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Heights and Distance Problems with Special Right Triangles

Explore problems involving heights of objects and distances using special right triangles 450 s2, 300 s3, and their applications in sports scenarios. Calculate distances in feet and seconds accurately.

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Heights and Distance Problems with Special Right Triangles

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  1. • Week12 day 1 The graph shows the height of a tennis ball from the time it is served to the time it hits the ground on the other side of the net. How many seconds elapse while the ball is 7 feet or more above the ground? 8 6 height (ft) 4 2 0 .2 .4 .6 .8 1.0 1.2 1.4 1.6 1.8 time (s) Record your answer and be sure to use the correct place value. 2

  2. 8.2 Special Right Triangles

  3. 450 s2 s 450 s 450-450-900 Triangle Theorem  In a 450-450-900 triangle, both legs are congruent and the length of the hypotenuse is 2 times the length of a leg. hypotenuse =2leg Pardekooper

  4. Lets try a problem 450 h 450 9 h=92 h=12.72 Pardekooper

  5. Lets try one more 450 22 h 450 h=222 h=4 Pardekooper

  6. Here’s one for baseball. A high school baseball diamond is a square. The distance from base to base is 90 ft. To the nearest foot, how far does the catcher throw the ball from home plate to second base ? 90 ft. x=902 x ft. x=126.9 x=127 Pardekooper

  7. 600 2s s 300 s3 300-600-900 Triangle Theorem In a 300-600-900 triangle, the length of the hypotenuse is twice the length of the shorter leg. The length of the longer leg is 3 times the length of the shorter leg.. hypotenuse =2shorter leg longer leg= 3shorter leg Pardekooper

  8. Lets try a problem 600 h 5 300 l h=2s l=s3 h=2(5) l=53 h=10 l=8.65 Pardekooper

  9. Here’s another 600 8 s 300 l l=s3 h=2s 8=2s l=43 2 2 l=6.92 4=s Pardekooper

  10. Just one more a 72 c 450 300 d b a=14 c=7 d=7 b=12.11 h=2s h=s2 h=2(7) h=72 h=14 s=7 l=s3 l=73 Pardekooper l=12.11

  11. Workbook P. 399 Pardekooper

  12. Assignment Workbook Page 399 all

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