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Ch. 13: Chemical Equilibrium

Ch. 13: Chemical Equilibrium. 13.1 The Equilibrium Condition. Equilibrium. dynamic equilibrium may seem like no changes are occurring but there are changes no NET changes When did this reaction reach it?. reactants. products. H 2 O(g) + CO(g)  H 2 (g) + CO 2 (g).

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Ch. 13: Chemical Equilibrium

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  1. Ch. 13: Chemical Equilibrium 13.1 The Equilibrium Condition

  2. Equilibrium • dynamic equilibrium • may seem like no changes are occurring but there are changes • no NET changes • When did this reaction reach it?

  3. reactants products H2O(g) + CO(g)  H2(g) + CO2(g)

  4. At equilibrium, forward and reverse reaction rates are ____________

  5. Equilibrium • equilibrium position of a reaction is determined by • initial _________________ • ____________ of reactants and products • degree of __________________ of reactants and products • GOAL: • _ • _

  6. lies “to the left” more _________ less ___________ lies “to the right” less __________ more _________ If reactants are mixed and concentrations do not change could already be at equilibrium reaction rates are so ________ that change is too difficult to detect Equilibrium Position

  7. Ch. 13: Chemical Equilibrium 13.2 Equilibrium Constant

  8. Law of Mass Action • created in 1864 by Guldberg and Waage (Norweigen) • For a reaction: jA + kB ⇄ lC + mD • equilibrium constant: K

  9. Law of Mass Action • because • Rateforward = • Ratereverse = • so if Ratef = Rater • kf[A]j[B]k =kr[C]l[D]m

  10. Example • Write the equilibrium expression for: 4NH3(g) + 7O2(g)  4NO2(g) + 6H2O(g) • What would it be for the reverse reaction?

  11. Equilibrium Constant • will always have the same value at a certain temperature • no matter what amounts are added • ratio at equilibrium will always be same

  12. Equilibrium Position • each set of equilibrium concentrations • depends on initial concentrations

  13. Ch. 13: Chemical Equilibrium 13.3 Equilibrium Expressions with Pressure

  14. Equilibrium with Gases • equilibria involving gases can be described using __________ instead of _______________ N2(g) + 3H2(g)  2NH3(g)

  15. Equilibrium with Gases N2(g) + 3H2(g)  2NH3(g)

  16. Calculating K from KP • KP = KC : RT can cancel out if total of coefficients are same on each side • where ∆n is the difference in moles of gas on either side of the equation • ∆n = (l+m) – (j+k) N2(g) + 3H2(g)  2NH3(g) • ∆n =

  17. Example • Setup the expression for KP in terms of KC, R and T 2NO(g) + Cl2(g)  2NOCl(g)

  18. Ch. 13: Chemical Equilibrium 13.4: Heterogeneous Equilibria

  19. Heterogeneous Equilibria • involve more than one phase • position of heterogeneous equilibria does NOT depend on amounts of: • _ • _ • because their concentrations stay constant (since they are PURE)

  20. Heterogeneous Equilibria • do not include liquids or solids in equilibrium expression • only include ________ and ______________

  21. Example 1 • 2H2O(l) ⇄ 2H2(g) + O2(g) • 2H2O(g) ⇄ 2H2(g) + O2(g)

  22. Ch. 13: Chemical Equilibrium 13.5/6: Applications of Equilibrium Constant (K)

  23. Equilibrium Constant • if we know the value of K, we can predict: • tendency of a reaction to occur • if a set of concentrations could be at equilibrium • equilibrium position, given initial concentrations

  24. Equilibrium Constant • If you start a reaction with only reactants: • concentration of reactants will decrease by a certain amount • concentration of products will increase by a same amount

  25. Example 2 • The following reaction has a K of 16. You are starting reaction with 9 O3 molecules and 12 CO molecules. • Find the amount of each species at equilibrium. O3(g) + CO(g)  CO2(g) + O2(g)

  26. Example 2

  27. Example 2

  28. Example 2

  29. If _________ mostly products goes essentially to completion lies far to right If _________ mostly reactants reaction is negligible lies far to left size of K and time needed to reach equilibrium are NOT related time required is determined by reaction rate (Ea) Extent of a Reaction

