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2-4. Writing Linear Functions. Warm Up. Lesson Presentation. Lesson Quiz. Holt McDougal Algebra 2. Holt Algebra 2. 3 4. x =. Warm Up Write each function in slope-intercept form. 1. 4 x + y = 8 2. – y = 3 x 3. 2 y = 10 – 6 x

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  1. 2-4 Writing Linear Functions Warm Up Lesson Presentation Lesson Quiz Holt McDougal Algebra 2 Holt Algebra 2

  2. 3 4 x = Warm Up Write each function in slope-intercept form. 1. 4x + y = 8 2. –y = 3x 3. 2y = 10 – 6x Determine whether each line is vertical or horizontal. 4. 5. y = 0 y = –4x + 8 y = –3x y = –3x + 5 vertical horizontal

  3. Objectives Use slope-intercept form and point-slope form to write linear functions. Write linear functions to solve problems.

  4. Vocabulary Point-slope form

  5. Recall from Lesson 2-3 that the slope-intercept form of a linear equation is y=mx + b, where m is the slope of the line and b is its y-intercept. In Lesson 2-3, you graphed lines when you were given the slope and y-intercept. In this lesson you will write linear functions when you are given graphs of lines or problems that can be modeled with a linear function.

  6. Example 1: Writing the Slope-Intercept Form of the Equation of a Line Write the equation of the graphed line in slope-intercept form. Identify the y-intercept. The y-intercept b is 1. Step 1

  7. 3 4 –4 –3 3 4 Slope is = = – . rise run –3 4 Example 1 Continued Step 2 Find the slope. Choose any two convenient points on the line, such as (0, 1) and (4, –2). Count from (0, 1) to (4, –2) to find the rise and the run. The rise is –3 units and the run is 4 units.

  8. m = – and b = 1. 3 4 The equation of the line is y = – x + 1. y = –x + 1 3 4 3 4 Example 1 Continued Write the equation in slope-intercept form. Step 3 y = mx + b

  9. Check It Out! Example 1 Write the equation of the graphed line in slope-intercept form. Identify the y-intercept. The y-intercept b is 3. Step 1

  10. 3 4 4 3 3 4 Slope is = . rise run Check It Out! Example 1 Continued Step 2 Find the slope. Choose any two convenient points on the line, such as (–4, 0) and (0, 3). Count from (–4, 0) to (0, 3) to find the rise and the run. The rise is 3 units and the run is 4 units 3

  11. m = and b = 3. 3 4 The equation of the line is y = x + 3. y = x + 3 3 4 3 4 Check It Out! Example 1 Continued Write the equation in slope-intercept form. Step 3 y = mx + b

  12. Notice that for two points on a line, the rise is the differences in the y-coordinates, and the run is the differences in the x-coordinates. Using this information, we can define the slope of a line by using a formula.

  13. 5 Helpful Hint 3 If you reverse the order of the points in Example 2B, the slope is still the same. m = = 6– 16 – 10 = 5– 11 – 6

  14. Example 2A: Finding the Slope of a Line Given Two or More Points Find the slope of the line through (–1, 1) and (2, –5). Let (x1, y1) be (–1, 1) and (x2, y2) be (2, –5). Use the slope formula. The slope of the line is –2.

  15. 3 4 The slope of the line is . Example 2B: Finding the Slope of a Line Given Two or More Points Find the slope of the line. Choose any two points. Let (x1, y1) be (4, 2) and (x2, y2) be (8, 5). Use the slope formula.

  16. Example 2C: Finding the Slope of a Line Given Two or More Points Find the slope of the line shown. Let (x1, y1) be (0,–2) and (x2, y2) be (1, –2). The slope of the line is 0.

  17. Check It Out! Example 2A Find the slope of the line. Let (x1, y1) be (–4, –1) and (x2, y2) be (–2, 1). Choose any two points. Use the slope formula. The slope of the line is 1.

  18. Check It Out! Example 2B Find the slope of the line through (2,–5) and (–3, –5). Let (x1, y1) be (2, –5) and (x2, y2) be (–3, –5). Use the slope formula. The slope of the line is 0.

  19. Because the slope of line is constant, it is possible to use any point on a line and the slope of the line to write an equation of the line in point-slope form.

  20. Example 3: Writing Equations of Lines In slope-intercept form, write the equation of the line that contains the points in the table. First, find the slope. Let (x1, y1) be (–8, –5) and (x2, y2) be (8, 1). Next, choose a point, and use either form of the equation of a line.

  21. Example 3 Continued Method A Point-Slope Form Rewrite in slope-intercept form. Using (8, 1): y – y1= m(x – x1) Distribute. Substitute. Solve for y. Simplify.

