1 / 45

BRAVAIS LATTICE

BRAVAIS LATTICE. BL describes the periodic nature of the atomic arrangements (units) in a X’l. X’l structure is obtained when we attach a unit to every lattice point and repeat in space Unit – Single atoms (metals) / group of atoms (NaCl) [BASIS]. Lattice + Basis = X’l structure.

gyan
Télécharger la présentation

BRAVAIS LATTICE

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. BRAVAIS LATTICE BL describes the periodic nature of the atomic arrangements (units) in a X’l. X’l structure is obtained when we attach a unit to every lattice point and repeat in space Unit – Single atoms (metals) / group of atoms (NaCl) [BASIS] Lattice + Basis = X’l structure Infinite array of discrete points arranged (and oriented) in such a way that it looks exactly the same from whichever point the array is looked at.

  2. R Q P 2-D honey comb net Not a BL Lattice arrangement looks the same from P and R, bur rotated through 180º when viewed from Q

  3. Primitive Translation Vectors If the lattice is a BL, then it is possible to find a set of 3 vectors a, b, c such that any point on the BL can be reached by a translation vector R = n1a + n2b + n3c where a, b, c are PTV and ni’s are integers eg: 2D lattice (B) (A) (C) a2 a2 a2 a1 a1 a2 a1 (D) a1 (A), (B), (C) define PTV, but (D) is not PTV

  4. 3-D Bravais Lattices (a) Simple Cube k PTV : a3 a2 a j a1 i

  5. Face centered cubic C2 PTV B F5 F4 F2 F3 F1 a2 A C1 a3 F6 a1 For Cube B, C1&C2 are Face centers; also F2&F3 All atoms are either corner points or face centers and are EQUIVALENT

  6. PTV (-1,-1,3) (-1,-1,2) (-1,0,2) (0,0,2) (0,-1,2) a3 (0,0,1) (0,1,1) a2 (0,0,0) (0,1,0) a1 (1,1,0) (1,2,0) (1,0,0)

  7. Alternate choice of PTV a2 a3 a1

  8. Only 2-fold symmetry 2 Oblique Lattice : a ≠ b, α ≠ 90

  9. Rectangular Lattice : a ≠ b, α = 90

  10. 2 Rectangular Lattice : a ≠ b, α = 90 : Symmetry operations b a mirror

  11. Hexagonal Lattice : a = b, α = 120 b a

  12. PUC and Unit cell for BCC Unit Cell Primitive Unit Cell

  13. Body-centered cubic: 2 sc lattices displaced by (a/2,a/2,a/2) A is the body center B PUC A B is the body center All points have identical surrounding

  14. PUC and Unit cell for FCC PUC Unit Cell

  15. PUC and Unit cell for FCC : alternate PTV

  16. P I P I F P I C F P (Trigonal) P P C P 7 X’l Systems 14 BL

  17. c b a

  18. a2 60º a1 A lattice which is not a BL can be made into a BL by a proper choice of 2D lattice and a suitable BASIS 2-D Lattice B A The original lattice which is not a BL can be made into a BL by selecting the 2D oblique lattice (blue color) and a 2-point BASIS A-B

  19. BCC Structure

  20. FCC Structure

  21. NaCl Structure

  22. Diamond Structure

  23. No. of atoms/unit cell = 8 Corners – 1 Face centers – 3 Inside the cube – 4 (¾, ¼, ¾) (¼, ¾, ¾) (¾, ¾,¼) z (¼, ¼,¼) y x (0,0,0) DiamondStructure

  24. Hexagonal Close Packed (HCP) Structure

  25. HCP = HL (BL) + 2 point BASIS at (000) and (2/3,1/3,1/2)

  26. The Simple Hexagonal Lattice

  27. The HCP Crystal Structure

  28. 4-circle Diffractometer

  29. Reciprocal Lattice (000)

  30. (201) plane k = k´- k = G201 k´ k θ201 2π/λ Incident beam (102) (002) (302) (202) (301) (201) (101) (001) (300) (200) (100) (000) (00 -1) (30 -1)

  31. a* (-200) (000) (200) b* 2π/λ Incident beam Rotaion = 0º

  32. (-200) (000) (200) a* 2π/λ b* Rotaion = 5º

  33. a* (-200) (000) (200) b* Rotaion = 10º

  34. a* (-200) (000) (200) 2π/λ b* Rotaion = 20º

  35. (-200) (000) (200) 2π/λ 2π/λ Incident beam Incident beam Rotaion = 5º Rotaion = 20º a* b*

  36. Schematic diagram of a four-circle diffractometer.

  37. Scattering Intensities and Systematic Absence I 2θ

  38. Diffraction Intensities • Scattering by electrons • Scattering by atoms • Scattering by a unit cell • Structure factors • Powder diffraction intensity calculations • – Multiplicity • – Lorentz factor • – Absorption, Debye-Scherrer and Bragg Brentano • – Temperature factor

  39. Scattering by atoms • We can consider an atom to be a collection of electrons. • This electron density scatters radiation according to the Thomson approach (classical Scattering). However, the radiation is coherent so we have to consider interference between x-rays scattered from different points within the atom • – This leads to a strong angle dependence of the scattering – FORM FACTOR.

  40. Form factor (Atomic Scattering Factor) • We express the scattering power of an atom using a form factor (f) • – Form factor is the ratio of scattering from the atom to what • would be observed from a single electron 30 29 Form factor is expressed as a function of (sinθ)/λ as the interference depends on both λ and the scattering angle Form factor is equivalent to the atomic number at low angles, but it drops rapidly at high (sinθ)/λ 20 fCu 10 0 0.6 1.0 0.8 0 0.2 0.4 sinθ/λ

  41. X-ray and neutron form factor The form factor is related to the scattering density distribution in an atoms - It is the Fourier transform of the scattering density - Neutrons are scattered by the nucleus not electrons and as the nucleus is very small, the neutron form factor shows no angular dependence NEUTRON b F- X-RAY 3He 7Li f C 1H Li+ sinθ/λ sinθ/λ

  42. (b) 1 3 3 2 2 (b) Scattering by a Unit Cell – Structure Factor The positions of the atoms in a unit cell determine the intensities of the reflections Consider diffraction from (001) planes in (a) and (b) If the path length between rays 1 and 2 differs by λ, the path length between rays 1 and 3 will differ by λ/2 and destructive interfe-rence in (b) will lead to no diffracted intensity c (a) b a 1 1 2 2 (a)

More Related