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Construction of Triangles and Their Properties

This project presents the construction of triangles, focusing on the properties of scalene triangles and the method for constructing triangles when two sides and the included angle (SAS) are given. We demonstrate the construction of triangle PQR with sides PR = 5 cm, PQ = 3 cm, and an included angle P = 70°. A step-by-step guide includes drawing line segments, using a protractor to measure angles, and ultimately forming the required triangle. Additionally, the construction techniques for triangles based on given angles and included sides are explored.

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Construction of Triangles and Their Properties

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  1. . WELCOME THE TO MATHS PROJECT

  2. . CONSTRUCTION OF TRIANGLES AND ITS PROPERTIES

  3. SUBMITED BY SUBMITED BYS ASWATHY.P ASWATHY.S INDHUBALA.B.A SARASWATHY.U S.T.D: 10.A GOVT.GRILS.HIGH.SCHOOL CHALAI

  4. If the length of the sides of a triangle are different ,it is called scalene triangle.

  5. Construction of a triangle when two of its sides and the included angle are given(SAS Triangle Construction)

  6. The lengths of two sides of a triangle PQR where PR =5 cm,PQ=3 cm and the included angle P=700

  7. To construct a triangle with two given sides and the includedangle. We first draw a rough sketchof PQR and indicate the lengths of its sides and the measure of the included angle. P 0 3CM 70 5CM R Q

  8. Step:1 Draw a line segment PR of length 5 cm P R . . 5CM

  9. STEP:3 From the ray PY, cut off line segment PQ of length 3cm. Y y Q Q . 0 0 70 70 R P P R 3CM 5CM

  10. Step:2 At P, draw an angle YPR of measure 700 using a protractor Y 0 70 P R

  11. Join QR.Thus , PQR is the required triangle. step:4

  12. The measures of to angles of a triangle, A=500, B=700and the included side AB=4cm.

  13. To construct a triangle with two given angles and the includedside. To construct a triangle with two given angles and the includedside. A 0 50 4CM o 70 B C

  14. STEP:1 Draw a line segment AB of length 4cm A B 4cm

  15. At A, draw XAB =500 using a protractor00 STEP:2 X 50 A B 4CM

  16. STEP: 3 .At B, draw YBA=700 using a protractor 4CM Y X . . Y . . X 0 0 0 0 50 50 70 70 A A B B 4CM 4CM

  17. . Let AX and BY intersect at C Thus, ABC is the required triangle.

  18. . GUIDED BY: Smt G.KUMARI SREEDEVI :

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