1 / 26

Newton’s Divided Difference Method in Mechanical Engineering Education

Explore Newton’s Divided Difference Polynomial Method of Interpolation in mechanical engineering education, used for finding values at unknown points. Learn linear, quadratic, and cubic interpolation examples to enhance STEM undergraduates' numerical methods knowledge.

chester-christensen
Télécharger la présentation

Newton’s Divided Difference Method in Mechanical Engineering Education

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Newton’s Divided Difference Polynomial Method of Interpolation Mechanical Engineering Majors Authors: Autar Kaw, Jai Paul http://numericalmethods.eng.usf.edu Transforming Numerical Methods Education for STEM Undergraduates http://numericalmethods.eng.usf.edu

  2. Newton’s Divided Difference Method of Interpolationhttp://numericalmethods.eng.usf.edu

  3. What is Interpolation ? Given (x0,y0), (x1,y1), …… (xn,yn), find the value of ‘y’ at a value of ‘x’ that is not given. http://numericalmethods.eng.usf.edu

  4. Interpolants Polynomials are the most common choice of interpolants because they are easy to: • Evaluate • Differentiate, and • Integrate. http://numericalmethods.eng.usf.edu

  5. Newton’s Divided Difference Method Linear interpolation: Given pass a linear interpolant through the data where http://numericalmethods.eng.usf.edu

  6. Example A trunnion is cooled 80°F to − 108°F. Given below is the table of the coefficient of thermal expansion vs. temperature. Determine the value of the coefficient of thermal expansion at T=−14°F using the direct method for linear interpolation. http://numericalmethods.eng.usf.edu

  7. Linear Interpolation http://numericalmethods.eng.usf.edu

  8. Linear Interpolation (contd) http://numericalmethods.eng.usf.edu

  9. Quadratic Interpolation http://numericalmethods.eng.usf.edu

  10. Example A trunnion is cooled 80°F to − 108°F. Given below is the table of the coefficient of thermal expansion vs. temperature. Determine the value of the coefficient of thermal expansion at T=−14°F using the direct method for quadratic interpolation. http://numericalmethods.eng.usf.edu

  11. Quadratic Interpolation (contd) http://numericalmethods.eng.usf.edu

  12. Quadratic Interpolation (contd) http://numericalmethods.eng.usf.edu

  13. Quadratic Interpolation (contd) http://numericalmethods.eng.usf.edu

  14. General Form where Rewriting http://numericalmethods.eng.usf.edu

  15. General Form http://numericalmethods.eng.usf.edu

  16. General form http://numericalmethods.eng.usf.edu

  17. Example A trunnion is cooled 80°F to − 108°F. Given below is the table of the coefficient of thermal expansion vs. temperature. Determine the value of the coefficient of thermal expansion at T=−14°F using the direct method for cubic interpolation. http://numericalmethods.eng.usf.edu

  18. Example http://numericalmethods.eng.usf.edu

  19. Example http://numericalmethods.eng.usf.edu

  20. Example http://numericalmethods.eng.usf.edu

  21. Comparison Table http://numericalmethods.eng.usf.edu

  22. Reduction in Diameter The actual reduction in diameter is given by where Tr = room temperature (°F) Tf= temperature of cooling medium (°F) Since Tr = 80 °F and Tr = −108 °F, Find out the percentage difference in the reduction in the diameter by the above integral formula and the result using the thermal expansion coefficient from the cubic interpolation. http://numericalmethods.eng.usf.edu

  23. Reduction in Diameter We know from interpolation that Therefore, http://numericalmethods.eng.usf.edu

  24. Reduction in diameter Using the average value for the coefficient of thermal expansion from cubic interpolation The percentage difference would be http://numericalmethods.eng.usf.edu

  25. Additional Resources For all resources on this topic such as digital audiovisual lectures, primers, textbook chapters, multiple-choice tests, worksheets in MATLAB, MATHEMATICA, MathCad and MAPLE, blogs, related physical problems, please visit http://numericalmethods.eng.usf.edu/topics/newton_divided_difference_method.html

  26. THE END http://numericalmethods.eng.usf.edu

More Related