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Probleme

Probleme. Problema 1:. Un segment [MN] cu lungimea de 39 cm se imparte in parti proportionale cu segmente date de 3 cm, 4cm, 6cm. Sa se afle partile. Rezolvare: {x,y,z} d.p. {3,4,6} x + y + z = 39 cm x y z x+y+z x+y+z 39 3 4 6 3+4+6 13 13.

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Probleme

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  1. Probleme

  2. Problema 1: • Un segment [MN] cu lungimea de 39 cm se imparte in parti proportionale cu segmente date de 3 cm, 4cm, 6cm. Sa se afle partile. • Rezolvare: {x,y,z} d.p. {3,4,6} x + y + z = 39 cm x y z x+y+z x+y+z 39 3 4 6 3+4+6 13 13 3 x 3 y 4 X=9 cm 3 3 z 6 3 Z=18 cm y=12 cm

  3. Problema 2: • În figura de mai jos segmentul (AB) a fost împarţit în 10 segmente congruente. , Punctele M, N, P, Q, R sunt aşezate astfel: • A M N P Q R B • Calculaţi rapoartele: AM , AM , AN • AN AP AQ • AM 2 AM 2 AN 4 • AN 4 AP 5 AQ 5

  4. Problema 3: Un segment [AB] cu lungimea de 240 mm se împarte in parţi proporâionale cu segmente de lungime:16 mm, 32 mm, 72 mm. Aflaţi lungimile părţilor: {x, y, z} d.p {16, 32, 72 } x + y + z 240 x y z x + y + z x +y +z 240 16 32 72 16 + 32 + 72 120 120 2 x z 16 2 x 32 mm 72 2 z 144 mm y 32 2 y 64 mm

  5. Problema 4: • Punctul M aparţine de (AB) astfel încât AM • MB 3 .Aflaţi AM şi MB, ştiin da AB 8. AM 3 AM+MB AB MB 1 AM 3xMB MBx4 8 MB 8:4 2 cm AM 3xMB 3x2 6 cm

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