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Complex Numbers and Polynomial Functions

Simplify complex numbers, factor polynomials, and graph polynomial functions with real and non-real zeros. Understand the end behavior, leading coefficient, degree, and number of real and non-real zeros.

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Complex Numbers and Polynomial Functions

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  1. total: pencil, red pen, highlighter, GP notebook U7D8 Have out: Bellwork: 1. Simplify the complex numbers. Write part (b) in a + bi form. +1 +1 a) b) r 3 16 2. Factor p(x) = x3 – 64, then find all zeros.

  2. total: 1. Simplify, and write in a + bi form. 2. Factor p(x) = x3 – 64, then find all zeros. +1 b) +2 find the zeros: +1 +1 4 4 +1 +1 +1 +1 +1 +1 +1

  3. y y y x x x conjugate Complex zeros always come in __________ pairs. 0 2 A cubic polynomial could have ___ or ___ complex zeros, and ___, ___, or ___ real zeros. 3 1 2 possibilities: 1 real 2 real (one is double) 3 real 0 non–real 0 non–real 2 non–real

  4. y y y y x x x x y x 0 2 4 A fourth degree polynomial could have ___, ___, or ___ complex zeros, and ___, ___, ___, ___, or ___ real zeros. 0 1 2 3 4 possibilities: 0 real 1 real (but it’s double) 2 real 4 non–real 2 non–real 2 non–real 3 real, but one is double 4 real 0 non–real 0 non–real

  5. REMEMBER: conjugate pair When there is a complex zero there is always a _____________.

  6. y x Turning Points to Degree Principle direction Turning points ____________ – points where the graph changes _________ from increasing to decreasing or decreasing to increasing. n–degree An _________ polynomial function has at most _____ turning points. n – 1 2 For example, a 4th degree polynomial has at most 3 turning points. However in many other cases, it is possible to have less. 3 1 n Using the same principle, a polynomial that has ___ turning points has a degree of ______ or greater. n + 1

  7. P(x) x 2. For each graph, a) describe the end behavior and describe the leading coefficient (+ / –) b) determine whether it represents an odd-degree or an even-degree polynomial function, and guess it’s minimum value. c) state the number of real zeros. d) state the number of non-real values. 1 End behavior: Leading coefficient: Degree: Real zeros: Non–real zeros: a) + odd, 3 3 0 2 To compute the minimum degree, count the number of turning points, then add 1. The real zeros are the ones where the graph crosses the x–axis. Remember: real + non-real = degree

  8. P(x) x b) End behavior: Leading coefficient: Degree: Real zeros: Non–real zeros: 2 + even, 4 4 0 3 To compute the minimum degree, count the number of turning points, then add 1. 1 P(x) End behavior: Leading coefficient: Degree: Real zeros: Non–real zeros: c) – even, 4 1 3 0 x 4 How may zeros are left? 2 Try the next few on your own...

  9. P(x) x d) e) P(x) x End behavior: Leading coefficient: Degree: Real zeros: Non–real zeros: End behavior: Leading coefficient: Degree: Real zeros: Non–real zeros: + + odd, 5 odd, 3 5 1 0 2 Remember: real + non-real = degree

  10. g) f) P(x) P(x) x x End behavior: Leading coefficient: Degree: Real zeros: Non–real zeros: End behavior: Leading coefficient: Degree: Real zeros: Non–real zeros: – – even, 6 odd, 9 2 1 4 8

  11. h) P(x) double zero! End behavior: Leading coefficient: Degree: Real zeros: Non–real zeros: x + even, 6 3 2

  12. Get out the worksheet: Graphing Polynomial Functions With Non–Real Zeros Part 1: Determine the degree and zeros. Sketch a graph of the polynomial function. 3 1) 3, ±2i When we graph this function, can we graph all the zeros (real and non–real)? No! We can only graph the real zeros on a Cartesian plane.

