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Limiting Reagent Calculations in Chemistry Problem

This chemistry problem involves determining the limiting reagent and calculating the grams of product formed in a reaction. Challenge yourself with this exercise to enhance your understanding of stoichiometry. Each step is explained thoroughly to support your learning.

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Limiting Reagent Calculations in Chemistry Problem

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  1. How many bikes can be made from 100 bicycle wheels, 20 frames and 80 pedals? 100 wheels × 1 bike = 50 bikes 2 wheels 20 frames × 1 bike = 20 bikes 1 frame 80 pedals × 1 bike = 40 bikes 2 pedals

  2. When given the reaction: S8(l) + 4 Cl2 (g) → 4 S2Cl2 (l) 5.0 mol Cl2 reacts with 2.0 mol S8, how many grams of S2Cl2 form? Which reactant is the limiting reagent?

  3. When given the reaction: S8(l) + 4 Cl2 (g) → 4 S2Cl2 (l) 5.0 mol Cl2 reacts with 2.0 mol S8, how many grams of S2Cl2 form? Which reactant is the limiting reagent? You must compare Cl2 to S8: 5.0 mol Cl2 × 1

  4. When given the reaction: S8(l) + 4 Cl2 (g) → 4 S2Cl2 (l) 5.0 mol Cl2 reacts with 2.0 mol S8, how many grams of S2Cl2 form? Which reactant is the limiting reagent? You must compare Cl2 to S8: 5.0 mol Cl2 × 4 mol S2Cl2 1 4 mol Cl2

  5. When given the reaction: S8(l) + 4 Cl2 (g) → 4 S2Cl2 (l) 5.0 mol Cl2 reacts with 2.0 mol S8, how many grams of S2Cl2 form? Which reactant is the limiting reagent? You must compare Cl2 to S8: 5.0 mol Cl2 × 4 mol S2Cl2 × 135 g S2Cl2 1 4 mol Cl2 1 mol S2Cl2

  6. When given the reaction: S8(l) + 4 Cl2 (g) → 4 S2Cl2 (l) 5.0 mol Cl2 reacts with 2.0 mol S8, how many grams of S2Cl2 form? Which reactant is the limiting reagent? You must compare Cl2 to S8: 5.0 mol Cl2 × 4 mol S2Cl2 × 135 g S2Cl2 = 675 g S2Cl2 1 4 mol Cl2 1 mol S2Cl2 2.0 mol S8 × 4 mol S2Cl2 × 135 g S2Cl2 = 1080 g S2Cl2 1 1 mol S8 1 mol S2Cl2

  7. When given the reaction: S8(l) + 4 Cl2 (g) → 4 S2Cl2 (l) 100.0 g Cl2 reacts with 200 g S8, how many grams of S2Cl2 form? Which reactant is the limiting reagent? • Each group must create a complete solution and present part of the solution to the class. • You will be assigned one part of the solution half way through the class period. • Mr. Gouterman will decide who will write the solution and who will explain the answer.

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