  30. Reaction Quotient • Q: equal to equilibrium expression but ___________ have to be at equilibrium • used to tell if a reaction is at equilibrium or not • relationship between Q and K tells which way the reaction will shift • _______: at equilibrium, no shift • _______: too large, forms reactants, shift to left • ______: too small, forms products, shift to right

  31. Example 3 • For the synthesis of ammonia at 500°C, the equilibrium constant is 6.0 x 10-2. Predict the direction the system will shift to reach equilibrium in the following case: N2(g) + 3H2(g)  2NH3(g)

  32. Example 3 • [NH3]0 = 1.0x10-3 M, [N2]0=1.0x10-5 M [H2]0=2.0x10-3 M Q __ K so forms _________, shifts to _____

  33. Example 4 • In the gas phase, dinitrogen tetroxide decomposes to gaseous nitrogen dioxide: N2O4(g) ⇄ 2NO2(g) • Consider an experiment in which gaseous N2O4 was placed in a flask and allowed to reach equilibrium at a T where KP = 0.133. At equilibrium, the pressure of N2O4 was found to be 2.71 atm. • Calculate the equilibrium pressure of NO2.

  34. Example 4

  35. Example 5 • At a certain temperature a 1.00 L flask initially contained 0.298 mol PCl3(g) and 8.70x10-3 mol PCl5(g). After the system had reached equilibrium, 2.00x10-3 mol Cl2(g) was found in the flask. PCl5(g)  PCl3(g) + Cl2(g) • Calculate the equilibrium concentrations of all the species and the value of K.

  36. Example 5

  37. Approximations • If K is very small, we can assume that the change (x) is going to be negligible • can be used to cancel out when adding or subtracting from a “normal” sized number • to simplify algebra 0

  38. Example 6 • At 35°C, K=1.6x10-5 for the reaction 2NOCl(g) ⇄ 2NO(g) + Cl2(g) • Calculate the concentration of all species at equilibrium for the following mixtures • 2.0 mol NOCl in 2.0 L flask • 1.0 mol NOCl and 1.0 mol NO in 1.0 L flask • 2.0 mol NOCl and 1.0 mol Cl2 in 1.0 L flask

  39. Example 6 • 2.0 mol NOCl in 2.0 L flask • [NOCl]= • [NO]= [Cl2]=

  40. Example 6 • 1.0 mol NOCl and 1.0 mol NO in 1.0 L flask • [NOCl]= • [NO]= [Cl2]=

  41. Example 6 • 2.0 mol NOCl and 1.0 mol Cl2 in 1.0 L flask • [NOCl]= • [Cl2]= [NO]=

  42. Ch. 13: Chemical Equilibrium 13.7: Le’ Chatlier’s Principle

  43. Le Châtlier’s Principle • can predict how certain changes in a reaction will affect the position of equilibrium

  44. Changing Concentration • system will shift away from the added component or towards a removed component • Ex: N2 + 3H2 2NH3 • if more N2 is added, then equilibrium position shifts to right • if some NH3 is removed, then equilibrium position shifts to right

  45. Change in Pressure • adding or removing gaseous reactant or product is same as changing conc. • adding inert or uninvolved gas • increase the ___________________ • ___________effect the equilibrium position

  46. Change in Pressure • changing the volume • decrease V • decrease in # gas molecules • shifts towards the side of the reaction with _____ gas molecules • increase V • increase in # of gas molecules • shifts towards the side of the reaction with _____ gas molecules

  47. Change in Temperature • all other changes alter the concentration at equilibrium position but don’t actually change value of K • value of K does change with temperature

  48. Change in Temperature • if energy is added, the reaction will shift in direction that consumes energy • treat energy as a • __________: for endothermic reactions • __________: for exothermic reactions

  49. add CO add C remove C add As4O6 remove As4O6 remove As4 decrease volume add Ne gas As4O6(s) + 6C(s) ⇄ As4(g) + 6CO(g)

  50. decrease volume increase volume add P4 remove Cl2 add Kr gas add PCl3 P4(s) + 6Cl2(g) ⇄ 4PCl3(l)

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