1 / 13

Recap – Electron Configuration

Recap – Electron Configuration. Shells contain sub-shells n = 1 has 1 s n = 2 has 2 s and 2 p n = 3 has 3 s , 3 p and 3 d n = 4 has 4 s , 4 p , 4 d and 4 f Sub-shells fill along diagonal. Rules for Lewis Structures.

chun
Télécharger la présentation

Recap – Electron Configuration

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Recap – Electron Configuration Shells contain sub-shells n = 1 has 1s n = 2 has 2s and 2p n = 3 has 3s, 3p and 3d n = 4 has 4s, 4p, 4d and 4f Sub-shells fill along diagonal

  2. Rules for Lewis Structures In Lecture 6 & 7 we looked at covalent bonding. This is formalised with the drawing of Lewis Structures. • Arrange the atoms. • Place the least electronegative atom (not H) in the centre. • Count the total number of valence electrons. • Remember to add or subtract e- for anions and cations. • Allocate two electrons between each pair of atoms which are assumed to be covalently bonded. • Use remaining valence electrons to form lone pairs. • Start with the surrounding atoms (centre atom last). • Check if the central atom has an octet (or more). • If not, move lone pairs from the (least electronegative) surrounding atoms into the bonding region (make double bonds).

  3. Hydrides – CH4 • C is at the centre • Total number of valence electrons = 4 (C) + 4×1 (H) = 8 • Four C-H bonds require 4×2 electrons: • Electrons remaining = 8 (valence) – 8 (bonding) = 0 • Carbon has octet: 4×2 electrons (in bonds): octet

  4. Hydrides – NH3 • N is at the centre • Total number of valence electrons • 5 (N) + 3×1 (H) = 8 • Three N-H bonds require 3×2 electrons: • Electrons remaining = 8 (valence) – 6 (bonding) = 2 • Place lone pair on nitrogen • Nitrogen has octet: • 3×2 electrons (in bonds) + 2 electrons (lone pair)

  5. Hydrides – NH4+ • N is at the centre • Total number of valence electrons • 5 (N) + 4×1 (H) -1 (positive charge) = 8 • Four N-H bonds require 4×2 electrons: • Electrons remaining = 8 (valence) – 8 (bonding) = 0 • Nitrogen has octet: • 4×2 electrons (in bonds)

  6. Organic Molecules • Carbon needs to make 4 bonds to achieve its octet. • There are very many carbon hydrides and these can contain C-C, C=C and C C bonds

  7. Organic Molecules • Organic molecules commonly also contain other elements such as oxygen and nitrogen • Oxygen (valency = 2) and nitrogen (valency = 3) can also make single or multiple bonds

  8. Organic Molecules • Organic molecules commonly also contain other elements such as oxygen and nitrogen • Oxygen (valency = 2) and nitrogen (valency = 3) can also make single or multiple bonds

  9. Bond Lengths and Energies • The length of a bond and energy is takes to break a bond depends on the type of bond • single bonds are longer and weaker than double bonds • double bonds are longer and weaker than triple bonds

  10. Electrons in Bonds • In single bonds: • The pair of electrons orbit directly between the two atoms. • This called a σ (“sigma”) bond σbond

  11. Electrons in Bonds • In double bonds: • The first bond is a σ bond • The second pair of electrons orbit above and below the σ bond • The second bond is called a p bond a p bond a σ bond • In triple bonds: • The first bond is a σ bond • The second and third bonds are p bonds

  12. Learning Outcomes: By the end of this lecture, you should: be able to draw Lewis structures for hydrides, including ones with charges be able to draw and understand Lewis structures for organic molecules containing C, H, N and O be able to explain the relationship between the type of bonds (single, double and triple) and bond strength and length be able to describe bonds as combinations of s and p bonds be able to complete the worksheet (if you haven’t already done so…)

  13. Questions to complete for next lecture: • Draw the Lewis structure of the following hydrides: • SiH4 • H2S • HCl • H3O+ • BH3 • Draw the Lewis structure of the following organic molecules: • CH3NH2 • (CH3)2NH • (CH3)3N • (CH3)4N+

More Related