1 / 12

13.3 Evaluating Trigonometric Functions

13.3 Evaluating Trigonometric Functions. Evaluating Trigonometric Functions Given a Point. Let ( 3 , – 4 ) be a point on the terminal side of an angle in standard position. Evaluate the six trigonometric functions of . 0. 0. 0. r = x 2 + y 2. = 3 2 + ( – 4 ) 2. = 25. r.

bin
Télécharger la présentation

13.3 Evaluating Trigonometric Functions

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. 13.3 Evaluating Trigonometric Functions

  2. Evaluating Trigonometric Functions Given a Point Let (3, – 4) be a point on the terminal side of an angle in standard position. Evaluate the six trigonometric functions of . 0 0 0 r=x2+y2 =32+(– 4)2 = 25 r (3, –4) SOLUTION Use the Pythagorean theorem to find the value of r. = 5

  3. Evaluating Trigonometric Functions Given a Point r 0 y r 4 5 csc = = – 0 sin = = – 0 y r 5 4 3 x r 5 0 cos = = sec = = 0 r x 5 3 y x 3 4 cot = =– tan = = – 0 0 x y 4 3 Using x = 3, y = – 4, and r = 5, you can write the following: (3, –4)

  4. TRIGONOMETRIC FUNCTIONS OF ANY ANGLE 0 0 ' 0 Let be an angle in standard position. Its reference angleis the acute angle (read thetaprime) formed by the terminal side of and the x-axis. The values of trigonometric functions of angles greater than 90° (or less than 0°) can be found using corresponding acuteangles called reference angles.

  5. TRIGONOMETRIC FUNCTIONS OF ANY ANGLE 0 90° < < 180°; π π << 0 2 0 ' ' ' 0 0 0 – 0 0 = 180° Degrees: Radians:= π –

  6. TRIGONOMETRIC FUNCTIONS OF ANY ANGLE 180° < < 270°; 3π π << 2 0 0 0 ' ' ' 0 0 0 – = 0 0 180° Degrees: π – Radians:=

  7. TRIGONOMETRIC FUNCTIONS OF ANY ANGLE 270° < < 360°; 3π 2π << 2 0 0 0 ' ' ' 0 0 0 – = 0 0 360° Degrees: 2π – Radians:=

  8. Finding Reference Angles Find the reference angle for each angle . 0 0 0 0 0 5π = 320° = – 6 ' ' ' 0 0 0 Because 270°< < 360°, the reference angle is = 360° – 320° = 40°. Because is coterminal with and π < < , the reference angle is = – π = . 7π 7π 3π 6 6 2 7π π 6 6 SOLUTION

  9. Evaluating Trigonometric Functions Given a Point CONCEPT EVALUATING TRIGONOMETRIC FUNCTIONS SUMMARY Use these steps to evaluate a trigonometric function of any angle . 0 1 3 2 Find the reference angle . 0 0 ' ' 0 0 Evaluate the trigonometric function for angle . Use the quadrant in which lies to determine thesign of the trigonometric function value of .

  10. Evaluating Trigonometric Functions Given a Point CONCEPT EVALUATING TRIGONOMETRIC FUNCTIONS SUMMARY Quadrant II Quadrant I sin , csc : + sin , csc : + 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 cos , sec : – cos , sec : + tan , cot :– tan , cot :+ Quadrant III Quadrant IV sin , csc : – sin , csc : – cos , sec : + cos , sec : – tan , cot :– tan , cot :+ Signs of Function Values

  11. Using Reference Angles to Evaluate Trigonometric Functions =30° =–210° 0 ' 0 ' 0 The reference angle is = 180° – 150° = 30°. 3 tan (– 210°) = – tan 30° = – 3 Evaluate tan (– 210°). SOLUTION The angle –210°is coterminal with 150°. The tangent function is negative in Quadrant II, so you can write:

  12. Using Reference Angles to Evaluate Trigonometric Functions Evaluate csc. π = 4 = 0 11π 11π 3π The angle is coterminal with . ' 0 4 4 4 ' 0 π 3π The reference angle is = π – = . 4 4 11π 11π π 4 csc = csc = 2 4 4 SOLUTION The cosecant function is positive in Quadrant II, so you can write:

More Related