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CS4432: Database Systems II

CS4432: Database Systems II. Lecture #23 Concurrency Control. Professor Elke A. Rundensteiner. Chapter 9 Concurrency Control. T1 T2 … Tn. DB (consistency constraints). Concepts. Transaction : sequence of r i (x), w i (x) actions

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CS4432: Database Systems II

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  1. CS4432: Database Systems II Lecture #23 Concurrency Control Professor Elke A. Rundensteiner concurrency control

  2. Chapter 9 Concurrency Control T1 T2 … Tn DB (consistency constraints) concurrency control

  3. Concepts Transaction: sequence of ri(x), wi(x) actions Conflicting actions: read/write on same resource A. Schedule: represents chronological order in which actions are executed Serial schedule: no interleaving of trans/actions S1, S2 are conflict equivalentschedules if S1 transform into S2 by swaps on non-conflicting actions. A schedule is conflict serializable if it is conflict equivalent to some serial schedule. concurrency control

  4. For a given schedule: Sd=r1(A)w1(A)r2(A)w2(A) r2(B)w2(B)r1(B)w1(B) T1 T2 T2 T1 Record dependencies in Precedence Graph: T1 T2 If graph has cycles, Then schedule is not conflict serializable. concurrency control

  5. Theorem P(S1) acyclic  S1 conflict serializable concurrency control

  6. How to enforce serializable schedules? concurrency control

  7. How to enforce serializable schedules? Option 1: try all possible swaps of non-conflicting operation pairs to determine if the schedule can be turned into a serial one, I.e., if the schedule is ‘good’. concurrency control

  8. How to enforce serializable schedules? Option 2: run system, recording P(S); at end of day, check for P(S) cycles and declare if execution was good concurrency control

  9. How to enforce serializable schedules? Option 3: prevent P(S) cycles from occurring T1 T2 ….. Tn Scheduler DB concurrency control

  10. A locking protocol Two new actions: lock (exclusive): li (A) unlock: ui (A) T1 T2 lock table scheduler concurrency control

  11. Rule #1: Well-formed transactions Ti: … li(A) … pi(A) … ui(A) ... concurrency control

  12. Rule #2 Legal scheduler S = …….. li(A) ………... ui(A) ……... no lj(A) concurrency control

  13. Exercise: • What schedules are legal?What transactions are well-formed? S1 = l1(A)l1(B)r1(A)w1(B)l2(B)u1(A)u1(B) r2(B)w2(B)u2(B)l3(B)r3(B)u3(B) S2 = l1(A)r1(A)w1(B)u1(A)u1(B) l2(B)r2(B)w2(B)l3(B)r3(B)u3(B) S3 = l1(A)r1(A)u1(A)l1(B)w1(B)u1(B) l2(B)r2(B)w2(B)u2(B)l3(B)r3(B)u3(B) concurrency control

  14. Exercise: • What schedules are legal?What transactions are well-formed? S1 = l1(A)l1(B)r1(A)w1(B)l2(B)u1(A)u1(B) r2(B)w2(B)u2(B)l3(B)r3(B)u3(B) S2 = l1(A)r1(A)w1(B)u1(A)u1(B) l2(B)r2(B)w2(B)l3(B)r3(B)u3(B) S3 = l1(A)r1(A)u1(A)l1(B)w1(B)u1(B) l2(B)r2(B)w2(B)u2(B)l3(B)r3(B)u3(B) concurrency control

  15. Schedule F : Adding locking ??? T1 T2 l1(A);Read(A) A A+100;Write(A);u1(A) l2(A);Read(A) A Ax2;Write(A);u2(A) l2(B);Read(B) B Bx2;Write(B);u2(B) l1(B);Read(B) B B+100;Write(B);u1(B) concurrency control

