1 / 9

E E 1205 Circuit Analysis

E E 1205 Circuit Analysis. Lecture 03 - Simple Resistive Circuits and Applications. Calculating Resistance. When conductor has uniform cross-section. Temperature Coefficient of Resistance. Metallic conductors have a linear increase of resistance with increased temperature.

ianna
Télécharger la présentation

E E 1205 Circuit Analysis

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. E E 1205 Circuit Analysis Lecture 03 - Simple Resistive Circuits and Applications

  2. Calculating Resistance When conductor has uniform cross-section

  3. Temperature Coefficient of Resistance Metallic conductors have a linear increase of resistance with increased temperature. To is the reference temperature (usually 20oC) and Ro is the resistance at the reference temperature. a is the temperature coefficient of resistance for the material. At 20oC, some values for a are:

  4. Resistors in Series By KCL: Is = I1= I2 By Ohm’s Law: V1 = R1·I1 and V2 = R2·I2 Combine: Vs = R1I1 + R2I2 = (R1 + R2) Is = ReqIs In General: Req = R1 + R2 +···+ Rn

  5. Resistors in Parallel (1/2) By KVL: Vs = V1 = V2 By KCL: Is = I1 + I2 By Ohm’s Law: and Combine:

  6. Resistors in Parallel (2/2) For two resistors: For many resistors: In terms of conductance:

  7. Voltage Divider Circuit

  8. Loaded Voltage Divider

  9. Voltage Divider Equations Unloaded: Loaded: If RL >> R2:

More Related