1 / 14

Vector Calculations

Vector Calculations. A boat leaves a harbour and travels due north for a distance of 3km and then due west for a distance of 8km. What is the displacement of the boat with respect to the harbour?

grahamh
Télécharger la présentation

Vector Calculations

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Vector Calculations • A boat leaves a harbour and travels due north for a distance of 3km and then due west for a distance of 8km. What is the displacement of the boat with respect to the harbour? • A helicopter rise vertically from the ground for a distance of 600m and then moves horizontally for a distance of 1.6km. What is the displacement of the helicopter from its starting position? ‘Tough Guy’ Question 4. After take off an aircraft climbs at a rate of 150m/s at an angle of 30° to the ground. What are the magnitudes of the horizontal and vertical components of its velocity

  2. Equations of motion

  3. Starter 1. Put the following in order of average speed (slowest first) 2. Estimate the average speed for each of the above (in mph) 3. What is the difference between speed and velocity?

  4. Starter (answers) Average speeds: Snail = 0.03mph Car =70mph Cheetah = 70mph Tennis serve = 100mph Bullet = 1000mph Speed is a scalar quantity. Speed = distance ÷ time Velocity is a vector quantity. Velocity = displacement ÷ time

  5. Learning Objectives • Recognise that speed can change during a journey • Be able to calculate average speed • Be able to use the following equations: v = u + at s =(u + v) t 2 v2 = u2 + 2as s = ut + ½at2

  6. Success criteria • Use the equations of motion directly to find required values. (Grade C) • Rearrange the equations of motion to find required values. (Grade A)

  7. How do we calculate (average) speed? Speed = distance time • This basic equation means we can only • solve a limited amount of problems.

  8. So we need something a little more complex... Click for video The BugattiVeyron goes from 0-200mph (or 89m/s) in 24.2 seconds. How many metres does it travel in this time? We can’t use speed=distance/time because the car was accelerating.

  9. These are the 4 equations of motion you must be able to use: v = u + at s =(u + v)t 2 v2 = u2 + 2as s = ut + ½at2 What does each letter mean? Take care: all units of distance and time must match. If they don’t, you must convert them.

  10. Back to the Bugatti question... The BugattiVeyron goes from 0-200mph (or 89ms-1) in 24.2 seconds. How many metres does it travel in this time? Which equation should we use? v = u + at s =(u + v)t 2 v2 = u2 + 2as s = ut + ½at2

  11. The BugattiVeyron goes from 0-200mph (or 89ms-1) in 24.2 seconds. How many metres does it travel in this time? • Using s =(u + v)t 2 • s = ? • u = 0ms-1 • v = 89ms-1 • t = 24.2s s = (0 + 89)x24.2 2 s = 1076.9m

  12. Higher level • For the higher paper you will be expected to rearrange the equations of motion. • For example.....

  13. Question: A skateboarder goes from standstill to 6m/s in 3 seconds. What is her acceleration? v = 6, u = 0, a = ?, t = 3 Using v = u + at 6 = 0 + (a x 3) 6 = 3a 6 = a 3 a = 2ms-2

  14. Equations of motion The best way to learn how to do these is practice!! Question sheet P5b5 - old course

More Related