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Recurrence Relations next number depends on the previous number

Limit L is equal to. Given three values in a sequence e.g. U 10 , U 11 , U 12 we can work out recurrence relation. U 11 = a U 10 + b. U 12 = a U 11 + b. Use Sim . Equations. b. L =. a = sets limit b = moves limit U n = no effect on limit. (1 - a ).

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Recurrence Relations next number depends on the previous number

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  1. Limit Lis equal to Given three values in a sequence e.g. U10 ,U11 , U12 we can work out recurrence relation U11 = aU10 + b U12 = aU11 + b Use Sim. Equations b L= a= sets limit b= moves limit Un = no effect on limit (1 - a) Recurrence Relations next number depends on the previous number Un+1 = aUn + b |a| > 1 |a| < 1 a > 1 then growth a < 1 then decay Limit exists when |a| < 1 + b = increase - b = decrease

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