1 / 14

Electric Potential

Electric Potential. Gravitational Potential. gravitational potential energy (work) per unit of mass. high PE. low PE. + + + + + +. - - - - - -. q. +. gain in KE = loss of PE. PE depends on charge q. Electric potential = potential energy (work) per unit of charge.

eyad
Télécharger la présentation

Electric Potential

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Electric Potential

  2. Gravitational Potential gravitational potential energy (work) per unit of mass

  3. high PE low PE + + + + + + - - - - - - q + gain in KE = loss of PE PE depends on charge q

  4. Electric potential = potential energy (work) per unit of charge V = UE/q = volts J/C units: only differences of potential (voltages) are measurable

  5. If define V = 0 @ infinity, then can designate V at a point Work to move a charge (q) from infinity (a great distance) to a given point: W = UE = qV

  6. 5000 V - - - + + + e- electron accelerated through 5000 V -8.01 x 10-16 J ΔPE: speed: 4.20 x 107 m/s

  7. Energy Units S.I. unit: Joule UE = qV 1 J = (1 C) ( 1 V) electron volt (eV): charge of 1 e- across a potential difference of 1 V 1 eV = (1 e-) (1 V)

  8. 1 eV = (1.602 x 10-19 C) (1 V) = 1.602 x 10-19 J 5000 V - - - + + + 2e- energy = 10 000 eV

  9. Q KE: QV - - - + + + m v: √(2QV/m) V 2Q KE: 2QV 2m v: √(2QV/m)

  10. Uniform Electric Field Field strength (+force) is constant

  11. Relationship between V and E for a Uniform Electric Field (between charged plates) W = Fd F = Eq qV W = UE = E = V/d qV = Eqd V/m units: N/C =

  12. E = V/d V = V2 – V1 V2 L ·P r V1 Electric field @ P? Electric potential @ P?

  13. Electric Potential around a Point Charge +Q r X V = kQ/r UE = Vq = kQq/r

  14. If more than 1 point charge: find V for each (include sign) and then find algebraic sum V = k Σi (qi/ri)

More Related