Understanding Stoichiometry: Moles, Molar Mass, and Formulas
Explore the concept of moles, molar mass, and formula calculations in chemistry through examples and practical applications. Learn about balancing reactions and empirical formulas. Video lessons included.
Understanding Stoichiometry: Moles, Molar Mass, and Formulas
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Presentation Transcript
UNIT 2 STOICHIOMETRY
Video 2.1 Moles and Molar Mass
Stoichiometry • The Mole represents a specific amount of any substance. • Specifically it represents 6.02x1023 particles such as atoms and molecules.
The Mole = 6.02x1023 • The mole is based on the fact that 12 grams of Carbon-12 has a mole of atoms. • A mole means you have 6.02x1023 particles.
Molar Mass • Molar Mass (aka gram formula mass or molecular mass) is the mass of one mole of a substance. • Element’s molar masses are reported on the periodic table.
Molar Mass Examples: Elements • What is the molar mass of iron? • What is the molar mass of copper? 55.8 g/mol 63.5 g/mol
Molar Mass Examples: Compounds • What is the molar mass of water? • H2O = 2(1.0) + 16.0 = • 18.0g/mol • What is the gram-formula-mass of calcium chloride? • CaCl2 = 40.1 + 2(35.5) = • 111.1 g/mol
Video 2.2 Calculating Moles
What if you have more than one mole of a substance? Use the formula on table T: number of moles = given mass (g) _ gram-formula mass (Given mass will be your answer.)
Let’s try these together… • Calculate the mass of 6.70 moles of carbon. 6.70 = x _ 12.og/mol x = 80.4 g
Example 2 Calculate the mass of 0.023moles of lithium. 0.023 = x _ 6.9 g/mol x = 0.16 g
Example 3 Calculate the mass of 25.02 moles of calcium phosphate. 25.02 = x _ 310.3/mol x = 7764 g
The gfm formula • Use the same formula to calculate the moles, placing the number in the question on the numerator: number of moles = given mass (g) gram-formula mass
Let’s try these together… 4. Determine the number of moles in 8.0 grams of Boron. x = 8.0 g _ 10.8g/mol x = 0.74 moles
Example 5 Determine the number of moles in 0.567 grams of Helium. x = 0.567 g _ 4.00 g/mol x = 0.142 moles
Example 6 Find the number of moles in 1230 grams of magnesium sulfate. x = 1230 g _ 120.4 g/mol x = 10.2 moles
Video 2.3 Moles to Coefficients
Reactions Mix + 2 Eggs + 1 cup water = Cake Reactants Products 2 Mix = 2 Cakes 6 Eggs = 3 Cakes
Coefficients 4Al + 3O2 2Al2O3 reactants products Coefficients: How many moles of the substance are needed in a reaction.
Relating Moles • To relate moles of one substance to another, simply create a proportion: 4Al + 3O2 2Al2O3 • If 3 moles of oxygen react, how many moles of Aluminum oxide form? 2 • If 4 moles of aluminum react, how many moles of oxygen are needed? 3 • If 4 moles of aluminum oxide are formed, how many moles of oxygen were used? 6 • If 8 moles of aluminum react, how many moles of oxygen are needed? 6
Relating Moles 16 Al + 3S8 8Al2S3 • If 2.50 moles of sulfur react, how many moles of aluminum sulfide form? 2.50 mole S = x moles Al2S3 3 8 x = 6.67 moles
Example 2 16 Al + 3S8 8Al2S3 If 3.75 moles of aluminum react, how many moles of sulfur are needed? 3.75 mole Al = x moles S8 16 3 x = 0.703 moles
THINK Why do chemists use moles to measure substances? Why aren’t grams, liters and molecules enough?
Video 2.4 Balancing
Conservation of Mass • In a reaction, atoms and molecules cannot appear or disappear. Mass must stay constant from the beginning to the end of the reaction. • H2 + O2 H2O • ___H2 + ___O2 ___ H2O
Balancing Reactions ___ N2 + ____H2 ____ NH3 ___Li + ____O2 ___Li2O
Balancing __Pb(NO3)2 +__K2CrO4___PbCr2O4 + ___KNO3 ___C4H8 + ___O2 ___CO2 + ___H2O
Types of Reactions • Synthesis: A + 2B AB2 • Decomposition: AB2 A + 2B • Combustion: CH4 + O2 CO2 + H2O • Single Replacement: AB + C CB +A • Double Replacement: AB + CD AD + CB * Notice synthesis and decomposition are opposites. Also, combustion can have any carbon compound as a reactant.
Video 2.5 Empirical and Molecular Formulas
Empirical Formulas • Empirical formula refers to any molecular formula in it’s reduced form. Are these empirical? If not, reduce them: • C2H2 • C6H12O6 • NO2 • Na2(OH)2 • CH • CH2O • NO2 • NaOH
Molecular Formulas • Molecular Formulas are some multiple of the empirical formula. • If the empirical formula is CH4 a molecular formula could be CH4, C2H8, C3H12 etc. • A compound whose empirical formula is NH3 has a mass of 34 g/mol. What is the empirical formula? NH3 = 17.0 g/mol 34/17 = 2 2NH3 = N2H6
Steps: • Find the mass of the empirical formula. • Divide the mass given by the empirical mass. • Distribute your answer through the empirical formula. • If a compound has a mass of 45 g/mol and an empirical formula of CH3, what is the molecular formula? CH3 = 15 g/mol 45/15 = 3 3CH3 = C3H9
Video 2.6 Percent Composition
Percent Composition • Nutrition Facts on foods can tell you just how much of a substance you are consuming and how that relates to how much you should eat in a day. • It is equally important to know how much of a element or compound is in a mixture.
Percent Composition % By mass: mass part x 100 total mass • Find the % by mass of phosphoric acid. H3PO4 3(1.0) x 100 3(1.o)+32.1+4(16.0) = 3.02%
Example 2 Find the percent by mass of Ca in Ca(OH)2. 40.0 x 100 40.0+2(16.0)+2(1.0) = 54.1%
Find the percent by mass of Na: 23.0/74.5 *100 = 30.9% • NaClO • NaCl • NaOH 23.0/58.5 *100 = 39.3% 23.0/40.0 *100 = 57.5%
Percent Composition Examples A sample of a substance containing only magnesium and chlorine was tested in the laboratory and found to be composed of 74.5% chlorine by mass. If the total mass of the sample was 190.2 grams, what is the mass of the magnesium? 0.745 (190.2) = 141.7 grams
For teacher use Class slides
THINK I went apple picking and they charge per dozen apples. I was worried it would take forever to count all the apples when I was on line. But the were smart: they weighed the apples. A dozen apples weighs 180 grams. • I have 540 grams of apples, how many dozen do I have? • How much does 2 dozen weigh? • How much does 0.25 dozen weigh? • How is this similar for moles?
Mole Quiz Review • Find the gram formula mass of: • Ne c. NH3 • NaCld. Mg(OH)2 • Find the number of moles is 230g Mg(OH)2 • Find the mass of 2.50 moles of NH3 • Given: 2NaCl + Mg(OH)2 2NaOH + MgCl2 Find the number of moles of NaCl that will react with 3.75 moles of Mg(OH)2.