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Geotechnology Fundamental Theories of Rock and Soil Mechanics. Geotechnology. Theory of Rock and Soil Mechanics Stress 1. Concept. Stress = Pressure = ???. Geotechnology. Theory of Rock and Soil Mechanics Stress 1. Concept. Stress = Pressure = Force Area.
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GeotechnologyFundamental Theories of Rock and Soil Mechanics
Geotechnology • Theory of Rock and Soil Mechanics • Stress 1. Concept Stress = Pressure = ???
Geotechnology • Theory of Rock and Soil Mechanics • Stress 1. Concept Stress = Pressure = Force Area
Geotechnology • Theory of Rock and Soil Mechanics • Stress 1. Concept Stress = Pressure = Force Area versus
A. Stress 2. Primary Forces (natural)
A. Stress 2. Primary Forces (natural) a. Gravitational Forces (overlying materials and upslope activity)
A. Stress 2. Primary Forces (natural) b. Tectonic Forces “Important for Virginia and the Eastern Seaboard?”
A. Stress 2. Primary Forces (natural) c. Fluid Pressures (‘quick conditions’)
Geotechnology • Theory of Rock and Soil Mechanics • Stress 3. Secondary Forces (Human Induced)
Geotechnology 3. Secondary Forces (Human Induced) a. Excavation and Mining
Geotechnology 3. Secondary Forces (Human Induced) b. Loading
Geotechnology 3. Secondary Forces (Human Induced) c. Other * Blasting * Tunneling * Pumping of Fluids
4. Stress (σn ) on a plane normal to Force σn = Force / Area Where n = ‘normal’, or stress perpendicular To the cross sectional area
σ = Force / Area 5. Stress on an inclined plane to Force Where inclined area = A = An/cos Θ Θ = angle to normal
σ = Force / Area 5. Stress on an inclined plane to Force Where is 1)Normal Force and 2)Shear Force = ??
σ = Force / Area 5. Stress on an inclined plane to Force Where Normal Force and Shear Force = ?? cos Θ = a h sin Θ = o h
σ = Force / Area 5. Stress on an inclined plane to Force Where Normal Force and Shear Force = ?? cos Θ= a =Fn h = F sin Θ = o = Fs h=F
σ = Force / Area 5. Stress on an inclined plane to Force Where Normal Force and Shear Force = ?? cos Θ = a = Fn h = F sin Θ = o = Fs h = F Fn = F cos Θ Fs = F sin Θ
A reminder… Fn = F cos Θ Fs = F sin Θ A = An/cos Θ 5. Stress on an inclined plane to Force
A reminder… Fn = F cos Θ Fs = F sin Θ A = An/cos Θ 5. Stress on an inclined plane to Force Stress Normal = Force Normal / Area σn = {F cos Θ} / {An/cos Θ} Stress Shear = Force Shear / Area τ = {F sin Θ} / {An/cos Θ}
5. Limits: (max) σn when Θ = 0 (min) σn when Θ = 90 (max) τ when Θ = 45 (min) τ when Θ = 0 or 90
Example Problem Given: Force = 10 lbs, Area (normal) = 5 in2 Determine σn and τ when Θ = 0 °, Θ = 30°, Θ = 45°, and Θ = 60°
Example Problem Given: Force = 10 lbs, Area (normal) = 5 in2 Determine σn and τ when Θ = 0 °, and Θ = 30° σn = {F cos Θ} / {An/cos Θ} = (10 lbs * cos 0)/(5 in2/cos 0) = τ = {F sin Θ} / {An/cos Θ} = (10 lbs * sin 0)/(5 in2/cos 0) =
Example Problem Given: Force = 10 lbs, Area (normal) = 5 in2 Determine σn and τ when Θ = 0 °, and Θ = 30° σn = {F cos Θ} / {An/cos Θ} = (10 lbs * cos 0)/(5 in2/cos 0) = 2 lbs/in2 τ = {F sin Θ} / {An/cos Θ} = (10 lbs * sin 0)/(5 in2/cos 0) = 0 lbs/in2
