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MIPS Program for Finding Minimum Values between Two Floating Point Arrays

This MIPS program reads two floating point arrays, array0 and array1, each containing five elements. For each element index 'i', it computes the minimum floating point value between array0[i] and array1[i] and stores the result in a third array, array2[i]. The program utilizes specific MIPS instructions for loading, comparing, and storing floating point numbers. It demonstrates fundamental concepts of MIPS programming while providing a practical example of array manipulation and comparison in assembly language.

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MIPS Program for Finding Minimum Values between Two Floating Point Arrays

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  1. CDA 3100 Recitation Week 7

  2. Write a Complete MIPS Program • For each array element i, find the min(array0[i], array1[i]) and store it into array2[i] • array0, array1, and array2 store floating point numbers • Each array holds 5 elements • array0 holds [0.6, 0.7, 0.9, 0.1, -0.8] • array1 holds [0.8, 1.9, 11.2, -0.19, 0.7]

  3. Some useful instructions • swc1 $f0, 0($t0) • Store floating point number into address • lwc1 $f0, 0($t0) • Load address as floating point number • s.s $f0, 0($t0) • Store floating point number into address • l.s $f0, 0($t0) • Load address as floating point number • mov.s $f0, $f1 • Copy a floating point number • c.lt.s $f0, f1 • If $f0 < $f1, a flag that can be used for jumps is triggered • bc1t L1 • Branch to L1 if flag is set • jalFunc • Go to a function • jr $ra • Return from function

  4. Answer (1) .data array0: .float 0.6, 0.7, 0.9, 0.1, -0.8 array1: .float 0.8, 1.9, 11.2, -0.19, 0.7 array2: .space 20 msg_newline: .asciiz “\n” .text .globl main

  5. Answer (2) main: la $a0, array0 la $a1, array1 la $a2, array2 li $a3, 5 jalfloatArray done: addi $t0, $a2, 0 addi $t1, $0, 0

  6. Answer (3) loop: li $v0, 2 l.s $f12, 0($t0) syscall li $v0, 4 la $a0, msg_newline syscall addi $t0, $t0, 4 addi $t1, $t1, 1 blt $t1, $a3, loop exit: li $v0,10 syscall

  7. Answer (4) floatArray: addi $sp, $sp, -12 swc1 $f0, 8($sp) swc1 $f1, 4($sp) swc1 $f2, 0($sp) addi $t0, $a0, 0 addi $t1, $a1, 0 addi $t2, $a2, 0 addi $t9, $0, 0

  8. Answer (5) floatArrayloop: l.s $f0, 0($t0) l.s $f1, 0($t1) c.lt.s $f0, $f1 bc1t floatArrayskip mov.s $f0, $f1

  9. Answer (6) floatArrayskip: s.s $f0, 0($t2) addi $t0, $t0, 4 addi $t1, $t1, 4 addi $t2, $t2, 4 addi $t9, $t9, 1 blt $t9, $a3, floatArrayloop lwc1 $f0, 8($sp) lwc1 $f1, 4($sp) lwc1 $f2, 0($sp) addi $sp, $sp, 12 jr $ra

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