Statistical Decision Making with Two Sample Inference for Different Population Scenarios
Explore various cases of statistical inference on mean and proportions for two populations with unknown and known variances. Learn hypothesis testing, t-tests, confidence intervals, and effective decision-making methods.
Statistical Decision Making with Two Sample Inference for Different Population Scenarios
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Ex: Drying time of primer has SD=8 min. 10 Samples of Primer1has x-bar1=121 min. and another 10 samples of Primer II has x-bar2=112 min. Is the primer 2 has effect to drying time. • H0: 1-2=0 H1:1-2>0 • n1=n2 1=2 • Z0=2.52 • P=1-(2.52)=0.0059 <0.05 • Then reject H0
H0: 1-2=0 H1:1-2≠0 • n1=n2=8 1=2 • T0=-0.35 • P=0.729 > 0.05 • Then accept H0 Two-Sample T-Test and CI: C5, C8 N Mean StDev SE Mean C5 8 92.26 2.39 0.84 C8 8 92.73 2.98 1.1 Difference = mu (C5) - mu (C8) Estimate for difference: -0.48 95% CI for difference: (-3.37, 2.42) T-Test of difference = 0 (vs not =): T-Value = -0.35 P-Value = 0.729 DF = 14 Both use Pooled StDev = 2.7009
H0: 1-2=0 H1:1-2≠0 • n1=n2=10 1 ≠ 2 • T0=-2.77 • P=0.016 < 0.05 • Then reject H0 Two-Sample T-Test and CI: Metro, Rural N Mean StDev SE Mean Metro 10 12.50 7.63 2.4 Rural 10 27.5 15.3 4.9 Difference = mu (Metro) - mu (Rural) Estimate for difference: -15.00 95% CI for difference: (-26.71, -3.29) T-Test of difference = 0 (vs not =): T-Value = -2.77 P-Value = 0.016 DF = 13
5-4 Paired t-test • A special case of the two-sample t-tests of Section 5-3 occurs when the observations on the two populations of interest are collected inpairs. • Each pair of observations, say (X1j, X2j), is taken under homogeneous conditions, but these conditions may change from one pair to another. • For example; The test procedure consists of analyzing the differences between hardness readings on each specimen.
H0: D=1-2=0 H1: D= 1-2≠0 • n1=n2=9 1 ≠ 2 • T0=6.08 • P=0.000 < 0.05 • Then reject H0 Paired T-Test and CI: Karlsruhe method, Lehigh method N Mean StDev SE Mean Karlsruhe method 9 1.3401 0.1460 0.0487 Lehigh method 9 1.0662 0.0494 0.0165 Difference 9 0.2739 0.1351 0.0450 95% CI for mean difference: (0.1700, 0.3777) T-Test of mean difference = 0 (vs not = 0): T-Value = 6.08 P-Value = 0.000
H0: p1=p2 H1: p1≠p2 • Z0=5.36 • P=0.000 < 0.05 • Then reject H0 Test and CI for Two Proportions Sample X N Sample p 1 253 300 0.843333 196 300 0.653333 Difference = p (1) - p (2) Estimate for difference: 0.19 95% CI for difference: (0.122236, 0.257764) Test for difference = 0 (vs not = 0): Z = 5.36 P-Value = 0.000