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Calculus Date: 3/7/2014 ID Check Obj: SWBAT connect Differential and Integral Calculus PowerPoint Presentation
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Calculus Date: 3/7/2014 ID Check Obj: SWBAT connect Differential and Integral Calculus

Calculus Date: 3/7/2014 ID Check Obj: SWBAT connect Differential and Integral Calculus

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Calculus Date: 3/7/2014 ID Check Obj: SWBAT connect Differential and Integral Calculus

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  1. Calculus Date: 3/7/2014 ID Check Obj: SWBAT connect Differential and Integral Calculus Do Now: pg 307 #37 B #23 HW Requests: SM pg 156; pg 295 #11-17 odds, 31-35 odds SM 162 In class pg 316 #2, 8, 14, 18 group 319 #1-4 HW: Read pg 305 Ex 8 Read pg 314 Error Analysis pg 316 #1-9 odds, 13-19 odds Announcements: Saturday Tutoring 11-1 (Derivatives) Mock AP Exam during ACT Testing “There is something in every one of you that waits and listens for the sound of the genuine in yourself. It is the only true guide you will ever have. And if you cannot hear it, you will all of your life spend your days on the ends of strings that somebody else pulls.” ― Howard Thurman Maximize Academic Potential Turn UP! MAP

  2. Trapezoidal Rule To approximate , use T = (y0 + 2y1 + 2y2 + …. 2yn-1 + yn) where [a,b] is partitioned into n subintervals of equal length h = (b-a)/n.

  3. Trapezoidal Rule To approximate , use T = (y0 + 2y1 + 2y2 + …. 2yn-1 + yn) where [a,b] is partitioned into n subintervals of equal length h = (b-a)/n. Equivalently, T = LRAMn + RRAMn 2 where LRAMn and RRAMn are the Riemann sums using the left and right endpoints, respectively, for f for the partition.

  4. Using the trapezoidal rule Use the trapezoidal rule with n = 4 to estimate h = (2-1)/4 or ¼, so T = 1/8( 1+2(25/16)+2(36/16)+2(49/16)+4) = 75/32 or about 2.344

  5. EX 2: Trapezoidal Rule T = (y0 + 2y1 + 2y2 + …. 2yn-1 + yn) where [a,b] is partitioned into n subintervals of equal length h = (b-a)/n. T = (y0 + 2y1 + 2y2 + 2y3 + y4) T = ¼ (0 + 2(.25) + 2(1) + 2(2.25) + 4) = 11/4

  6. Simpson’ Rule To approximate , use S = (y0 + 4y1 + 2y2 + 4y3…. 2yn-2 +4yn-1 + yn) where [a,b] is partitioned into an evennumber n subintervals of equal length h =(b –a)/n. Simpson’s Rule assumes that a figure with a parabolic arc is used to compute the area

  7. Using Simpson’s Rule Use Simpson’s rule with n = 4 to estimate h = (2 – 1)/4 = ¼, so S = 1/12 (1 + 4(25/16) + 2(36/16) + 4(49/16) + 4) = 7/3

  8. EX 2: Simpson’s Rule

  9. The Definite Integral

  10. When we find the area under a curve by adding rectangles, the answer is called a Rieman sum. The width of a rectangle is called a subinterval. The entire interval is called the partition. subinterval partition Subintervals do not all have to be the same size.

  11. If the partition is denoted by P, then the length of the longest subinterval is called the norm of P and is denoted by . As gets smaller, the approximation for the area gets better. subinterval partition if P is a partition of the interval

  12. is called the definite integral of over . If we use subintervals of equal length, then the length of a subinterval is: The definite integral is then given by:

  13. Leibnitz introduced a simpler notation for the definite integral: Note that the very small change in x becomes dx.

  14. It is called a dummy variable because the answer does not depend on the variable chosen. upper limit of integration Integration Symbol integrand variable of integration (dummy variable) lower limit of integration

  15. We have the notation for integration, but we still need to learn how to evaluate the integral.

  16. velocity time In section 6.1, we considered an object moving at a constant rate of 3 ft/sec. Since rate . time = distance: If we draw a graph of the velocity, the distance that the object travels is equal to the area under the line. After 4 seconds, the object has gone 12 feet.

  17. If the velocity varies: Distance: (C=0 since s=0 at t=0) After 4 seconds: The distance is still equal to the area under the curve! Notice that the area is a trapezoid.

  18. What if: We could split the area under the curve into a lot of thin trapezoids, and each trapezoid would behave like the large one in the previous example. It seems reasonable that the distance will equal the area under the curve.

