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Advanced SQL: Intersect, Except, Null Values & Table Modification

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21 diapositives · 315 Views · Jul 31, 2014

Learn advanced SQL commands like INTERSECT and EXCEPT, handling NULL values, three-valued logic, explicit joins, various types of joins, and table modifications like insertions, deletions, and updates.

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Advanced SQL: Intersect, Except, Null Values & Table Modification
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  1. Lecture 4: Advanced SQL

  2. INTERSECT and EXCEPT:(missing from MySQL) (SELECT R.A, R.B FROM R)INTERSECT (SELECT S.A, S.B FROM S) SELECT R.A, R.B FROM RWHEREEXISTS(SELECT *FROM SWHERE R.A=S.A and R.B=S.B) (SELECT R.A, R.B FROM R)EXCEPT (SELECT S.A, S.B FROM S) SELECT R.A, R.B FROM RWHERENOTEXISTS(SELECT *FROM SWHERE R.A=S.A and R.B=S.B)

  3. Null Values • NULL in SQL is used as a placeholder for a missing or unknown values • By default, a table column can hold a NULL value

  4. Use of Null Values • If x=Null then 4*(3-x)/7 is still NULL • If x=Null then x=“Joe” is UNKNOWN • In SQL there are three boolean values: FALSE = 0 UNKNOWN = 0.5 TRUE = 1

  5. Three-Valued Logic • C1 AND C2 = min(C1, C2) • C1 OR C2 = max(C1, C2) • NOT C1 = 1 – C1 Rule in SQL: include only tuples that yield TRUE SELECT * FROM Person WHERE (age < 25) AND (height > 6 OR weight > 190) E.g.age=20height=NULLweight=200

  6. Three-Valued Logic Unexpected behavior: Some Persons are not included ! SELECT * FROM Person WHERE age < 25 OR age >= 25

  7. Working with Null Values Can test for NULL explicitly: • x IS NULL • x IS NOT NULL Now it includes all Persons SELECT * FROM Person WHERE age < 25 OR age >= 25 OR age IS NULL

  8. Explicit Joins Explicit joins in SQL: Product(name, category) Purchase(prodName, store) Same as: But Products that never sold will be lost ! SELECT Product.name, Purchase.store FROM Product JOIN Purchase ON Product.name = Purchase.prodName SELECT Product.name, Purchase.store FROM Product, Purchase WHERE Product.name = Purchase.prodName

  9. Left Outer Joins Left outer joins in SQL: Product(name, category) Purchase(prodName, store) SELECT Product.name, Purchase.store FROM Product LEFT OUTER JOIN Purchase ON Product.name = Purchase.prodName

  10. Product Purchase

  11. Types of Joins - Summary • Inner join: same as Join, implicit Join • Left outer join: • Same as Left join • Include the left tuple even if there’s no match • Right outer join: • Same as right join • Include the right tuple even if there’s no match • Full outer join: • Missing from MySQL(but can be emulated! how?) • Include the both left and right tuples even if there’s no match

  12. Modifying the Database Three kinds of modifications • Insertions • Deletions • Updates Sometimes they are all called “updates”

  13. Insertions General form: INSERT INTO R(A1,…., An) VALUES (v1,…., vn) Example: Insert a new purchase to the database: INSERT INTO Purchase(buyer, seller, product, store) VALUES (‘Joe’, ‘Fred’, ‘wakeup-clock-espresso-machine’, ‘The Sharper Image’) Missing attributes  NULL. May drop attribute names if give them in order.

  14. Insertions INSERT INTO PRODUCT(name) SELECT DISTINCT Purchase.product FROM Purchase WHERE Purchase.date > “10/26/01” The query replaces the VALUES keyword. Here we insert manytuples into PRODUCT The number of columns must be identical

  15. Insertion: an Example Product(name, listPrice, category) Purchase(prodName, buyerName, price) prodName is foreign key in Product.name Suppose database got corrupted and we need to fix it: Purchase Product Task: insert in Product all prodNames from Purchase

  16. Insertion: an Example INSERT INTO Product(name) SELECT DISTINCT prodName FROM Purchase WHERE prodName NOT IN (SELECT name FROM Product)

  17. Insertion: an Example INSERT INTO Product(name, listPrice) SELECT DISTINCTprodName, price FROM Purchase WHEREprodNameNOT IN (SELECT name FROM Product) ERROR!

  18. Deletions Example: DELETE FROM PURCHASE WHERE seller = ‘Joe’ AND product = ‘Brooklyn Bridge’ Factoid about SQL: there is no way to delete only xoccurrences of a tuple that appears x+ktimes in a relation.

  19. Updates Example: UPDATEProduct SETlistPrice= listPrice/2 WHERE Product.name IN (SELECT product FROM Purchase WHERE Date =‘Oct, 25, 1999’);

  20. Updates Using Exists Example: UPDATE Product SETlistPrice = (SELECT AVG(price)FROM PurchaseWHERE prodName=name)WHERE EXISTS (SELECT *FROM PurchaseWHERE prodName=name);

  21. Table Modifications - Summary INSERT INTO table_name(column1, column2,...)VALUES(value1, value2, ...) INSERT INTO table_name(column1, column2,...)SELECT … DELETE FROM table_name WHERE cond UPDATEtable_nameSETcolumn1=expr1, column2=expr2,...WHEREcond