  13. y x 3 1) 3, ±2i Graph the only real x–intercept. Next thing to consider: how do we graph the function and still make it look like a 3rd degree polynomial? (3, 0) We must have an inflection point some–where on the graph because it is cubic. Graph the y–intercept Therefore, we only know 4 things: (0, –12) (1) x–intercept (2) y–intercept (3) end behavior (4) inflection point is somewhere However, we don’t know the effect of the non–real zeros on the polynomial.

  14. y x 3 1) 3, ±2i We only know 4 things: (1) x–intercept (2) y–intercept (3, 0) (3) end behavior (4) inflection point is somewhere There are several acceptable graphs that meet these 4 criteria. (0, –12) Draw your graph. Be careful to cross the x–axis only once through the real zero, and make sure that the graph passes the vertical line test.

  15. y x 3 1) 3, ±2i The actual graph is given on the left. Does your graph look like this? Maybe not, but that’s okay.  (3, 0) Since we are NOT using graphing calculators, we have some freedom when we sketch graphs. Therefore, there are many acceptable answers. (0, –12) Let’s look at some other possibilities…

  16. y y (3, 0) x x (0, –12) 3 1) 3, ±2i (3, 0) (0, –12) All of these graphs meet the 4 criteria. Any other possibilities out there?

  17. 2) 4 x = ±3, ± 3i y non–real solutions 2 real (–3, 0) (3, 0) x We can ONLY graph the real zeros. (0, –81)

  18. 2) 4 x = ±3, ± 3i What are the criteria we know? y (1) x–intercept (2) y–intercept (3) end behavior (–3, 0) (3, 0) x Draw a 4th degree polynomial that fits these criteria. (0, –81) Does your graph look like this? No? Let’s look at other possibilities…

  19. y (–3, 0) (3, 0) x (0, –81) 2) 4 x = ±3, ± 3i y (–3, 0) (3, 0) x (0, –81) Even though these are not the correct graph, they are acceptable at this point in Algebra 2 without a graphing calculator. You will have to wait until Math Analysis for further details.

  20. 3 3) x = 0, ±5i y x (0, 0) There is only one real zero and 2 non–real zeros. Only graph the real zero.

  21. 3 3) x = 0, ±5i We only know 4 things: y (1) x–intercept (2) y–intercept (same as x–int) (3) end behavior (4) inflection point is somewhere since the function is cubic x (0, 0) Draw a 3rd degree polynomial that fits these criteria. Does your graph look like this? Let’s look at other possibilities…

  22. 3 3) x = 0, ±5i y y x x (0, 0) (0, 0) All of these graphs meet the 4 criteria. Any other possibilities out there?

  23. –3 –2 4 4) y –3 1 x (0, –3) There are 2 real zeros and 2 non–real zeros. Only graph the real zeros.

  24. 4 4) What are the criteria we know? y (1) x–intercept (2) y–intercept (3) end behavior x Draw a 4th degree polynomial that fits these criteria. (0, –3) Does your graph look like this? Let’s look at other possibilities…

  25. 4 4) y y x x (0, –3) (0, –3) All of these graphs meet the criteria. Any other possibilities out there?

  26. Complete the worksheet.

  27. (–2, 4) Day 7 Mixed Practice 1a) Determine the function that generates each graph below. roots: x = –4, 0, 2 Double zero P(x) = a (x + 4) (x)2 (x – 2 ) 4 = a(–2+4)(–2)2(–2 – 2) Boing! 4 = a(2)(4)(–4) 4 = a(–32)

  28. Day 7 Mixed Practice 1d) Determine the function that generates each graph below. zeros: x = –2, 1, 3 P(x) = a (x + 2)3 (x – 1) (x – 3)2 –2 = a(–1+2)3(–1 – 1)(–1 – 3)2 –2 = a(1)3(–2)(–4)2 (–1, –2) Double zero (squared term) –2 = a(–2)(16) –2 = a(–32) triple zero (cubic term)

  29. 3. Simplify. a) b) c)

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