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Ambiguity in Language Processing

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Learn about the challenges of ambiguity in natural language processing, parsing sentences and resolving ambiguities effectively. Explore solutions to address combinatorial explosions of ambiguity.

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Ambiguity in Language Processing

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  1. Probabilistic CKY 600.465 - Intro to NLP - J. Eisner

  2. Our bane: Ambiguity • John saw Mary • Typhoid Mary • Phillips screwdriver Mary note how rare rules interact • I see a bird • is this 4 nouns – parsed like “city park scavenger bird”? rare parts of speech, plus systematic ambiguity in noun sequences • Time flies like an arrow • Fruit flies like a banana • Time reactions like this one • Time reactions like a chemist • or is it just an NP? 600.465 - Intro to NLP - J. Eisner

  3. Our bane: Ambiguity • John saw Mary • Typhoid Mary • Phillips screwdriver Mary note how rare rules interact • I see a bird • is this 4 nouns – parsed like “city park scavenger bird”? rare parts of speech, plus systematic ambiguity in noun sequences • Time | flies like an arrow NP VP • Fruit flies | like a banana NP VP • Time | reactions like this one V[stem] NP • Time reactions | like a chemist S PP • or is it just an NP? 600.465 - Intro to NLP - J. Eisner

  4. How to solve this combinatorial explosion of ambiguity? • First try parsing without any weird rules, throwing them in only if needed. • Better: every rule has a weight. A tree’s weight is total weight of all its rules. Pick the overall lightest parse of sentence. • Can we pick the weights automatically?We’ll get to this later … 600.465 - Intro to NLP - J. Eisner

  5. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  6. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  7. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  8. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  9. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  10. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  11. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  12. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  13. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  14. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  15. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  16. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  17. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  18. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  19. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  20. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  21. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  22. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  23. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  24. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  25. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  26. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  27. 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  28. S Follow backpointers … 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  29. S NP VP 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  30. S NP VP PP VP 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  31. S NP VP PP VP P NP 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  32. S NP VP PP VP P NP Det N 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  33. Which entries do we need? 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  34. Which entries do we need? 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  35. Not worth keeping … 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  36. … since it just breeds worse options 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  37. Keep only best-in-class! inferior stock 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  38. Keep only best-in-class! (and backpointers so you can recover parse) 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  39. Probabilistic Trees • Instead of lightest weight tree, take highest probability tree • Given any tree, your assignment 1 generator would have some probability of producing it! • Just like using n-grams to choose among strings … • What is the probability of this tree? S NP time VP PP VP flies P like NP Det an N arrow 600.465 - Intro to NLP - J. Eisner

  40. Probabilistic Trees • Instead of lightest weight tree, take highest probability tree • Given any tree, your assignment 1 generator would have some probability of producing it! • Just like using n-grams to choose among strings … • What is the probability of this tree? • You rolled a lot of independent dice … S NP time VP | S) p( PP VP flies P like NP Det an N arrow 600.465 - Intro to NLP - J. Eisner

  41. Chain rule: One word at a time p(time flies like an arrow) = p(time) * p(flies | time) * p(like | time flies) * p(an | time flies like) * p(arrow | time flies like an) 600.465 - Intro to NLP - J. Eisner

  42. Chain rule + backoff (to get trigram model) p(time flies like an arrow) = p(time) * p(flies | time) * p(like | time flies) * p(an | time flies like) * p(arrow | time flies like an) 600.465 - Intro to NLP - J. Eisner

  43. Chain rule – written differently p(time flies like an arrow) = p(time) * p(time flies | time) * p(time flies like | time flies) * p(time flies like an | time flies like) * p(time flies like an arrow | time flies like an) Proof: p(x,y | x) = p(x | x) * p(y | x, x) = 1 * p(y | x) 600.465 - Intro to NLP - J. Eisner

  44. Chain rule + backoff p(time flies like an arrow) = p(time) * p(time flies | time) * p(time flies like | time flies) * p(time flies like an | time flies like) * p(time flies like an arrow | time flies like an) Proof: p(x,y | x) = p(x | x) * p(y | x, x) = 1 * p(y | x) 600.465 - Intro to NLP - J. Eisner

  45. Chain rule: One node at a time S S S S NP time VP | S) * p( | ) | S) = p( p( NP NP time VP VP NP VP PP VP flies P like NP S S * p( | ) Det an N arrow NP time NP time VP VP PP VP S S * p( | ) * … NP time NP time VP VP PP VP flies PP VP 600.465 - Intro to NLP - J. Eisner

  46. model you used in homework 1! (called “PCFG”) Chain rule + backoff S S S S NP time VP | S) * p( | ) | S) = p( p( NP NP time VP VP NP VP PP VP flies P like NP S S * p( | ) Det an N arrow NP time NP time VP VP PP VP S S * p( | ) * … NP time NP time VP VP PP VP flies PP VP 600.465 - Intro to NLP - J. Eisner

  47. model you used in homework 1! (called “PCFG”) Simplified notation S NP time VP | S) = p(S NP VP| S) * p(NP  flies| NP) p( PP VP flies P like NP * p(VP VP NP| VP) Det an N arrow * p(VP flies| VP) * … 600.465 - Intro to NLP - J. Eisner

  48. Already have a CKY alg for weights … S NP time VP | S) = w(S NP VP) + w(NP  flies| NP) w( PP VP flies P like NP + w(VP VP NP) Det an N arrow + w(VP flies) + … Just let w(X Y Z) = -log p(X Y Z| X) Then lightest tree has highest prob

  49. 2-8 2-2 multiply to get 2-22 2-12 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

  50. 2-8 2-2 multiply to get 2-22 2-12 Need only best-in-class to get best parse 2-13 1 S  NP VP 6 S  Vst NP 2 S  S PP 1 VP  V NP 2 VP  VP PP 1 NP  Det N 2 NP  NP PP 3 NP  NP NP 0 PP  P NP

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