1 / 6

Viterbi once again!

0.9. 0.95. 1:1/6 2:1/6 3:1/6 4:1/6 5:1/6 6:1/6. 1:1/10 2:1/10 3:1/10 4:1/10 5:1/10 6:1/2. 0.05. 0.10. Loaded. Fair. Viterbi once again!. Model generates numbers 312453666641. The unfair casino : Loaded dice p(6) = 0.5; switch fair to load:0.05; switch load to fair: 0.1.

kioko
Télécharger la présentation

Viterbi once again!

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. 0.9 0.95 1:1/6 2:1/6 3:1/6 4:1/6 5:1/6 6:1/6 1:1/10 2:1/10 3:1/10 4:1/10 5:1/10 6:1/2 0.05 0.10 Loaded Fair Viterbi once again! • Model generates numbers • 312453666641 The unfair casino: Loaded dice p(6) = 0.5; switch fair to load:0.05; switch load to fair: 0.1

  2. Example: 566. What was the series of dice used to generate this output? 0.9 0.95 1:1/6 2:1/6 3:1/6 4:1/6 5:1/6 6:1/6 1:1/10 2:1/10 3:1/10 4:1/10 5:1/10 6:1/2 0.05 0.10 Loaded Fair Model decoding (Viterby) FFF = 0.167*0.95*0.167*0.95*0.167 = 0.0042 FFL = 0.167*0.95*0.167*0.05*0.5 = 0.00666 FLF = 0.167*0.05*0.5*0.1*0.167 = 0.000070 FLL = 0.167*0.05*0.5*0.9*0.5 = 0.0019 LFF LFL LLF LLL

  3. Example: I now add one more say 5! After my first 3 throws I have ended up having either a loaded or a fair dice in my hand The most likely “path” to a loaded dice is FLL = 0.167*0.05*0.5*0.9*0.5 = 0.0019 The most likely path to a fair dice is FFF = 0.167*0.95*0.167*0.95*0.167 = 0.0042 Since the Markov model has no memory, the most likely path to having a fair dice after the 4th through is 0.9 0.95 1:1/6 2:1/6 3:1/6 4:1/6 5:1/6 6:1/6 1:1/10 2:1/10 3:1/10 4:1/10 5:1/10 6:1/2 0.05 0.10 Loaded Fair Model decoding (Viterby)

  4. Log model -0.05 -0.02 1:-0.78 2:-0.78 3:-0.78 4:-0.78 5:-0.78 6:-0-78 1:-1 2:-1 3:-1 4:-1 5:-1 6:-0.3 -1.3 -1 Fair Loaded Model decoding (Viterby)

  5. Log model -0.05 -0.02 1:-0.78 2:-0.78 3:-0.78 4:-0.78 5:-0.78 6:-0-78 1:-1 2:-1 3:-1 4:-1 5:-1 6:-0.3 -1.3 -1 Fair Loaded Model decoding (Viterby) Identify what series of dice was used to generate this output?

  6. Log model -0.05 -0.02 1:-0.78 2:-0.78 3:-0.78 4:-0.78 5:-0.78 6:-0-78 1:-1 2:-1 3:-1 4:-1 5:-1 6:-0.3 -1.3 -1 Fair Loaded Model decoding (Viterby) Series of dice is FFFFLLL

More Related