Example Problem Given: Force = 10 lbs, Area (normal) = 5 in2 Determine σn and τ when Θ = 0 °, and Θ = 30° σn = {F cos Θ} / {An/cos Θ} = (10 lbs * cos 30)/(5 in2/cos 30) = lbs/in2 τ = {F sin Θ} / {An/cos Θ} = (10 lbs * sin 30)/(5 in2/cos 30) = lbs/in2
Example Problem Given: Force = 10 lbs, Area (normal) = 5 in2 Determine σn and τ when Θ = 0 °, and Θ = 30° σn = {F cos Θ} / {An/cos Θ} = (10 lbs * cos 30)/(5 in2/cos 30) = 1.50 lbs/in2 τ = {F sin Θ} / {An/cos Θ} = (10 lbs * sin 30)/(5 in2/cos 30) = 0.87 lbs/in2
Example Problem Given: Force = 10 lbs, Area (normal) = 5 in2 Determine σn and τ when Θ = 0 °, and Θ = 45° σn = {F cos Θ} / {An/cos Θ} = (10 lbs * cos 45)/(5 in2/cos 45) = τ = {F sin Θ} / {An/cos Θ} = (10 lbs * sin 45)/(5 in2/cos 45) =
Example Problem Given: Force = 10 lbs, Area (normal) = 5 in2 Determine σn and τ when Θ = 0 °, and Θ = 45° σn = {F cos Θ} / {An/cos Θ} = (10 lbs * cos 45)/(5 in2/cos 45) = 1.00 lbs/in2 τ = {F sin Θ} / {An/cos Θ} = (10 lbs * sin 45)/(5 in2/cos 45) = 1.00 lbs/in2
Example Problem Given: Force = 10 lbs, Area (normal) = 5 in2 Determine σn and τ when Θ = 0 °, and Θ = 60° σn = {F cos Θ} / {An/cos Θ} = (10 lbs * cos 60)/(5 in2/cos 60) = 0.5 lbs/in2 τ = {F sin Θ} / {An/cos Θ} = (10 lbs * sin 60)/(5 in2/cos 60) = 0.87 lbs/in2
Do your answers conform to the trends shown here? 5. Limits: (max) σn when Θ = 0 (min) σn when Θ = 90 (max) τ when Θ = 45 (min) τ when Θ = 0 or 90
Stress at any point can be ‘resolved’ via 3 mutually perpendicular stresses: σ1 , σ2 , σ3 Where σ1 > σ2 > σ3 6. Stress (σ) in 3 dimensions
B. Strain “your ideas??”
B. Strain 1. Strain Effects
B. Strain 1. Strain Effects a. Stress produces deformation Strain = dL L
B. Strain 1. Strain Effects a. Stress produces deformation “phi”
B. Strain 1. Strain Effects a. Strain Ellipse Maximum Shear Stress: Where σ1 - σ3 2
2. Stress – Strain Diagrams σ “which material is stronger?” ε
II. Elastic Response A. Young’s Modulus (E) “best shown in rocks” E = stressσ strain ε “elastic limit” “The greater E is, ……?
II. Elastic Response A. Young’s Modulus (E) “best shown in rocks” E = stressσ strain ε “The greater E is, the less deformation per unit stress OR “the stronger the material”
II. Elastic Response B. Poisson’s Ratio (ν) ν = lateral strain length strain In compression In tension
II. Elastic Response C. Ideal Elastic Behavior
II. Elastic Response D. Non-Ideal Elastic Behavior Strain hardening
‘delayed feedback’ II. Elastic Response E. Hysteresis Hard Rock “under repeated loads” Soft Rock
Assumes OM, MD II. Elastic Response F. Stress-Strain in Soils Limits of Proportionality (how much of the strain is Elastic?)
“under repeated loads” II. Elastic Response G. Repeated Loading of Soils (when rolled) Increment of permanent strain decreases (densification)
III. Time-Dependent Behavior – Strain A. Creep – under static loads Elastic response occurs instantaneously
Collapsed Culvert, Cincinnati, OH
III. Time-Dependent Behavior – Strain A. Creep – under static loads