Télécharger la présentation
## Questions:

- - - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - - -

**Questions:**• what is the intensity of the double-slit pattern at an arbitrary position? • What about three slits? Interference of Light • Intensity of double-slit pattern • Three slits**Young’s Double Slit Experiment**Screen at infinity θ d Δx Path difference Δx = d sin θ d sinθ = m λ, m = 0, 1, 2, … Maximum intensity at • d sinθ = (m +½ ) λ, m = 0, 1, 2, … Minimum intensity at**Find the intensity of the double-slit interference pattern**as a function of position on the screen. Two waves: E1 = E0sin(w t) E2 = E0sin(w t + f ) where:**Trigonometry:**sin a + sin b = 2 cos [(a-b)/2] sin [(a+b)/2] E1 + E2 = E0[sin(w t) +sin(w t + f )] = 2 E0cos (f / 2) sin(w t + f / 2)] Resultant amplitude ER Resultant intensity, (a function of angle qto the screen)**I**position • fringes are wide, with fuzzy edges • equally spaced (in sin θ or small θ) • equal intensity**Quiz**With only one slit open, the intensity in the centre of the screen is 100 W/m 2. With both (identical) slits open together, the intensity at locations of constructive interference will be • zero • 100 W/m2 • 200 W/m2 • 400 W/m2**Example**• Two narrow parallel slits are separated by 0.85mm and are illuminated by light of a 600nm wavelength. • What is the phase difference between the two interfering waves on a screen 2.8m away at a point 2.5mm from the central bright fringe? • What is the ratio of the intensity at this point to the intensity at the center of a bright fringe?**Three Equally-Spaced Slits**θ is the phase difference between consecutive slits d Δx = dsinθ d Total,**Three Slits Pattern**The total displacement is where = 2 (d sin )/ • When d sin = m and , ER = 3E0 (maximum value); so the bright fringes are in the same locations as with two slits. • There are minima (zero intensity) at = 120° and = 240° (where d sin = /3, 2/3 ); to see this, add the first and third term above). • At = 180° (where d sin = /2) there is a small maximum: ER = E0**2 slits**4I0 I 9I0 3 slits I0 2/3 1/2 1 1/3 In wavelengths f = 2π/3 rad Δx =λ /3**Differences between 2-slit and 3-slit patterns:**• 3 Slits: • Main peaks become narrower & brighter • One “extra” faint secondary peak in between • Main peaks ( = m2π) are in the same places As the number of slits becomes large, the main interference fringes become even narrower and brighter; the additional numerous faint peaks become less and less noticeable in comparison.**Many Slits (“diffraction grating”)**I 0 1 -1 m=(d sin )/**Quiz**Suppose the multiple slits from the previous slide were illuminated with white light, instead of red. What would the pattern on the screen look like? • The three bright lines would be white, with a little colour at the edges, but otherwise the same • Each of the three lines would spread into a wide coloured spectrum • Two of the three lines would spread into a wide coloured spectrum, with the centre one narrow and white