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FOOTBALL PROBABILITY

FOOTBALL PROBABILITY. By: Logan Carter April 11,2012 Period 1. Participants. Logan Carter. Game Objective. Get to the end zone before the other player. Contents. Game board. Dice. 2 Colored game pegs. Probability cards. Penalty cards. Scratch paper and a pencil . Game Setup.

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FOOTBALL PROBABILITY

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  1. FOOTBALL PROBABILITY By: Logan Carter April 11,2012 Period 1

  2. Participants Logan Carter

  3. Game Objective Get to the end zone before the other player.

  4. Contents Game board. Dice. 2 Colored game pegs. Probability cards. Penalty cards. Scratch paper and a pencil.

  5. Game Setup This is a two player game. Each player chooses a game piece and sets their game piece on the start line.

  6. To Play * Flip a coin to see who goes first. * Player 1 rolls the die and moves forward that amount of spaces. Each roll of the die is considered a turn. * The spaces on the board will be marked with probability question spaces, penalty spaces, time out spaces, blank spaces, and bonus spaces. * Choose the card listed on the space you land on. (The probability space will have a probability math question that will allow you to keep your spot if answered correctly. If you answer the question incorrectly you must draw a card from the penalty stack of cards and follow the directions on the card.) * If you land on a penalty space, draw a card from the penalty card stack and follow directions on the card. *The time out space means you do not have to

  7. To Play continued… answer a question, and you remain on the same space until your next turn. *After player one has answered their question, player two rolls the die. *If two players land on the same space. The last players to land on the space has made an interception and does not have to answer a question. The original player on the spot now has to answer the question in order to stay on the spot. If the question is answered incorrectly the original player has to return to start.

  8. Be A Winner! The first player to reach the end zone wins the game..

  9. How To Solve The Problems

  10. Coin & Die Question: Jerry is rolling a die and flipping a coin, what is the probability he would get tails and an odd number? Step 1 : Make and look at the sample space.

  11. Jerry is rolling a die and flipping a coin, what is the probability he would get tails and an odd number?Step 2:

  12. Jerry is rolling a die and flipping a coin, what is the probability he would get tails and an odd number? Step 3:

  13. Jerry is rolling a die and flipping a coin, what is the probability he would get tails and an odd number?Step: 4 Probability = 3 Total outcomes 12

  14. Jerry is rolling a die and flipping a coin, what is the probability he would get tails and an odd number? Step 5: 3 ÷ 3 = 1 12 3 4

  15. Jerry is rolling a die and flipping a coin, what is the probability he would get tails and an odd number? Step: 6 33 ÷ 3 = 1 numerator = 1÷ 4 = 0.25 12 3 4 denominator

  16. Jerry is rolling a die and flipping a coin, what is the probability he would get tails and an odd number?Step: 7 1 ÷ 4 = 0.25 0.25 x 100 = 25% or 0.25 = 25%

  17. Two Dice: Rob is about to roll two(2) dice 48 times. How many times should he expect to get a sum of four(4)?Step 1

  18. Two Dice: Rob is about to roll two(2) dice 48 times. How many times should he expect to get a sum of four(4)?Step 2

  19. Two Dice: Rob is about to roll two(2) dice 48 times. How many times should he expect to get a sum of four(4)?Step 3 3 = x or 1 = x 36 48 12 48

  20. Two Dice: Rob is about to roll two(2) dice 48 times. How many times should he expect to get a sum of four(4)?Step 4 1 = x 12 48

  21. Two Dice: Rob is about to roll two(2) dice 48 times. How many times should he expect to get a sum of four(4)?Step 4 1 = x 12 48 48 x 1 = 48

  22. Two Dice: Rob is about to roll two(2) dice 48 times. How many times should he expect to get a sum of four(4)?Step 5 divide 1 = x 12 48 48 x 1 = 48 12

  23. Two Dice: Rob is about to roll two(2) dice 48 times. How many times should he expect to get a sum of four(4)?Step 5 divide 1 = x 12 48 48 x 1 = 48 = 4 or 4 12 1

  24. Two Dice: Rob is about to roll two(2) dice 48 times. How many times should he expect to get a sum of four(4)?Step 5 divide 48 x 1 = 48 = 4 or 4 12 1 Rob should get a sum of 4 times

  25. Football Probability makes learning math fun. Learning to solve theoretical and experimental probability questions also teaches you the difference between the two different types of probabilities. Using a sample space will help you solve a theoretical question, while experimental results will answer your experimental probability.

  26. Football Probability

  27. References 1. Game board accessed April 11, 201ttp://www.google.com/imgres?q=football+game+board&start=202&um=1&hl=en&biw=1600&bih=665&tbm=isch&tbnid=a_-cqtwmj7-lzM:&imgrefurl=http://www.masterfile.com/stock-photography/image/400-05184629/American-football-field-with-chalk-markings-on-black-board&docid=lNk-Hl-oNmfCCM&imgurl=http://image1.masterfile.com/em_w/05/18/46/400-05184629w.jpg&w=550&h=391&ei=PSyGT6CyD-SyiQKE2MjjDw&zoom=1&iact=rc&dur=148&sig=113843051757089930241&page=8&tbnh=142&tbnw=190&ndsp=30&ved=1t:429,r:54,s:202,i:121&tx=108&ty=106 2. Trouble game pegs access April 11, 2012 from http://www.google.com/imgres?q=Trouble+game+pegs&um=1&hl=en&biw=1600&bih=665&tbm=isch&tbnid=6RSSc906KDCPbM:&imgrefurl=http://cgi.ebay.com/1986-Trouble-Pop-O-Matic-Game-Parts-4-Pastic-Pegs-Pawns-/320661539922&docid=9rN58oau3X7VkM&itg=1&imgurl=http://i.ebayimg.com/t/1986-Trouble-Pop-O-Matic-Game-Parts-4-Pastic-Pegs-Pawns-/00/%2524(KGrHqEOKpYE0VG%252B7Eg%252BBNZH8O4RH!~~_35.JPG&w=300&h=225&ei=yyyGT_mnNfLaiQKsgO3jDw&zoom=1&iact=rc&dur=368&sig=113843051757089930241&page=1&tbnh=143&tbnw=172&start=0&ndsp=24&ved=1t:429,r:39,s:0,i:98&tx=117&ty=114 3. All other photos accessed April 11, 2012 from Microsoft clip art. 4. Slides 11-24 Janine Paula and Lovely Valerie, 2011. 5. Slide 26 accessed April 15, 2012 from http://www.leaguelineup.com/calendar.asp?cmenuid=3&url=wahiawalancers&sid=343499841

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