  22. The equation of the line is . Example 3 Continued Method B Slope-intercept Form Using (8, 1), solve for b. Rewrite the equation using m and b. y= mx+ b y = mx + b Substitute. 1 = 3 + b Simplify. b = –2 Solve for b.

  23. Check It Out! Example 3a Write the equation of the line in slope-intercept form with slope –5 through (1, 3). Method A Point-Slope Form y – y1= m(x – x1) y – (3)= –5(x – 1) Substitute. y – 3 = –5(x – 1) Simplify. Rewrite in slope-intercept form. y – 3 = –5(x – 1) y – 3 = –5x + 5 Distribute. The equation of the slope is y = –5x + 8. y = –5x + 8 Solve for y.

  24. Check It Out! Example 3b Write the equation of the line in slope-intercept form through (–2, –3) and (2, 5). First, find the slope. Let (x1, y1) be (–2,–3) and (x2, y2) be (2, 5). Method B Slope-Intercept Form y= mx+ b Rewrite the equation using m and b. 5= (2)2+ b 5 = 4 + b y =2x+ 1 y = mx + b 1 = b The equation of the line is y = 2x + 1.

  25. Example 4A: Entertainment Application The table shows the rents and selling prices of properties from a game. Express the rent as a function of the selling price. Let x = selling price and y = rent. Find the slope by choosing two points. Let (x1, y1) be (75, 9)and (x2, y2) be (90, 12).

  26. Example 4A Continued To find the equation for the rent function, use point-slope form. y – y1= m(x – x1) Use the data in the first row of the table. Simplify.

  27. Example 4B: Entertainment Application Graph the relationship between the selling price and the rent. How much is the rent for a property with a selling price of $230? To find the rent for a property, use the graph or substitute its selling price of $230 into the function. Substitute. y = 46 – 6 y = 40 The rent for the property is $40.

  28. Check It Out! Example 4a Express the cost as a linear function of the number of items. Let x = items and y = cost. Find the slope by choosing two points. Let (x1, y1) be (4, 14) and (x2, y2) be (7, 21.50).

  29. Check It Out! Example 4a Continued To find the equation for the number of items, use point-slope form. y – y1= m(x – x1) Use the data in the first row of the table. y – 14 = 2.5(x – 4) y = 2.5x + 4 Simplify.

  30. Check It Out! Example 4b Graph the relationship between the number of items and the cost. Find the cost of 18 items. To find the cost, use the graph or substitute the number of items into the function. y = 2.5(18) + 4 Substitute. y = 45 + 4 y = 49 The cost for 18 items is $49.

  31. By comparing slopes, you can determine if the lines are parallel or perpendicular. You can also write equations of lines that meet certain criteria.

  32. Example 5A: Writing Equations of Parallel and Perpendicular Lines Write the equation of the line in slope-intercept form. parallel toy = 1.8x + 3 and through (5, 2) m = 1.8 Parallel lines have equal slopes. Use y – y1 = m(x – x1) with (x1, y1) = (5, 2). y –2 = 1.8(x – 5) y –2 = 1.8x – 9 Distributive property. y= 1.8x – 7 Simplify.

  33. The slope of the given line is , so the slope of the perpendicular line is the opposite reciprocal, . Example 5B: Writing Equations of Parallel and Perpendicular Lines Write the equation of the line in slope-intercept form. perpendicular toand through (9, –2) Use y – y1 = m(x – x1). y + 2 is equivalent to y – (–2). Distributive property. Simplify.

  34. Check It Out! Example 5a Write the equation of the line in slope-intercept form. parallel to y = 5x – 3 and through (1, 4) m = 5 Parallel lines have equal slopes. Use y – y1 = m(x – x1) with (x1, y1) = (5, 2). y –4 = 5(x – 1) y – 4 = 5x – 5 Distributive property. y= 5x – 1 Simplify.

  35. The slope of the given line is , so the slope of the perpendicular line is the opposite reciprocal, . Example 5B: Writing Equations of Parallel and Perpendicular Lines Write the equation of the line in slope-intercept form. perpendicular toand through (9, –2) Use y – y1 = m(x – x1). y + 2 is equivalent to y – (–2). Distributive property. Simplify.

  36. The slope of the given line is , so the slope of the perpendicular, line is the opposite reciprocal . Check It Out! Example 5b Write the equation of the line in slope-intercept form. perpendicular toand through (0, –2) Use y – y1 = m(x – x1). y + 2 is equivalent to y – (–2). Distributive property. Simplify.

  37. Write the equation of each line in slope-intercept form. 1. 2. parallel to y = 0.5x + 2 and through (6, 1) 3. perpendicular to and through (4, 4) Lesson Quiz: Part I y = –2x –1 y = 0.5x – 2

  38. Lesson Quiz: Part II 4. Express the catering cost as a function of the number of people. Find the cost of catering a meal for 24 people. f(x) = 12x + 50; $338

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