1 / 6

Special Right Triangles

Understand the principles of 30º-60º-90º & 45º-45º-90º triangles, solving for sides with given angles using x and ratios. Visual diagrams demonstrate the theorems in action. Learn how to find side lengths in these geometric configurations with ease.

ellie
Télécharger la présentation

Special Right Triangles

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Special Right Triangles Lesson 9.7

  2. 30º-60º-90º Triangles Theorem 72: In a triangle whose angles have the measures of 30º, 60º, and 90º, the lengths of the sides opposite these angles can be represented by x, , and 2x respectively. (30º-60º-90º-Triangle Theorem) 30º 2x 60º x

  3. Find BC and AC. • Place x, , and 2x on the diagram. • 2x = 10x = 5 • BC = 5 • AC = A 2x = 10 10 C 60º B x

  4. 45º-45º-90º Triangles Theorem 73:In a triangle whose angles have the measures of 45º, 45º, and 90º, the lengths of the sides opposite these angles can be represented by x, x, and , respectively. (45º-45º-90º-Triangle Theorem) x 45º x 45º

  5. MOPR is a square. Find MP. • The diagonal divides the square into two 45º-45º-90º triangles. • Place x, x, and on the corresponding parts of the triangle. • Since x = 9, • MP = R M 9 x = 9 O P x

  6. Find ST and TV. • Place x, x, and onto the diagram. T x S x 4 V 45º

More Related