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Steps for Solving a. Stoichiometry Problem. By: Aryn Balogh Period: 1. If 12.7g of water is decomposed using an electric current, how many grams of Hydrogen and Oxygen gas will be produced?. Step 1: Write a complete and balanced chemical equation.

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## Steps for Solving a

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**Steps for Solving a**Stoichiometry Problem By: Aryn Balogh Period: 1**If 12.7g of water is decomposed using**an electric current, how many grams of Hydrogen and Oxygen gas will be produced?**Step 1:Write a complete and balanced chemical equation.**2H2O 2H2 + O2**Step 2:Draw a column for each chemical.**2H2O 2H2 + O2**Step 3: Write the amount given in the appropriate column.**2H2O 2H2 + O2 12.7g**Step 4:Convert the amount given into moles.**2H2O 2H2 + O2 12.7g/1 x 1mole/18.0148g= 0.705 moles**Step 5:Find moles for each of the other chemicals.**a) In each of the other columns write the moles of given (x) a fraction. 2H2O 2H2 + O2 12.7g/1 x 1mole/18.0148g= 0.705 moles 0.705mx X/X 0.705mx X/X**b) The numerator of the fraction is the coefficient of that**column. 2H2O 2H2 + O2 12.7g/1 x 1mole/18.0148g= 0.705m x 2/X= 0.705m x 1/X=**c) The denominator of the fraction is the coefficient of**the given column. 2H2O 2H2 + O2 0.705m x 1/2= 12.7g/1 x 1mole/18.0148g= 0.705m x 2/2=**d) Do math and label as moles.**2H2O 2H2 + O2 12.7g/1 x 1mole/18.0148g= 0.705 moles 0.705m x 2/2= 0.705 moles 0.705m x 1/2= 0.353 moles**Step 6:Convert all moles into grams.**2H2O 2H2 + O2 12.7g/1 x 1mole/18.0148g= 0.705 moles 0.705m x 2/2= 0.705 moles 0.705m x 1/2= 0.353 moles 0.705m/1 x 2.0158g/1m= 1.42g 0.353m/1 x 31.998g/1m= 11.3g**Step 7:Verify the law of conservation of mass**2H2O 2H2 + O2 12.7g/1 x 1mole/18.0148g= 0.705 moles 0.705m x 2/2= 0.705 moles 0.705m x 1/2= 0.353 moles 0.705m/1 x 2.0158g/1m= 1.42g 0.353m/1 x 31.998g/1m= 11.3g 12.7g = 1.42g + 11.3g 12.7g = 12.7g 1.42g of Hydrogen gas will be produced & 11.3g of Oxygen will be produced.

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