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The Work-Energy Theorem and Kinetic Energy

The Work-Energy Theorem and Kinetic Energy. 6.2. Work-Energy Theorem. Do work means  W = Fs F = ma So work gives an object some acceleration Acceleration means the velocity changes. Derivation of Work-Energy Th. F = ma Fs = mas v f 2 = v 0 2 + 2 as  solve for as

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The Work-Energy Theorem and Kinetic Energy

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  1. The Work-Energy Theorem and Kinetic Energy 6.2

  2. Work-Energy Theorem • Do work means  W = Fs • F = ma • So work gives an object some acceleration • Acceleration means the velocity changes

  3. Derivation of Work-Energy Th. • F = ma • Fs = mas • vf2 = v02 + 2as solve for as • as = ½ (vf2 – v02) • Fs = m ½ (vf2 – v02) • W = ½ mvf2 – ½ mv02

  4. Kinetic Energy • Energy due to motion • If something in motion hits an object, it will move a some distance • KE = ½ mv2 • Scalar • Unit is joule (J)

  5. Work-Energy Theorem • Net external force = change in kinetic energy

  6. Example 1 • A 0.075-kg arrow is fired horizontally. The bowstring exerts an average force of 65 N on the arrow over a distance of 0.90 m. With what speed does the arrow leave the bow? • 39.5 m/s

  7. Example 2 • A foolish skier, starting from rest, coasts down a mountain that makes an angle of 30° with the horizontal. The coefficient of kinetic friction between her skis and the snow is 0.100. She coasts for a distance of 20 m before coming to the edge of a cliff and lands downhill at a point whose vertical distance is 5 m below the edge. How fast is she going just before she lands? • 10.52 m/s

  8. Practice Work • Do some work on these. • 173 CQ 4 – 8, P 12, 13, 15, 17, 18, 20, 23 • Total of 13 problems

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