~90% of single-letter sequencing errors decreases error rate  decreases effective repeat content However, we have only limited read length. Many heuristics have been introduced to handle repeats…

  14. Overlap-Layout-Consensus Assemblers: ARACHNE, PHRAP, CAP, TIGR, CELERA Overlap: find potentially overlapping reads Layout: merge reads into contigs and contigs into supercontigs Consensus: derive the DNA sequence and correct read errors ..ACGATTACAATAGGTT..

  15. Overlap • Find the best match between the suffix of one read and the prefix of another • Due to sequencing errors, need to use dynamic programming to find the optimal overlap alignment • Apply a filtration method to filter out pairs of fragments that do not share a significantly long common substring

  16. T GA TACA | || || TAGA TAGT Overlapping Reads • Sort all k-mers in reads (k ~ 24) • Find pairs of reads sharing a k-mer • Extend to full alignment – throw away if not >95% similar TAGATTACACAGATTAC ||||||||||||||||| TAGATTACACAGATTAC

  17. Overlapping Reads and Repeats • A k-mer that appears N times, initiates N2 comparisons • For an Alu that appears 106 times  1012 comparisons – too much • Solution: Discard all k-mers that appear more than t Coverage, (t ~ 10)

  18. Finding Overlapping Reads Create local multiple alignments from the overlapping reads TAGATTACACAGATTACTGA TAGATTACACAGATTACTGA TAG TTACACAGATTATTGA TAGATTACACAGATTACTGA TAGATTACACAGATTACTGA TAGATTACACAGATTACTGA TAG TTACACAGATTATTGA TAGATTACACAGATTACTGA

  19. Finding Overlapping Reads (cont’d) • Correcterrors using multiple alignment C: 20 C: 20 C: 35 C: 35 C: 0 T: 30 C: 35 C: 35 TAGATTACACAGATTACTGA C: 40 C: 40 TAGATTACACAGATTACTGA TAG TTACACAGATTATTGA TAGATTACACAGATTACTGA TAGATTACACAGATTACTGA A: 15 A: 15 A: 25 A: 25 - A: 0 A: 40 A: 40 A: 25 A: 25 • Score alignments • Accept alignments with good scores Multiple alignments will be covered later in the course…

  20. Layout • Repeats are a major challenge • Do two aligned fragments really overlap, or are they from two copies of a repeat?

  21. repeat region Merge Reads into Contigs Merge reads up to potential repeat boundaries

  22. repeat region Merge Reads into Contigs (cont’d) • Ignore non-maximal reads • Merge only maximal reads into contigs

  23. repeat boundary??? Merge Reads into Contigs (cont’d) • Ignore “hanging” reads, when detecting repeat boundaries sequencing error b a

  24. Merge Reads into Contigs (cont’d) ????? Unambiguous • Insert non-maximal reads whenever unambiguous

  25. Link Contigs into Supercontigs Normal density Too dense: Overcollapsed? (Myers et al. 2000) Inconsistent links: Overcollapsed?

  26. Link Contigs into Supercontigs (cont’d) Find all links between unique contigs Connect contigs incrementally, if  2 links

  27. Link Contigs into Supercontigs (cont’d) Fill gaps in supercontigs with paths of overcollapsed contigs

  28. d ( A, B ) Link Contigs into Supercontigs (cont’d) Contig A Contig B • Define G = ( V, E ) • V := contigs • E := ( A, B ) such that d( A, B ) < C • Reason to do so: Efficiency; full shortest paths cannot be computed

  29. Link Contigs into Supercontigs (cont’d) Contig A Contig B Define T: contigs linked to either A or B Fill gap between A and B if there is a path in G passing only from contigs in T

  30. Consensus • A consensus sequence is derived from a profile of the assembled fragments • A sufficient number of reads is required to ensure a statistically significant consensus • Reading errors are corrected

  31. Derive Consensus Sequence TAGATTACACAGATTACTGA TTGATGGCGTAA CTA Derive multiple alignment from pairwise read alignments TAGATTACACAGATTACTGACTTGATGGCGTAAACTA TAG TTACACAGATTATTGACTTCATGGCGTAA CTA TAGATTACACAGATTACTGACTTGATGGCGTAA CTA TAGATTACACAGATTACTGACTTGATGGGGTAA CTA TAGATTACACAGATTACTGACTTGATGGCGTAA CTA Derive each consensus base by weighted voting

  32. What You Should Know • The challenges in assembling fragments for whole genome shotgun sequencing • Lander-Waterman model • Main heuristics used in Overlap-Layout-Consensus

More Related