1 / 12

Tic-Tac-Toe Factoring

Tic-Tac-Toe Factoring. A fun way to factor quadratics!. Where do you begin?. You start by identifying the a , b and c values in your quadratic expression or equation. Remember the form is a x 2 + b x+ c You may want to write down the values next to your problem. Now, for placement.

kirima
Télécharger la présentation

Tic-Tac-Toe Factoring

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Tic-Tac-Toe Factoring A fun way to factor quadratics!

  2. Where do you begin? • You start by identifying the a, b and c values in your quadratic expression or equation. • Remember the form is ax2+bx+c • You may want to write down the values next to your problem.

  3. Now, for placement • Draw a tic-tac-toe board. • You will place numbers in specific spots to properly factor your problem

  4. Placement of your values

  5. Example: a=1 b=7 c = 6 a⋅c = 6 Fill in the boxes like this a b a⋅c

  6. Now, you have to do some thinking! • Find the factorspairs of a⋅cthat have a sum equal to the value of b. • In our example, a⋅c=6and b=7 • So, the factor pairs of 6 are 1⋅6 and 2⋅3 where 1+6=7 and 2+3=5 • Since b = 7, you would choose 1and 6as your factors.

  7. Placement of Factors • Place the factors beneath the a⋅cvalue on the Tic-Tac-Toe board (order doesn’t matter). a b a⋅c Factors of a⋅cwith a sum of b

  8. The next part is tricky! • You have to find the GCF (greatest common factor) of the numbers in these boxes… …and put it here

  9. Whew, the hard parts are done! • Complete the multiplication equations to fill the blanks. = = 1 1 X X 6 = X

  10. Finishing up • Now, all you have to do is group some numbers to form the binomials. (x+6) (x+1) • The variables go with the numbers in the left column. Rewrite the circled numbers in binomial form like this… (x+6)(x+1) • You don’t usually see the 1 in front of the variable so you don’t have to put it there.

  11. You are finished… • with the factoring part, anyway. • If you want to make sure your answer is correct, multiply the two binomials. If this results in your original trinomial, you are correct! (x+ 6)(x+ 1) = x2 + 7x + 6

  12. Finding the Zeros • To find the zeros, use the zero product property toset each binomial equal to zero and solve for the variable. • x+1=0 x+6=0 -1-1-6 -6 0 -1 0 -6 x =-1x =-6 • The solutions are -1 and -6 • These solutions indicate thatthe parabola intercepts the x-axis at -1 and 6.

More Related