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Thermal losses on the HOM and FPC hooks (BNL cavity)

Thermal losses on the HOM and FPC hooks (BNL cavity). Summary. HOM hook, 2 configurations: Superconducting Niobium Copper FPC hook (copper) Conclusions. HOM hook. Power losses evaluated on the old hook geometry, HFSS calculation performed by M. Navarro and S. Verdú

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Thermal losses on the HOM and FPC hooks (BNL cavity)

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  1. Thermal losses on the HOM and FPC hooks (BNL cavity) F. Carra – CERN

  2. Summary • HOM hook, 2 configurations: • Superconducting Niobium • Copper • FPC hook (copper) • Conclusions F. Carra – CERN

  3. HOM hook • Power losses evaluated on the old hook geometry, HFSS calculation performed by M. Navarro and S. Verdú • Scaling factor HFSS/ANSYS for Nb supra: 3.996E10 • Scaling factor HFSS/ANSYS for Cu: 2.056E16 • Total RF losses on the hook: • Nb supra ~ 5 mW • Cu ~ 2.5 kW!!! F. Carra – CERN

  4. HOM hook – Nb supra • HFSSANSYS to evaluate temperature distribution on the hook • Objective: Tmax < Tsupra (to avoid losing Nb superconductivity) • Conduction only considered (2K boundary on the contact hook/HOM wall) • Results: • Tmax= 3.1K OK! • Low heat flux to He bath (5 mW) OK! • The solution is acceptable from the thermal point of view F. Carra – CERN

  5. HOM hook – Copper • Thermal load too high  the ANSYS calculation is not even converging due to the too high temperature gradient on the hook! • Rough calculation by hand: Tmaxon copper > 10.000K!!! • One can think about studying a cooling circuit for that (very difficult), but anyway the thermal losses to the He bath are huge! F. Carra – CERN

  6. FPC hook – Copper • Total RF losses on the Cu hook ~ 500 W • Lower than the HOM hook (Cu version), but still quite huge • Active cooling needed (most likely water: heat load very high!) F. Carra – CERN

  7. FPC hook – Copper • Example of cooling circuit calculation – WATER • Cooling channel diameter = 4 mm, water speed = 1.3 m/s (should be acceptable for copper)  Q = 1 l/min • hc ~ 7 kW/m2/K (to be checked if this is sufficient depending on the total surface of the cooling channels) • ΔTwater= W/(ρwater ∙ cp_water∙ Q) = 7 ˚C (should be ok) • These characteristics would probably be acceptable, but: • Probably difficult to design a circuit which cools down also the curve part of the hook! F. Carra – CERN

  8. FPC hook – Copper • In this case, imagine that we have a perfect cooling of the straight part (temperature = 26˚C imposed to the zone circled in red) • Huge temperature increase on the curve part! (it’s the most loaded one & it’s not actively cooled) F. Carra – CERN

  9. Conclusions • The geometry studied is the old one! Calculation on the new hook geometry ongoing (s. Verdú) • For the HOM, the Nb supra solution is acceptable from the thermal point of view (low temperature increase and low heat losses to the He bath), while the Cu solution presents way too high thermal loads  not acceptable! • For the FPC, a cooling circuit with water can probably evacuate the heat load; it will be evaluated also with air, but the heat load seems too high for this solution • The problem is to reach with the coolant all the hook: how can one thermalize the curve part? • If the curve part is not thermalized, the temperature rises up to over 400 ˚C! F. Carra – CERN

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