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Kelas : XII Semester : 1

INDUKSI MAGNET. Mata Pelajaran : FISIKA. Kelas : XII Semester : 1. SK - KD. Standar Kompetensi 2 . Menerapkan konsep kelistrikan dan kemagnetan dalam berbagai penyelesaian masalah dan produk teknologi. Kompetensi Dasar

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Kelas : XII Semester : 1

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  1. INDUKSI MAGNET Mata Pelajaran: FISIKA Kelas : XII Semester : 1

  2. SK - KD StandarKompetensi 2. Menerapkankonsepkelistrikandankemagnetandalamberbagaipenyelesaianmasalahdanprodukteknologi KompetensiDasar 2.2. Menerapkaninduksimagnetikdangayamagnetikpadabeberapaprodukteknologi

  3. IndikatorPencapaian Mendeskripsikan induksimagnetikdisekitarkawatberarus (lurus, melingkar, solenoida)

  4. Materi • I. HUKUM AMPERE 1.1. Induksi Magnet ikdiSekitarKawatLurusBeraru BesarInduksimagnetikdisekitarkawatlurusberarusdapatdirumuskansebagai : ʘ i⊗ B ●P Bp = μ0 i 2π a Di mana: Bp = induksi magnet dititik P ( Wb/m²) µ0 = permeabilitasbahan = 4π . 10⁻⁷ Wb/Am) i= kuatarus (A) a = jaraktitiksembarangterhadapkawat berarus (m)

  5. Materi • Arahinduksi magnet dapatditentukandenganmenggunakanKaidahTanganKananPertamasebagaiberikut: ● Arahibujarisebagaiarahkuataruslistriki ●Arahlipatanempatjari lain sebagaiarahinduksi magnet B

  6. Materi • ContohSoal: (1) Sebuahkawatlurusdialiriaruslistrik 10 A. Tentukanlahinduksi magnet disekitarkawatitu yang berjarak 20 cm ! Penyelesaian: Diketahui :i = 10 A Ditanya: B ? a = 20 cm = 2 x 10⁻¹ m μ₀ = 4π x 10⁻⁷ Wb/Am Jawab : B = μ₀ I 2π a = (4π x 10⁻⁷) (10) (2π) (2 x 10⁻¹) = 4 x 10 ⁻⁵ Wb/m²

  7. Materi • ContohSoal: (2) i₁ = 3 A i₂ The diagram on the side shows two long, Straight, and parallel wires. Current of 3 A Are flowing through the wires in opposite ●P Directions. Determine the magnitude of 0,4 m The magnetic field induction at point P ! 0,5 m Solution : Electrical current I = 3 A Distance from P to wire 1, a₁ = 0,5 – 0,4 = 0,1 m Distance from P to wire 2, a₂ = 0,4 m i₁ B₁ B₂ i₂ ●

  8. Materi The magnitudes 0f B₁ and B₂ are calculated : B₁ = μ₀i B₂ = μ₀i 2π a₁ 2π a₂ = (4π x 10⁻⁷) (3) = (4π x 10⁻⁷) (3) (2π) (10⁻¹) (2π) (4 x 10⁻¹) = 6 x 10⁻⁶ T = 1,5 x 10⁻⁶ T The magnetic induction at P is the resultant of vectors B₁ and B₂. Since B₁ and B₂ are vectors in the same direction , then their resultant is the algebraic sum of their magnitudes Bp = B₁ + B₂ = (6 x 10⁻⁶) + (1,5 x 10⁻⁶) = 7,5 x 10⁻⁶ T Hence, the magnitude of magnetic induction at point P is 7,5 x 10⁻⁶ T

  9. Materi 1.2. InduksiMagnetikpadaSumbuKawatMelingkarBerarus Besarinduksimagnetikpadasumbukawatmelingkardapatdirumuskansebagai : i P● ʘ B a a) Bp = μ₀ I ; Di mana : a = jari – jari (m) 2a b) Untukkawatmelingkarberupakumparandengan N lilitan : Bp = Nμ₀i 2a ; N = jumlahlilitankawat

  10. Materi ContohSoal: Sebuahkumparanterdiridari 10 liitandenganjari – jari 20 cm, dialiriarussebesar 5 A. Tentukanlahinduksimagnetikdipusatlingkaran ! a Penyelesaian : Diketahui : a = 20 cm ●P = 2 x 10⁻¹ m i = 5 A Jawab : Bp = Nμ₀i 2a = (10) (4π x 10⁻⁷) (5) 2 (2 x 10⁻¹) = 5π x 10⁻⁵ T

  11. LatihanSoal • LatihanSoal : • 1. Sebuahkawatlurusvertikaldialiriarus 5 A kearahatas. Tentukanlahbesarinduksi magnet disebuahtitikberjarak 10 cm disebelahkanankawatitu ! • Sebuahkawatberaruslistrik 10 A terletakdisebelahkanankawattersebut. Jikabesarinduksi magnet yang dihasilkan 6,5 x 10-5 wb/m2, hitunglahjarakkawatterhadapkawat ! • A looped wire consist of 20 turns. The radius of the circle = 10 cm. For the magnetic induction at the center to be equal to 4π x 10⁻³ T, determine the electrical current strength which flows ! (μ₀ = 4π x 10⁻⁷ Wb/Am)

  12. UjiKompetensi Untukevaluasibelajarklik link dibawahini UjiKompetensi

  13. Referensi Sumber : 1. Fisika 3 SMA Kelas 12, Purwoko, Pendi (Yudhistira) 2. LKS Fisika (SIMPATI SMA) XII Semester 1 ( Grahadi) 3. Physics for Senior High School 1ᶳᵗ Semester , MarthenKanginan (Erlangga)

  14. Penyususun & Editor

  15. Penutup TerimaKasih SelamatBelajar Good Luck….!

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