  19. The area under the curve We can use anti-derivatives to find the area under a curve!

  20. Riemann Sums • Sigma notation enables us to express a large sum in compact form

  21. Calculus Date: 2/18/2014 ID Check Objective: SWBAT apply properties of the definite integral Do Now: Set up two related rates problems from the HW Worksheet 6, 10 HW Requests: pg 276 #23, 25, 26, Turn in #28 E.C In class: Finish Sigma notation Continue Definite Integrals HW:pg 286 #1,3,5,9, 13, 15, 17, 19, 21, Announcements: “There is something in every one of you that waits and listens for the sound of the genuine in yourself. It is the only true guide you will ever have. And if you cannot hear it, you will all of your life spend your days on the ends of strings that somebody else pulls.” ― Howard Thurman Turn UP! MAP Maximize Academic Potential

  22. When we find the area under a curve by adding rectangles, the answer is called a Rieman sum. The width of a rectangle is called a subinterval. The entire interval is called the partition. subinterval partition Subintervals do not all have to be the same size.

  23. The width of a rectangle is called a subinterval. The entire interval is called the partition. Let’s divide partition into 8 subintervals. subinterval partition Pg 274 #9 Write this as a Riemann sum. 6 subintervals

  24. If the partition is denoted by P, then the length of the longest subinterval is called the norm of P and is denoted by . As gets smaller, the approximation for the area gets better. subinterval partition if P is a partition of the interval

  25. is called the definite integral of over . If we use subintervals of equal length, then the length of a subinterval is: The definite integral is then given by:

  26. Leibnitz introduced a simpler notation for the definite integral: Note that the very small change in x becomes dx. Note as n gets larger and larger the definite integral approaches the actual value of the area.

  27. It is called a dummy variable because the answer does not depend on the variable chosen. upper limit of integration Integration Symbol integrand variable of integration (dummy variable) lower limit of integration

  28. Calculus Date: 2/19/2014 ID Check Objective: SWBAT apply properties of the definite integral Do Now: Bell Ringer Quiz HW Requests: pg 276 #25, 26, pg 286 1-15 odds In class: pg 276 #23, 28 Continue Definite Integrals HW:pg 286 #17-35 odds Announcements: “There is something in every one of you that waits and listens for the sound of the genuine in yourself. It is the only true guide you will ever have. And if you cannot hear it, you will all of your life spend your days on the ends of strings that somebody else pulls.” ― Howard Thurman Turn UP! MAP Maximize Academic Potential

  29. Bell Ringer Quiz (10 minutes)

  30. Riemann Sums • LRAM, MRAM,and RRAM are examples of Riemann sums • Sn = This sum, which depends on the partition P and the choice of the numbers ck,is a Riemann sum for f on the interval [a,b]

  31. Definite Integral as a Limit of Riemann Sums Let f be a function defined on a closed interval [a,b]. For any partition P of [a,b], let the numbers ck be chosen arbitrarily in the subintervals [xk-1,xk]. If there exists a number I such that no matter how P and the ck’s are chosen, then f is integrable on [a,b] and I is the definite integral of f over [a,b].

  32. Definite Integral of a continuous function on [a,b] Let f be continuous on [a,b], and let [a,b] be partitioned into n subintervals of equal length Δx = (b-a)/n. Then the definite integral of f over [a,b] is given by where each ck is chosen arbitrarily in the kth subinterval.

  33. Definite integral This is read as “the integral from a to b of f of x dee x” or sometimes as “the integral from a to b of f of x with respect to x.”

  34. Using Definite integral notation The function being integrated is f(x) = 3x2 – 2x + 5 over the interval [-1,3]

  35. Definition: Area under a curve If y = f(x) is nonnegative and integrable over a closed interval [a,b], then the area under the curve of y = f(x) from a to b is the integral of f from a to b, We can use integrals to calculate areas and we can use areas to calculate integrals.

  36. Nonpositive regions If the graph is nonpositive from a to b then

  37. Area of any integrable function = (area above the x-axis) – (area below x-axis)

  38. Turn UP! MAP Maximize Academic Potential

  39. Integral of a Constant If f(x) = c, where c is a constant, on the interval [a,b], then

  40. Evaluating Integrals using areas We can use integrals to calculate areas and we can use areas to calculate integrals. Using areas, evaluate the integrals: 1) 2)

  41. Evaluating Integrals using areas Evaluate using areas: 3) 4) (a<b)

  42. Evaluating integrals using areas Evaluate the discontinuous function: Since the function is discontinuous at x = 0, we must divide the areas into two pieces and find the sum of the areas = -1 + 2 = 1

  43. Integrals on a Calculator You can evaluate integrals numerically using the calculator. The book denotes this by using NINT. The calculator function fnInt is what you will use. = fnInt(xsinx,x,-1,2) is approx. 2.04

  44. Evaluate Integrals on calculator • Evaluate the following integrals numerically: • = approx. 3.14 • = approx. .89

  45. Rules for Definite Integrals • Order of Integration:

  46. Rules for Definite Integrals • Zero:

  47. Rules for Definite Integrals • Constant Multiple: Any number k k= -1