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This overview covers essential concepts of Binary Search Trees (BSTs) from CS.332. It includes operation fundamentals such as insertion, searching, and deletion, emphasizing the BST properties and structure. The review highlights tree walking techniques, including inorder, preorder, and postorder traversals used to print elements in sorted order. It also discusses the efficiency of BST operations in terms of time complexity and explores applications like sorting and implementing priority queues. This material serves as both a review and preparation for exams on dynamic data structures.
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CS 332: Algorithms Go over exam Binary Search Trees David Luebke 19/1/2014
Exam • Hand back, go over exam David Luebke 29/1/2014
Review: Dynamic Sets • Next few lectures will focus on data structures rather than straight algorithms • In particular, structures for dynamic sets • Elements have a key and satellite data • Dynamic sets support queries such as: • Search(S, k), Minimum(S), Maximum(S), Successor(S, x), Predecessor(S, x) • They may also support modifying operationslike: • Insert(S, x), Delete(S, x) David Luebke 39/1/2014
Review: Binary Search Trees • Binary Search Trees (BSTs) are an important data structure for dynamic sets • In addition to satellite data, eleements have: • key: an identifying field inducing a total ordering • left: pointer to a left child (may be NULL) • right: pointer to a right child (may be NULL) • p: pointer to a parent node (NULL for root) David Luebke 49/1/2014
F B H A D K Review: Binary Search Trees • BST property: key[leftSubtree(x)] key[x] key[rightSubtree(x)] • Example: David Luebke 59/1/2014
Inorder Tree Walk • What does the following code do? TreeWalk(x) TreeWalk(left[x]); print(x); TreeWalk(right[x]); • A: prints elements in sorted (increasing) order • This is called an inorder tree walk • Preorder tree walk: print root, then left, then right • Postorder tree walk: print left, then right, then root David Luebke 69/1/2014
F B H A D K Inorder Tree Walk • Example: • How long will a tree walk take? • Prove that inorder walk prints in monotonically increasing order David Luebke 79/1/2014
Operations on BSTs: Search • Given a key and a pointer to a node, returns an element with that key or NULL: TreeSearch(x, k) if (x = NULL or k = key[x]) return x; if (k < key[x]) return TreeSearch(left[x], k); else return TreeSearch(right[x], k); David Luebke 89/1/2014
F B H A D K BST Search: Example • Search for D and C: David Luebke 99/1/2014
Operations on BSTs: Search • Here’s another function that does the same: TreeSearch(x, k) while (x != NULL and k != key[x]) if (k < key[x]) x = left[x]; else x = right[x]; return x; • Which of these two functions is more efficient? David Luebke 109/1/2014
Operations of BSTs: Insert • Adds an element x to the tree so that the binary search tree property continues to hold • The basic algorithm • Like the search procedure above • Insert x in place of NULL • Use a “trailing pointer” to keep track of where you came from (like inserting into singly linked list) David Luebke 119/1/2014
F B H A D K BST Insert: Example • Example: Insert C C David Luebke 129/1/2014
BST Search/Insert: Running Time • What is the running time of TreeSearch() or TreeInsert()? • A: O(h), where h = height of tree • What is the height of a binary search tree? • A: worst case: h = O(n) when tree is just a linear string of left or right children • We’ll keep all analysis in terms of h for now • Later we’ll see how to maintain h = O(lg n) David Luebke 139/1/2014
Sorting With Binary Search Trees • Informal code for sorting array A of length n: BSTSort(A) for i=1 to n TreeInsert(A[i]); InorderTreeWalk(root); • Argue that this is (n lg n) • What will be the running time in the • Worst case? • Average case? (hint: remind you of anything?) David Luebke 149/1/2014
3 1 8 2 6 5 7 Sorting With BSTs • Average case analysis • It’s a form of quicksort! for i=1 to n TreeInsert(A[i]); InorderTreeWalk(root); 3 1 8 2 6 7 5 1 2 8 6 7 5 2 6 7 5 5 7 David Luebke 159/1/2014
Sorting with BSTs • Same partitions are done as with quicksort, but in a different order • In previous example • Everything was compared to 3 once • Then those items < 3 were compared to 1 once • Etc. • Same comparisons as quicksort, different order! • Example: consider inserting 5 David Luebke 169/1/2014
Sorting with BSTs • Since run time is proportional to the number of comparisons, same time as quicksort: O(n lg n) • Which do you think is better, quicksort or BSTsort? Why? David Luebke 179/1/2014
Sorting with BSTs • Since run time is proportional to the number of comparisons, same time as quicksort: O(n lg n) • Which do you think is better, quicksort or BSTSort? Why? • A: quicksort • Better constants • Sorts in place • Doesn’t need to build data structure David Luebke 189/1/2014
More BST Operations • BSTs are good for more than sorting. For example, can implement a priority queue • What operations must a priority queue have? • Insert • Minimum • Extract-Min David Luebke 199/1/2014
BST Operations: Minimum • How can we implement a Minimum() query? • What is the running time? David Luebke 209/1/2014
BST Operations: Successor • For deletion, we will need a Successor() operation • Draw Fig 13.2 • What is the successor of node 3? Node 15? Node 13? • What are the general rules for finding the successor of node x? (hint: two cases) David Luebke 219/1/2014
BST Operations: Successor • Two cases: • x has a right subtree: successor is minimum node in right subtree • x has no right subtree: successor is first ancestor of x whose left child is also ancestor of x • Intuition: As long as you move to the left up the tree, you’re visiting smaller nodes. • Predecessor: similar algorithm David Luebke 229/1/2014
F Example: delete Kor H or B B H C A D K BST Operations: Delete • Deletion is a bit tricky • 3 cases: • x has no children: • Remove x • x has one child: • Splice out x • x has two children: • Swap x with successor • Perform case 1 or 2 to delete it David Luebke 239/1/2014
BST Operations: Delete • Why will case 2 always go to case 0 or case 1? • A: because when x has 2 children, its successor is the minimum in its right subtree • Could we swap x with predecessor instead of successor? • A: yes. Would it be a good idea? • A: might be good to alternate David Luebke 249/1/2014
The End • Up next: guaranteeing a O(lg n) height tree David Luebke 259/1/2014