Chemistry Solutions Review 2010 Test Preparation
Enhance your understanding of chemistry solutions with this comprehensive vocabulary review from 2010. Learn key definitions, properties, and calculations. Prepare effectively for your test!
Chemistry Solutions Review 2010 Test Preparation
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Solutions Test Revew Chemistry 2010
Vocabulary: matching • Saturated solution: solution containing the maximum amount of solute that can be dissolved at a given temperature • Unsaturated solution: contains less solute that can be theoretically dissolved at a given temperature. • Supersaturated solution: contains more solute that can be theoretically dissolved at a given temperature
Concentrated solution: a solution with a large amount of solute compared to solvent • Dilute solution: contains only a small amount of the maximum solute that can be dissolved at a given temperature • Miscible: describes liquids that dissolve in each other • Immiscible: describes liquids that are insoluble in each other • Colligative properties: depend upon the number of particles of solute in solution • Molarity: moles of solute per 1 liter of solution • Henry’s Law: at a given temperature the solubility of a gas is directly proportional to the pressure of the gas above the liquid
Multiple Guess facts: need to know • Increasing the temperature of a liquid-solid solution will increase the rate of dissolving and the amount of crystalline material that dissolves • Agitating, crushing, and heating increase the rate of dissolving • As pressure of a gas decreases above a solution solubility into the liquid decreases proportionally (Henry’s Law) • If solubility of a gas is 1g/L @ 100 Kpa of pressure what pressure would be required to increase solubility to 3g/L
Name the three colligative properties: boiling point elevation, freezing point depression, vapor pressure lowering • The more particles an ionic compound breaks into the more it will change the colligative properties (ex: CaCl2 = 3 particles, NaCl =2, C6H12O6 = 1) • Molarity = moles/liter • Ex: 50 moles in 10L = 50moles/10L = 5M • Molality = moles of solute/1kg of solvent 116g NaCl in 450mL(.450kg) of water = 2 moles of NaCl/.450kg = 4.44 molal or 4.44m • Percent (mass/volume) is based on mass of solute/mL of solvent. Remember I mL of water weights 1 gram • Ex: 30 grams of solute in 150mL of water = 30/150 = .20 x 100/% = 20%
To turn an unsaturated solution into a saturated solution: add solute, or lower the temperature • Study notes from today and review sheet, test next class • No net ionic equations on test • Questions ???????