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Introduction to General Chemistry PowerPoint Presentation
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Introduction to General Chemistry

Introduction to General Chemistry

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Introduction to General Chemistry

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  1. Introduction to General Chemistry Ch. 1.6 - 1.9 Lecture 2 Suggested HW: 33, 37, 40, 43, 45, 46

  2. Accuracy and Precision • Accuracy defines how close to the correct answer you are. Precision defines how repeatable your result is. Ideally, data should be both accurate and precise, but it may be one or the other, or neither. Accurateandprecise. Reached the target and the data was reproduced. Precise, but not accurate. Did not reach the target, but result was reproduced. Accurate, but not precise. Reached the target, but could not reproduce the result.

  3. Measuring Accuracy • Accuracy is calculated by percentage error (%E) • We take the absolute value because you can’t have negative error. • GROUP PROBLEM • - A certain brand of thermometer is considered to be accurate if the %E is < 0.8%. The thermometer is tested using water (BP = 100oC). You bring a pot of distilled water to a boil and measure the temperature 5 times. The thermometer reads: 100.6o, 100.4o, 99.8o, 101.0o, and 100.4o. Is it accurate?

  4. Measuring Precision: Significant Figures • Precision is indicated by the number of significant figures.Significant figures are those digits required to convey a result. • There are two types of numbers: exact and inexact • Exact numbers have defined values and possess an infinite number of significant figures because there is no limit of confidence: * There are exactly12eggs in a dozen * There are exactly24hours in a day * There are exactly1000 grams in a kilogram • Inexact number are obtained from measurement. Any number that is measured has error because: • Limitations in equipment • Human error

  5. Measuring Precision: Significant Figures • Example: Some laboratory balances are precise to the nearest cg (.01g). This is the limit of confidence. The measured mass shown in the figure is 335.49g. • The value 335.49 has 5 significant figures, with the hundredths place (9) being the uncertain digit. Thus, the (9) is estimated, while the other numbers are known. • It would properly reported as 335.49±.01g • - The actual mass could be anywhere between 335.485… g and 335.494…g. The balance is limited to two decimal places, so it rounds up or down. We use ± to include all possibilities.

  6. Determining the Number of Significant Figures In a Result • All non-zeros and zeros between non-zeros are significant • 457 (3) ; 2.5(2) ; 101(3) ; 1005(4) • Zeros at the beginning of a number aren’t significant. They only serve to position the decimal. • .02 (1) ; .00003 (1) ; 0.00001004 (4) • For any number with a decimal, zeros to the right of the decimal are significant • 2.200(4) ; 3.0(2)

  7. Determining the Number of Significant Figures In a Result • Zeros at the end of an integer may or may not be significant • 130(2 or 3), 1000(1, 2, 3, or 4) • This is based on scientific notation • 130 can be written as: 1.3 x 102  2 sig figs 1.30x 102  3 sig figs • If we convert 1000 to scientific notation, it can be written as: 1x 103 1 sig fig 1.0x 103  2 sig figs 1.00x 103  3 sig figs 1.000x 103  4 sig figs *Numbers that must be treated as significant CAN NOT disappear in scientific notation

  8. Calculations Involving Significant Figures • You can not get exact results using inexact numbers • Multiplication and division • Result can only have as many significant figures as the least precise number (3 s.f.) (2 s.f.) (1 s.f.)

  9. Calculations Involving Significant Figures • Addition and Subtraction • Result must have as many digits to the right of the decimal as the least precise number 20.4 1.322 83 + 104.722 211.942 212

  10. Group Work • Using scientific notation, convert 0.000976392 to 3 sig. figs. • Using scientific notation, convert 198207.6 to 1 sig. fig. H=10.000 cm W = .40 cm L = 31.00 cm • Volume of rectangle ? • Surface area (SA = 2WH + 2LH + 2LW) ? note: constants in an equation are exact numbers Limit of certainty is the ones place

  11. Dimensional Analysis • Dimensional analysis is an algebraic method used to convert between different units • Conversion factors are required • Conversion factors are exact numbers which are equalities between one unit set and another. • For example, we can convert between inches and feet. The conversion factor can be written as: • In other words, there are 12 inches per 1 foot, or 1 foot per 12 inches.

  12. Dimensional Analysis conversion factor (s) • Example. How many feet are there in 56 inches? • Our given unit of length is inches • Our desiredunit of length is feet • We will use a conversion factor that equates inches and feet to obtain units of feet. The conversion factor must be arranged such that the desired units are ‘on top’ 4.7 ft

  13. Group Work • Answer the following using dimensional analysis. Consider significant figures. • Convert 35 minutes to hours • Convert 40 weeks to seconds • Convert 4 gallons to cm3 (1 gallon = 4 quarts and 1 quart = 946.3 mL) • *35 to (1 mile = 5280 ftand 1 ft = 12 in)

  14. High Order Exponent Unit Conversion (e.g. Cubic Units) • As we previously learned, the units of volume can be expressed as cubic lengths, or as capacities. When converting between the two, it may be necessary to cube the conversion factor • Ex. How many mL of water can be contained in a cubic container that is 1 m3 Must use this equivalence to convert between cubic length to capacity 3 Cube this conversion factor

  15. Group Work • Convert 10 mL to m3 (c = 10-2) • Convert 100 L to µm3 (µ = 10-6) • Convert 48.3 ft2 to cm2 (1 in. = 2.54 cm)