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In this stoichiometry problem, we explore the mass of Cadmium Sulfide (CdS) produced when 8.47 g of Cadmium (Cd) reacts with 2.51 g of Sulfur (S). The first step in solving the problem is to convert the mass of each reactant into moles. The balanced chemical reaction needs to be established, and the coefficients and molar masses of the reactants will guide the calculations. We'll identify the limiting reactant and ultimately calculate the expected mass of CdS produced from the given reactants.
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Problem What mass of CdS is produced if 8.47g of cadmium reactswith 2.51g of sulfur ? Cd + S CdS Next!!
What’s The First Step To Solving This Problem ? . Figure Out The Grams For Cd Convert The Grams Into Moles. Make Sure The Problem Is Balanced. Back !!
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The Next Step Is Changing 8.47g of Cd Into Moles. How Would You Do That ? . 112.41gCd * 8.47gCd * Back To Problem !!
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The Next Step Is: Where Did The 1’s Come From ? The Mass The Charges The coefficients Back To The Problem !!
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The Mass of CdS (144.47)would go over ?? . 1molCdS 1molCd 112.41gCd Back To Problem !!
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Do The Calculations !! • 8.47gCd * * * is equal to ?? 10.89gCd 10.89molCd 10.89gCdS Back To Problem !!
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Now, Change 2.51gS into grams of CdS. . 2.51gS * * * = 11.31gS 2.51gS * * * = 11.31gCd 2.51gS * * * = 11.31gCdS
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8.47gCd is 10.89gCdS. 2.51gS is 11.31gCdS. Which one is the limiting reactant ? • . Cd S
Your Finished !! • Good Job !!
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