1 / 10

The Circle

Chapter 3 Conics. 3.3. The Circle. 3.3. 1. MATHPOWER TM 12, WESTERN EDITION. Developing the Standard Forms of the Equation of a Circle. Note:. The standard form of the equation of a circle with its centre at the origin (0, 0) is. 3.3. 2.

Télécharger la présentation

The Circle

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Chapter 3 Conics 3.3 The Circle 3.3.1 MATHPOWERTM 12, WESTERN EDITION

  2. Developing the Standard Forms of the Equation of a Circle Note: The standard form of the equation of a circle with its centre at the origin (0, 0) is 3.3.2

  3. Developing the Standard Forms of the Equation of a Circle This is the of the equation of a circle with the centre at 3.3.3

  4. Finding the Equation of a Circle Determine the equation of a circle with centre C(-5, 2) and passing through the point P(-8, 7). From the standard form: (x - h)2 + (y - k)2 = r2 Therefore, the equation of the circle in standard form is 3.3.4

  5. Writing the General Form of the Equation of a Circle The general form of the equation is Write the following equation in general form: (x + 5)2 + (y - 2)2 = 34 3.3.5

  6. Finding the Centre and the Radius Find the centre and the radius of each circle: 1.x2 + y2 - 8x + 10y - 14 = 0 To find the centre and radius, write the equation in standard form. To do this, you must complete the square: x2 + y2 - 8x + 10y - 14 = 0 The centre is and the radius is 2.3x2 + 3y2 + 6x + 12y + 5 = 0 The centre is and the radius is 3.3.6

  7. Using a Graphing Calculator Graph: (x - 3)2 + (y - 4)2 = 16 Your calculator will only graph a function, therefore, you must write the equation in the form y = . Make sure that you use a ZSquare graphing window. You can also use the Draw circle command on your TI-83: Press [2nd][PRGM] 9 and enter the following: 3.3.7

  8. Using a Graphing Calculator Using your graphing calculator, graph the following equations: a) x2 + y2 = 16 b) 4x2 + y2 = 16 c) 0.5x2 + y2 = 16 d) Ax2 + y2 = 16, when A = 0 3.3.8

  9. Using a Graphing Calculator [cont’d] Using your graphing calculator, graph the following equations: d) x2 + 4y2 = 16 e) x2 + 0.5y2 = 16 f) x2 + Cy2 = 16, when C = 0 3.3.9

  10. Assignment Suggested Questions: Pages 141 and 142 A 1-25 odd, 27-32 B 36-45, 49, 50, 51, 54, 56, 58 (graph), 62 3.3.11

More Related