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In this lab, inspired by the 2013 Tri-Valley Cannonball Champion’s methodology, students will determine the specific heat of aluminum by utilizing water's high specific heat capacity. By measuring energy changes—using Joules, mass in grams, and temperature change in degrees Celsius—learn how different substances require unique amounts of heat to change temperature. The experiment emphasizes the significance of water's specific heat in regulating body temperature and environmental stability, further illustrating the principles of thermal energy transfer.
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Specific Heat Pre – Lab
“Flying Freddie Spooner” 2013 Tri-Valley Cannonball Champion
Specific Heat • Different substances require different amounts of heat to change their temperature. • In general the specific heat of a substance indicates how hard something is to heat up or cool down. • Scientifically speaking the specific heat is the amount of heat required to change the temperature of 1 gram of a substance by 1ºC.
Importance of Water’s High Specific Heat • Maintenance of Body Temperature
Importance of Water’s High Specific Heat • Temperature fluctuations that permit life.
Importance of Water’s High Specific Heat • Heat Storage on a Larger Scale.
How can we determine experimentally the specific heat of this metal? Lead
J/g °C We must determine three things to find the specific heat? Joules (Energy) Grams (mass) °C (temperature change)
What measurements of this metal are needed to find it’s specific heat? Lead
Today you will use the high specific heat capacity of water to help us determine the specific heat of a metal. • How will we do this?
. 100.0°C
. 100.0°C
How Do We Use the Measurements Below to Determine the Specific Heat of the Metal? 100.0°C
H = mΔTCp H Metal’s p 100.0°C
100.0°C What does this answer represent? Hwater = mΔTCp = (50.00g)(6.8°C)(4.184 J/g C) = 1422.56J = 1400J
100.0°C Hwater = Hmetal = 1400J We can now find the Cp of the metal
Calculate the “Percent Error”of our specific heat measurement.
You will experimentally determine the specific heat of Aluminum 0.90