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Announcements :

Announcements : Midterm exam coming up Wednesday Feb. 16 , (two evening times, 5-6 pm or 6-7 pm). Material: Chapter 1-5 . Key equations will be provided on the last page of the exam. Bring a calculator to the test ( non-programmable ).

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Announcements :

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  1. Announcements: • Midterm exam coming up Wednesday Feb. 16, (two evening times, 5-6 pm or 6-7 pm). • Material: Chapter 1-5. • Key equations will be provided on the last page of the exam. • Bring a calculator to the test (non-programmable). • I will put up a practice exam on our class web page (http://www.wfu.edu/~gutholdm/Physics113/phy113.html)

  2. Chapter 6: Circular Motion • Reading assignment: Chapter 4.4, 4.5, 6.1, 6.2 (skip 6.3, 6.4, 6.5) • Homework : Ch. 4: OQ1, OQ7, 27, 30, 32 • Ch.6: 1, 6, 8, 9, 57 • Due dates: Tu/Th section: Monday, Feb. 21 • MWF section: Monday, Feb. 21 • Remember: Homework 5 is due Monday, Feb. 14 (section A & B) • In this chapter we will learn about the forces acting on particles when they move on a circular trajectory.

  3. Quick quizz Name all objects that experience a net acceleration • Space ship at constant velocity • A braking car • Particle going straight at constant speed • Hammer of a hammer thrower (see picture) • B & D

  4. Uniform Circular Motion  Motion in a circular path at constant speed. • Velocity is changing, thus there is an acceleration!! • Velocity is tangent to the path of the object • Acceleration is perpendicular to velocity • Centripetal acceleration is towards the center of the circle • Magnitude of acceleration is • r is radius of circle

  5. Thus far we have applied Newton’s law, F = m*a to linear motion. Now we’ll apply it to rotational motion

  6. Particle moving with uniform speed v in a circular path with radius r has an acceleration ar: (Derivation: see Chapter 4.4) • The acceleration points towards the center of the circle! • Centripetal acceleration

  7. Newton’s law along the radial direction (along r):

  8. Uniform Circular motion: • The velocity of the particle is along the __________ • The centripetal acceleration is towards the __________ • The centripetal force acting on the particle is towards the ________ • Centripetal force causes a change in the ________________ but no change in ________________. The magnitude of the centripetal acceleration is: a =______________ Newton’s law: The force on the particle is (centripetal force) F= m·a = ______________

  9. A particle is moving in a circular path. If the force on the particle would suddenly vanish (string cut) in which direction would the ball fly off?

  10. Black board example 6.1 Jeff Gordon leads his race and must drive into a curve at top speed to win it all. The radius of the curve is 1000.0 m and the coefficient of static friction between his tires and the pavement is 0.500. Find the maximum speed he can have and still make the turn.

  11. Black board example 6.2 An amusement park ride consists of a rotating circular platform 8.00 m in diameter from which 10.0 kg seats are suspended from 2.5 m chains. When the system rotates, the chains make an angle of 28° with the vertical. • Draw a free body diagram of a 40.0 kg child riding in a seat and find the tension in the chain. • What is the speed of each seat?

  12. Non-uniform circular motion, tangential and radial acceleration • Now: consider particles which move on a circular path with changing speed (speeding up or slowing down). • Total acceleration has a tangential and radial component: • Tangential component causes a change in speed • Radial component causes a change in the direction of the velocity

  13. Non-uniform circular motion, tangential and radial acceleration Previous slide: acceleration has a radial and tangential component  Force has a corresponding radial and tangential component. The bead speeds up with constant tangential acceleration, as it moves right. Draw the vectors representing the force on the bead at points A, B, C.

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