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Fizzies were popular in the ‘60s & ‘70s They were “instant fizz” tablets sold by the Emerson Drug Company in the US who also made “ B romo Seltzer ” headache remedy.
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Fizzies were popular in the ‘60s & ‘70s They were “instant fizz” tablets sold by the Emerson Drug Company in the US who also made “Bromo Seltzer” headache remedy. They work by the reaction of an acid and a base. Today we’re going to try making some but for the best taste, you have to get the ratio just right! H3C6H5O7 + 3NaHCO3 Na3C6H5O7 + 3H2O + 3CO2 citric acid + sodium hydrogen carbonate sodium citrate + water + carbon dioxide H3C6H5O7 + NaHCO3 Na3C6H5O7 + H2O + CO2 citric acid + sodium hydrogen carbonate sodium citrate + water + carbon dioxide 192 g/mol 84 g/mol Click to reveal balance the equation calculate the formula mass of each of the two reactants
H3C6H5O7 + 3NaHCO3 Na3C6H5O7 + 3H2O + 3CO2 citric acid + sodium hydrogen carbonate sodium citrate + water + carbon dioxide First we will make the drink without considering the “stoichiometry” • In a plastic disposable cup measure out … • ½ a centimetre of juice concentrate • a level table spoon of icing sugar • up to1g of NaHCO3 • half a cup of water • dissolve everything • measure out in a separate cake case up to 1g of citric acid then add to your drink, stir + taste is your drink too sour? too chalky? .. or just right? The only way to get it right every time is to add the chemicals in the right ratio
H3C6H5O7 + 3NaHCO3 Na3C6H5O7 + 3H2O + 3CO2 citric acid + sodium hydrogen carbonate sodium citrate + water + carbon dioxide 192 g/mol 84 g/mol Let’s work out the ideal ratio for the acid and base to mix in so neither is left over … • We’ll add 0.5g of NaHCO3. How many moles do you have in 0.5g? • How many moles of citric acid will react with one mole of NaHCO3? (look at the ratio in the chemical equation) • So how many moles of citric acid will you need to add? • Calculate the mass of citric acid to add … 0.5/84 = 0.00595 moles Check your answer with me before making up your second fizzy drink mix to see if it is any tastier 1/3rd of a mole 0.00595/3 = 0.00198 moles 0.00198 moles x 192 g/mol = 0.38g