230 likes | 340 Vues
This article presents a review of common SQL query patterns used for data aggregation and counting from various tables. We focus on how to manipulate queries using a Query Builder, rather than writing raw SQL. The examples illustrate how to calculate sums for one column based on another and count occurrences within specific columns. The discussed patterns include summing values, counting distinct items, and handling subqueries for counting specific conditions, all while emphasizing best practices for using a Query Builder effectively.
E N D
Access Patterns we have seen
We review some of the common patterns we have used. • IMPORTANT NOTE: SQL is given for informational purpose only. We have not covered SQL but used the Query Builder instead.
Table • ID A B C • 1 a1 b1 5 • 2 a1 b1 8 • 3 a1 b2 7 • 4 a1 b2 2 • 5 a1 b2 1 • 6 a2 b1 7 • 7 a2 b1 8 • 8 a3 b2 0
What we want: summing for distinguished column of another column • A SumOfC • a1 23 • a2 15 • a3 0
SQL query SELECT Table1.A, Sum(Table1.C) AS SumOfC FROM Table1 GROUP BY Table1.A;
Query Builder Manipulation • Create Query • Choose Table1 • Select column A • Select column C • Totals (GroupBy default) • Sum for column C
Table • ID A B C • 1 a1 b1 5 • 2 a1 b1 8 • 3 a1 b2 7 • 4 a1 b2 2 • 5 a1 b2 1 • 6 a2 b1 7 • 7 a2 b1 8 • 8 a3 b2 0
What we want: Counting for distinguished column • B CountOfB • b1 4 • b2 4
SQL SELECT Table1.B, Count(Table1.B) AS CountOfB FROM Table1 GROUP BY Table1.B;
Query Builder Manipulation • Create Query • Select Table1 • Select column B • Select column B • Totals (GroupBy) • For second column B choose count
Table2 (DebateResults) • ID winner loser forced • 1 1 2 1 • 2 2 1 2 • 3 1 3 3 • 4 3 2 2 • 5 4 1 4 • 6 1 4 4 • 7 1 5 0
What we want: count wins for each debater • winner CountOfwinner • 1 4 • 2 1 • 3 1 • 4 1
SQL • SELECT Table2.winner, Count(Table2.winner) AS CountOfwinner • FROM Table2 • GROUP BY Table2.winner;
Query Builder Manipulation • Create Query • Choose Table2 • Select winner column twice • Totals (GroupBy) • For second winner column: Count
Table2 (DebateResults) • ID winner loser forced • 1 1 2 1 • 2 2 1 2 • 3 1 3 3 • 4 3 2 2 • 5 4 1 4 • 6 1 4 4 • 7 1 5 0
What we want: count faults • FaulterCountOfFaulter • 1 2 • 2 1 • 5 1
Add calculated field for Faulters: subquery • What do we want for the subquery?
Create Faulter column from Loser column • Faulter forced • 2 1 • 1 2 • 1 4 • 5 0
SQL • SELECT Table2.loser AS Faulter, Table2.forced • FROM Table2 • WHERE (((Table2.loser)<>[forced]));
Query Builder Manipulation • Create Query • select loser column; rename to Faulter; condition <>[forced] • select forced column (for checking result) • name subquery: Faults
Reminder: What we want • FaulterCountOfFaulter • 1 2 • 2 1 • 5 1
SQL • SELECT Faults.Faulter, Count(Faults.Faulter) AS CountOfFaulter • FROM Faults • GROUP BY Faults.Faulter;
Query Builder Manipulation • Create Query • Choose subquery Faults • Select Faulter column twice • Totals (GroupBy) • select Count for second