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Unit 9- Stoichiometry. What is Stoichiometry?. Using chemical equations to make predictions about the quantities of reactants or products. Predicting a precipitate. Practice with precipitates (SOLID). H 2 SO 4 + BaCl 2 Ba SO 4(s) + HCl
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What is Stoichiometry? • Using chemical equations to make predictions about the quantities of reactants or products.
Practice with precipitates (SOLID) • H2SO4 + BaCl2 BaSO4(s)+ HCl • Al2(SO4)3 + NH4OH Al(OH) 3 + (NH4)2SO4 • Which is the precipitate or Solid formed??? • AgNO3 + H2S Ag2S + HNO3
A sandwich analogy… • Suppose you wanted to make turkey sandwiches. You use the following: 2 bread slices + 2 turkey slices + 1 cheese slice 1 sandwich If you have 10 slices of bread, how many sandwiches could you make? If you had unlimited bread, 8 slices of cheese and 14 slices of turkey, how many could you make?
We do the same with chemical reactions!!! • N2 (g)+ 3H2 (g) 2NH3 (g) What does this mean?
Calculations • Mole – Mole Calculations: • Coefficients from the balanced chemical equation are used to write conversion factors called mole to mole ratios. • With these ratios you can relate moles of to one compound to moles of another compound.
Mole to mole ratio • Mole Ratios for Ammonia: • N2 + 3H2 2NH3 • 1 mol N2 – 3 mol H2 • 2 mol NH3 – 1 mol N2 • 3 mol H2 – 2 mol NH3
Practice • Using the following equation – give the mole ratio of oxygen gas to water. • 2H2S + 3O2 2SO2 + 2 H2O • Answer: 3 mole O2 / 2 mol H2O
Moles of Product • How many moles of ammonia are produced when 0.60 mol of nitrogen reacts with hydrogen? • N2 + 3H2 2NH3 • Known: moles of nitrogen = 0.60 mol of N2 • Unknown: moles of ammonia?
Answer: • 0.60 mol N2 x 2 mol NH3 = 1.2 mol NH3 1 mol N2
Practice Problem • 4 Al + 3O2 2Al2O3 • How many moles of aluminum are needed to form 3.7 mol Al2O3? • Known: Mole of Al2O3 • Unknown: mole of Al
Answer • 3.7 mol Al2O3 X 4 mole Al = 7.4 mol Al 2 mol Al2O3
Gram to mole • How many moles of ammonia can be produced from 15g of N2? What we know… Molar mass of N2 is 28.02 g/mol We are given: 15 g of N2 We need to find: moles of NH3
How to solve gram to mole… Start with the balanced chemical equation: 3 H2 + N2 2 NH3 15g N2 1mol N2 2 mol NH3 28.02 g N2 1 mol N2 = 1.1 mol
Now try this one… H2 + Br2 2 HBr How many moles of HBr will be produced from 12.45 grams of H2?
Mass to Mass Calculations • Calculate the number of grams of NH3 produced by the reaction of 5.40 g of H2 and excess nitrogen. The balanced equation is: N2 + 3H2 2NH3
Practice Known: 5.00 g of CaC2 Unknown: g of C2H2
Answer • 5.00 g CaC2 X 1 mol CaC2 X 1 mol C2H2 X 26.0 g C2H2 = 2.03 g C2H2 64.0 g CaC2 1 mol CaC2 1 mol C2H2
What is a limiting Reagent? • Reactant that limits the amount of product that is produced. • Why? – It runs out first.
Identify the limiting reagent… • When magnesium metal is dropped into hydrochloric acid, hydrogen gas and magnesium chloride are produced. If the magnesium is consumed, and HCl remains, what is the limiting reagent?
Reaction Yields • Theoretical Yield – maximum amount of product that could be formed from the amounts of reactants • Actual Yield – amount of product actually produced in the reaction • Often less than the theoretical yield
Percent Yield • Ratio of the actual yield to the theoretical yield • Measure of the efficiency of the reaction • Actual / theoretical yield x 100= percent yield!
Why is percent yield usually less than 100%? • Reaction doesn’t go to completion • Impurities in reactants • Product might be lost during experimental process