1 / 14

Momentum

? – If a bowling ball and tennis ball were rolled down a bowling alley at the same speed, which would knock more pins down? Why?

latham
Télécharger la présentation

Momentum

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. ? – If a bowling ball and tennis ball were rolled down a bowling alley at the same speed, which would knock more pins down? Why? ? – What if two 8 lb bowling balls were rolled down the alley, but a 7 yr old rolled one ball while an adult rolled the other. Which one would knock know the most pins? Why?

  2. Momentum • Based upon mass and speed • Vector • Represented by the letter “p” • To calculate – p = mv • Units – kg*m/s

  3. Practice • An ostrich with a mass of 146 kg is running to the right with a velocity of 17 m/s What is the ostrich’s momentum? • A 21 kg child is riding a 5.9 kg bike with a velocity of 4.5 m/s to the northwest. What is the total momentum of the child and bike? • What velocity must a car with a mass of 1210 kg have in order to have a momentum of 56250 kg*m/s?

  4. An ostrich with a mass of 146 kg is running to the right with a velocity of 17 m/s What is the ostrich’s momentum? • P = mv • P = (146)(17) • P = 2482 kg*m/s, right

  5. A 21 kg child is riding a 5.9 kg bike with a velocity of 4.5 m/s to the northwest. What is the total momentum of the child and bike? • P = mv • P = (21+5.9)(4.5) • P = 121.05 kg*m/s, northwest

  6. What velocity must a car with a mass of 1210 kg have in order to have a momentum of 56250 kg*m/s? • P = mv • 56250 = 1210(v) • V = 46.48 m/s, in the direction the car is moving

  7. ? – What do you have to do in order to change the momentum of an object? ? – Does an objects motion change instantly? The change in momentum occurs when a force is applied over a certain amount of time = IMPULSE p = Ft mv = Ft

  8. Practice • A 0.50 kg football is thrown with a velocity of 15 m/s to the right. A stationary receiver catches the ball and brings it to rest in 0.020 s. What is the force exerted on the receiver? • An 82 kg man drops from rest on a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching the water. What force does the water exert on him? • A 0.40 kg soccer ball approaches a player horizontally with a velocity of 18 m/s to the north. The player strikes the ball and causes it to move in the opposite direction with a velocity of 22 m/s. What impulse was delivered to the ball by the player? • A 2250 kg car traveling to the west slows down uniformly from 20.0 m/s to 5.0 m/s. How long does it take the car to decelerate if the force on the car is 8450 N to the east? How far does the car travel during the deceleration?

  9. A 0.50 kg football is thrown with a velocity of 15 m/s to the right. A stationary receiver catches the ball and brings it to rest in 0.020 s. What is the force exerted on the receiver? • mv = Ft • 0.50 (0-15) = F (0.20) • -37.5 N (left)

  10. An 82 kg man drops from rest on a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching the water. What force does the water exert on him? • mv = Ft vf2 = vi2 + 2ax • 82(7.67-0) = F(.55) vf2 = 0 + 2(9.8)(3) • F = 1143.2 N upvf = 7.67 m/s

  11. A 0.40 kg soccer ball approaches a player horizontally with a velocity of 18 m/s to the north. The player strikes the ball and causes it to move in the opposite direction with a velocity of 22 m/s. What impulse was delivered to the ball by the player? • mv = Ft • 0.4(-22-18) = Ft • -16 kg*m/s

  12. A 2250 kg car traveling to the west slows down uniformly from 20.0 m/s to 5.0 m/s. How long does it take the car to decelerate if the force on the car is 8450 N to the east? How far does the car travel during the deceleration? • mv = Ft • 2250(-5-(-20)) = 8450(t) • t = 3.99 s

  13. Collisions Elastic vs. Inelastic Object hit and bounce off each other Objects hit and stick together • Total mass after collision is • the combination of the • two objects • Kinetic Energy is not conserved • Velocities are the same • Masses stay separate • Kinetic energy is conversed • Velocities are different Law of Conservation of Momentum The momentum before a collision and after a collision is the same

  14. Examples • A 1850 kg luxury sedan stopped at a traffic light is struck from the rear by a compact car with a mass of 975 kg. The two cars become entangled as a result of the collision. If the compact car was moving at a velocity of 22.0 m/s to the north before the collision, what is the velocity of the entangled mass after the collision? • A 0.015 kg marble moving to the right at 0.225 m/s makes an elastic head on collision with a 0.030 kg shooter marble moving to the left at 0.180 m/s. After the collision, the smaller marble moves to the left at 0.315 m/s. Assume that neither marble rotates before or after the collision and that both marbles are moving on a frictionless surface. What is the velocity of the 0.030 kg marble after the collision?

More Related