1 / 18

King Fahd University of Petroleum & Minerals

This lecture covers the application of equations of translation and rotation motion, center of mass role, slipping vs. tipping scenarios, and practical examples. Discusses concepts like wheely vs. non-wheely and provides detailed examples on motion problems.

cathyj
Télécharger la présentation

King Fahd University of Petroleum & Minerals

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. King Fahd University of Petroleum & Minerals Mechanical Engineering Dynamics ME 201 BY Dr. Meyassar N. Al-Haddad Lecture # 31

  2. Objectives • Apply the Equation of Translation motion • Rectilinear Translation • Curvilinear Translation • Apply the equation of Rotation motion • The roll of the center of mass G • Discuss the slipping Vs. Tipping • Discuss the slipping Vs. freely rotating • Discuss the “wheely” Vs. Non-wheely

  3. General Application of the Equations of Motion Summation of moment in FBD = summation of the kinetic moment in K.D

  4. Kinetic Moment

  5. Rectilinear Translation

  6. Curvilinear Translation

  7. x N slipping Vs. Tipping If x > 1.5 ft tipping If x < 1.5 ft slipping

  8. Slipping Vs. Freely rotating Front wheel Vs Back wheel drive Vs Four wheel drive mg FA=msNA NA NB slipping Freely Rotating

  9. “Wheely” Vs. Non-Wheely Wheely : lift the front wheel off the ground NB=0

  10. Example 17-5

  11. Example mk=0.2 a= ? Flip Or Tipp? If x > 0.5 m tipping will take place

  12. Example mm=125 kg mR= 75 kg a= ? NB=? FB=? ms=? Minimum to Lift front wheel

  13. Problem aG mBNB NA NB m = 80 kg mB= 0.8 NA= ? NB= ? When rear wheel locks for break a = ? Deceleration

  14. Problem a = 0 mBNB NA NB m= 80 kg mB= ? NA=? NB=? a =? When traveling at constant velocity and no break was applied

  15. Problem mkNA NA NB=0 m= 80 kg NA=? NB=? a =? mk=? minimum When rider applies the front break and back wheel start to lift off the ground

  16. Example mBD=100kg mAB=mCD= Neglect q = 30o w = 6 rad/s TA= ? TD= ? aG=?

  17. Thank You

More Related