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Inference about Two Population Proportions in Testing Claims

This lesson focuses on testing claims and constructing confidence intervals for the difference between two population proportions. It also covers determining the necessary sample size for estimating the difference.

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Inference about Two Population Proportions in Testing Claims

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  1. Lesson 11 - 3 Inference about Two Population Proportions

  2. Objectives • Test claims regarding two population proportions • Construct and interpret confidence intervals for the difference between two population proportions • Determine the sample size necessary for estimating the difference between two population proportions within a specified margin of error

  3. Vocabulary • Robust – minor deviations from normality will not affect results • Independent – when the individuals selected for one sample do not dictate which individuals are in the second sample • Dependent – when the individuals selected for one sample determine which individuals are in the second sample; often referred to as matched pairs samples

  4. Requirements Testing a claim regarding the difference of two proportions • Samples are independently obtained using simple random sampling • n1p1(1-p1) ≥ 10 and n2p2(1-p2) ≥ 10 • n1 ≤ 0.05N1 and n2 ≤ 0.05N2; (this requirement ensures the independence necessary for a binomial experiment)

  5. Classical and P-Value Approach – Two Proportions -zα -zα/2 zα zα/2 p1 – p2 z0 = --------------------------------- p(1-p) where x1 + x2 p = ------------ n1 + n2 1 1 --- + --- n1 n2 P-Value is thearea highlighted Remember to add the areas in the two-tailed! -|z0| |z0| z0 z0 Critical Region Test Statistic:

  6. Confidence Interval – Difference in Two Proportions Lower Bound: Upper Bound: p1 and p2 are the sample proportions of the two samples Note: the same requirements hold as for the hypothesis testing p1(1 – p1) p2(1 – p2) --------------- + -------------- n1 n2 (p1 – p2) – zα/2 · p1(1 – p1) p2(1 – p2) --------------- + -------------- n1 n2 (p1 – p2) + zα/2 ·

  7. 2 zα/2 n = n1= n2 = p1(1 – p1) + p2(1 – p2) ------ E 2 zα/2 n = n1= n2 = 0.25 ------ E Sample Size for Estimating p1 – p2 The sample size required to obtain a (1 – α) * 100% confidence interval with a margin of error E is given by rounded up to the next integer, where pi is a prior estimate of pi. If a prior estimates of pi are unavailable, the sample required is rounded up to the next integer. The margin of error should always be expressed as a decimal when using either of these formulas.

  8. Two Proportions using TI • Hit STAT and Select Test • Scroll down to 2-PropZTest and ENTER • Enter data from problem • select test type (left, two or right tailed) • Hit Calculate • Classical: compare Z0 with Zc (from table) • P-value: compare p-value with α

  9. Example We have two independent samples. 55 out of a random sample of 100 students at one university are commuters. 80 out of a random sample of 200 students at another university are commuters. We wish to know of these two proportions are equal. We use a level of significance α = .05 Check Requirements Random sample discussed above is SRS  p1 = 0.55 n1 p1(1-p1) = 24.75 > 10  n1 = 100 n1 < 0.05N1assume > 2000 total students  p2 = 0.40 n2 p2(1-p2) = 48 > 10  n2 = 200 n2 < 0.05N2assume > 4000 total students 

  10. p1 – p2 z0 = --------------------------------- p(1-p) Pooled Est: 55 + 80 p = -------------- = 0.45 100 + 200 1 1 --- + --- n1 n2 Example Problem Cont. Checked • Requirements: • HypothesisH0: H1: • Test Statistic: • Critical Value: • Conclusion: p1 = p2 (No difference) p1 ≠ p2 = 2.462, p = 0.0138 zc(0.05/2) = 1.96, α = 0.05 Reject H0 sufficient evidence to support a difference in the proportions of students who commute

  11. Summary and Homework • Summary • We can compare proportions from two independent samples • We use a formula with the combined sample sizes and proportions for the standard error • The overall process, other than the formula for the standard error, are the general hypothesis test and confidence intervals process • Homework • pg 609 - 611: 1, 2, 4, 6, 9, 15, 24

  12. Homework Answers • 4 a) H0: p1 = p2 H1: p1 < p2 b&d) z0 = -0.346 p = 0.3649 c) Zc = -1.645 FTR H0 • 6 a) H0: p1 = p2 H1: p1 ≠ p2 b&d) z0 = -2.189 p = 0.0286 c) Zc = -1.960 Rej H0 • 24 a) 2551 b) 3383

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