  16. Schedule F A B T1 T2 25 25 l1(A);Read(A) A A+100;Write(A);u1(A) 125 l2(A);Read(A) A Ax2;Write(A);u2(A) 250 l2(B);Read(B) B Bx2;Write(B);u2(B) 50 l1(B);Read(B) B B+100;Write(B);u1(B) 150 250 150 concurrency control

  17. Rule #3 Two phase locking (2PL)for transactions Ti = ……. li(A) ………... ui(A) ……... no unlocks no locks concurrency control

  18. # locks held by Ti Time Growing Shrinking Phase Phase concurrency control

  19. Schedule F : Does it follow 2PL ? T1 T2 l1(A);Read(A) A A+100;Write(A);u1(A) l2(A);Read(A) A Ax2;Write(A);u2(A) l2(B);Read(B) B Bx2;Write(B);u2(B) l1(B);Read(B) B B+100;Write(B);u1(B) concurrency control

  20. Schedule G T1 T2 l1(A);Read(A) A A+100;Write(A) l1(B); u1(A) l2(A);Read(A) A Ax2;Write(A); concurrency control

  21. Schedule G T1 T2 l1(A);Read(A) A A+100;Write(A) l1(B); u1(A) l2(A);Read(A) A Ax2;Write(A);l2(B) delayed concurrency control

  22. Schedule G T1 T2 l1(A);Read(A) A A+100;Write(A) l1(B); u1(A) l2(A);Read(A) A Ax2;Write(A);l2(B) Read(B);B B+100 Write(B); u1(B) delayed concurrency control

  23. Schedule G T1 T2 l1(A);Read(A) A A+100;Write(A) l1(B); u1(A) l2(A);Read(A) A Ax2;Write(A);l2(B) Read(B);B B+100 Write(B); u1(B) l2(B); u2(A);Read(B) B Bx2;Write(B);u2(B); delayed concurrency control

  24. A B 25 25 125 250 125 250 250 250 We Got the GOOD Schedule !!!! T1 T2 Read(A); A  A+100 Write(A); Read(A);A  A2; Write(A); Read(B); B  B+100; Write(B); Read(B);B  B2; Write(B); concurrency control

  25. Schedule H (T2 reversed) T1 T2 l1(A); Read(A) l2(B);Read(B) A A+100;Write(A) B Bx2;Write(B) … … concurrency control

  26. Schedule H (T2 reversed) T1 T2 l1(A); Read(A) l2(B);Read(B) A A+100;Write(A) B Bx2;Write(B) l1(B) l2(A) delayed delayed concurrency control

  27. Assume deadlocked transactions are rolled back • They have no effect • They do not appear in schedule E.g., Schedule H = This space intentionally left blank! concurrency control

  28. We need to show 2PL Protocol “works”: Show that rules #1,2,3  conflict- serializable schedules concurrency control

  29. Conflict rules for li(A), ui(A): • li(A), lj(A) conflict • li(A), uj(A) conflict concurrency control

  30. Theorem Rules #1,2,3  conflict (2PL) serializable schedule To help in proof: Definition Shrink(Ti) = SH(Ti) = first unlock action of Ti concurrency control

  31. By rule 3: SH(Ti) SH(Tj) So, SH(Ti) <S SH(Tj) Proof of lemma: Ti  Tj means that S = … pi(A) … qj(A) …; p,q conflict By rules 1,2: S = … pi(A) … ui(A) … lj(A) ... qj(A) … Lemma Ti  Tj in S  SH(Ti) <S SH(Tj) concurrency control

  32. Theorem Rules #1,2,3  conflict (2PL) serializable schedule Proof: (1) Assume P(S) has cycle T1 T2 …. Tn T1 (2) By lemma: SH(T1) <SH(T2) < ... <SH(T1) (3) Impossible, so P(S) acyclic (4)  S is conflict serializable concurrency control

  33. Beyond this simple 2PL protocol, it is all a matter of improving performance and allowing more concurrency…. • Shared locks • Multiple granularity • Other types of C.C. mechanisms concurrency control

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